Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Explain why it is easier for a nucleus to capture a neutron than for a nucleus to capture a proton.

Short Answer

Expert verified
Neutrons are easier to capture because they are neutral and don't face electrostatic repulsion like protons.

Step by step solution

01

Understanding the Charges

A nucleus captures other particles more effectively when there is minimal electrostatic repulsion. Neutrons are neutral particles and do not experience electrostatic repulsion when approaching a nucleus. On the other hand, protons are positively charged, just like the nucleus, leading to strong electrostatic repulsion between the approaching proton and the nucleus.
02

Nuclear Forces Involved

Both neutrons and protons are affected by the strong nuclear force when they are very close to the nucleus. The strong nuclear force is responsible for binding protons and neutrons in the nucleus, and it acts over very short ranges. Since the neutron does not face electrostatic repulsion, it can get closer to the nucleus and be more effectively captured by the strong nuclear force.
03

Potential Energy Consideration

When a charged particle like a proton approaches a nucleus, it must overcome the repulsive potential energy barrier due to electrostatic forces. Neutrons do not have this barrier to overcome since they are neutral particles, making it energetically easier for them to be captured by the nucleus.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Neutron Capture
Neutron capture is a fundamental process in nuclear chemistry that occurs when a nucleus absorbs a neutron. Due to its neutral charge, a neutron can effortlessly approach a nucleus without facing electrostatic repulsion. This makes it easier for the neutron to get close enough to be influenced by the strong nuclear force, which is crucial for capturing it by the nucleus. This process is pivotal in many natural and artificial nuclear reactions, such as those occurring in nuclear reactors and certain types of radioactive decay.
  • Neutrons have no charge and do not experience repulsion from the nucleus.
  • Neutron capture can lead to a more massive nucleus, sometimes making it unstable and causing radioactive decay.
  • This process is essential for elements heavier than iron, which cannot be formed by fusion.
Electrostatic Repulsion
Electrostatic repulsion is a force that occurs between charged particles. In the context of a nucleus capturing particles, protons, which are positively charged, experience significant electrostatic repulsion as they approach the positively charged nucleus. This repulsion acts as a barrier, making it difficult for protons to get close to the nucleus. In contrast, neutron capture does not involve overcoming such repulsion, as neutrons are neutrally charged.
  • Occurs between like-charged particles.
  • Makes it challenging for protons to be captured by a nucleus.
  • Does not affect neutrons, allowing easy capture by the nucleus.
Strong Nuclear Force
The strong nuclear force is one of the four fundamental forces in nature. It is responsible for holding protons and neutrons together in the nucleus. Despite its short range, it is incredibly powerful and works effectively when particles are very close. In neutron capture, this force overcomes the differences in charge and allows particles to bind together.
  • Operates over very short distances, typically the size of an atomic nucleus.
  • Overrides electrostatic repulsion at close range, allowing nucleons to bind.
  • Plays a key role in stabilizing the nucleus and enabling neutron capture.
Potential Energy Barrier
The potential energy barrier refers to the energy hurdle that must be overcome for two particles to interact. For a charged particle like a proton, this energy barrier is primarily due to electrostatic repulsion from the nucleus. Neutrons, having no charge, don't face this barrier. As a result, they can be more easily incorporated into the nucleus during a reaction, making neutron capture more favorable compared to proton capture.
  • Primarily affects charged particles due to electrostatic forces.
  • Neutrons don't face energy barriers, simplifying their capture.
  • Understanding potential energy barriers helps predict reaction outcomes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Under proper conditions, fusion of a helium- 3 nucleus with a proton produces helium-4 plus a neutron. Write a balanced nuclear equation to represent this process.

What is the difference between nuclear fission and nuclear fusion? Illustrate your answer with an example of each.

In 1998 , researchers in Dubna, Russia, synthesized element 112 , copernicium, by reaction of uranium- 238 nuclei with calcium- 48 nuclei. The copernicium- 283 isotope was produced along with neutrons. Write a balanced nuclear equation to represent this synthesis.

Radioactive isotopes are often used as "tracers" to follow an atom through a chemical reaction. Acetic acid reacts with methanol, \(\mathrm{CH}_{3} \mathrm{OH}\), by eliminating a molecule of \(\mathrm{H}_{2} \mathrm{O}\) to form methyl acetate, \(\mathrm{CH}_{3} \mathrm{COOCH}_{3}\). Explain how you would use the radioactive isotope \({ }^{18} \mathrm{O}\) to show whether the oxygen atom in the water product comes from the \(-\mathrm{OH}\) of the acid or the \(-\mathrm{OH}\) of the alcohol. $$ \begin{aligned} &\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{CH}_{3} \mathrm{OH} \longrightarrow \mathrm{CH}_{3} \mathrm{COOCH}_{3}+\mathrm{H}_{2} \mathrm{O}\\\ &\begin{array}{lll} \text { acetic acid } & \text { methanol } & \text { methyl acetate } \end{array} \end{aligned} $$

Iodine- 131 is used in the form of sodium iodide to treat cancer of the thyroid. (a) The isotope decays by ejecting a \(\beta\) particle. Write a balanced equation to show this process. (b) The isotope has a half-life of 8.04 days. If you begin with \(25.0 \mathrm{mg}\) of radioactive \(\mathrm{Na}^{131} \mathrm{I},\) calculate the mass (mg) that remains after 32.2 days.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free