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Four metals \(\mathrm{A}, \mathrm{B}, \mathrm{C},\) and \(\mathrm{D}\) exhibit these properties: (a) Only \(\mathrm{A}\) and \(\mathrm{C}\) react with \(1.0-\mathrm{M} \mathrm{HCl}\) to give \(\mathrm{H}_{2}\) gas. (b) When \(\mathrm{C}\) is added to solutions of ions of the other metals, metallic \(\mathrm{A}, \mathrm{B},\) and \(\mathrm{D}\) are formed. (c) Metal D reduces \(\mathrm{B}^{n+}\) ions to give metallic \(\mathrm{B}\) and \(\mathrm{D}^{n+}\) ions. On the basis of this information, arrange the four metals in order of increasing ability to act as reducing agents.

Short Answer

Expert verified
The order is B, D, A, C from least to most reducing ability.

Step by step solution

01

Understand Reactivity with HCl

The metals A and C react with 1.0-M HCl to produce H2 gas, indicating they are more reactive metals capable of displacing hydrogen ions from HCl. B and D do not react with HCl.
02

Analyze Metal Reduction of Ions

When C is added to solutions containing ions of A, B, or D, the metallic form of A, B, and D are formed. This indicates that C can reduce these ions, making C a strong reducing agent compared to A, B, and D.
03

Understand Reducing Power from D

Metal D reduces B^n+ ions to produce metallic B and D^n+ ions. This shows that D is a stronger reducing agent than B, as it donates electrons to B^n+ to form metallic B.
04

Infer Order of Reducing Ability

Combining the above information, the order of reducing ability (from least to most) is B, D, A, C. B is the least effective because it is reduced by D, while A and C's reactivity with HCl and C's ability to reduce all other metals indicate they are stronger reducing agents.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reactivity with Hydrochloric Acid
When metals are introduced to hydrochloric acid ( HCl ), a fascinating chemical interaction can occur. Metals like A and C , which react with 1.0-M HCl to release H_2 gas, exhibit a higher reactivity. This means that these metals have the ability to displace hydrogen ions ( H^+ ) from the acid, resulting in the formation of hydrogen gas. This reaction can be represented as follows:
  • Metal + 2HCl -> Metal chloride + H_2 gas
If a metal can achieve this, it suggests that the metal is more active in terms of chemical reactions. In our exercise, metals B and D do not release H_2 gas upon interacting with HCl , indicating lower reactivity, unlike A and C that actively participate in this reaction. This characteristic becomes a foundational element determining the reactivity series within the chemical world.
Metal Reduction
The concept of metal reduction involves one metal causing another metal to return to its metallic state by donating electrons. When metal C is added to solutions containing ions of A , B , or D , the metallic forms of these metals ( A , B , and D ) are reformed. This process highlights the capability of C as a powerful reducing agent. When metal C intervenes, it supplies electrons to the metallic ions present in the solution, allowing them to regain their neutral metallic form.
  • C + Metal ions -> Cation + Metal
For instance: - The fact that metal C can reduce ions of A , B , and D to their metals illustrates its significant electron-donating ability. - This process vividly demonstrates the relative strength of reducing agents in chemistry.
Order of Reducing Agents
The order of reducing agents is determined based on their ability to cause reduction (i.e., donation of electrons to other substances). In our exercise: - Metal C , being able to reduce the ions of A , B , and D to their metallic forms, signifies that it's the strongest reducing agent. - Metal D , capable of reducing B^{n+} ions to metallic B , is stronger than B , though not as potent as C. It ranks higher than B due to its ability to donate electrons more effectively. Through these observations, we craft an order for these metals based on their reducing power:
  • B < D < A < C
This hierarchy gives an understanding of their reducing ability, with B being the least effective reducing agent as shown in its inability to reduce D to metallic form. This guidance aids in predictions about the behavior of metals during redox reactions.
Redox Reactions
Redox reactions are the heart of many chemical processes, involving the transfer of electrons between substances. These reactions are essential in understanding the behavior of reducing agents and oxidizing agents. In such reactions: - The substance that loses electrons is undergoing oxidation and acts as a reducing agent. - The substance that gains electrons is reduced and is known as the oxidizing agent. In our scenario:
  • Metal C acts as a reducing agent by losing electrons to the ions of A , B , and D , thereby helping them regain their metallic forms.
  • Metal D reduces B^{n+} ions, indicating that it undergoes oxidation to donate electrons.
By examining redox reactions, we gain insights into the fundamental interactions between elements and compounds. These processes help in determining the power and order of reducing agents.

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Most popular questions from this chapter

A current of \(0.0125 \mathrm{~A}\) is passed through a solution of \(\mathrm{CuCl}_{2}\) for \(2.00 \mathrm{~h} .\) Calculate the mass of copper deposited at the cathode and the volume of \(\mathrm{Cl}_{2}\) gas (in \(\mathrm{mL}\) at STP) produced at the anode.

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