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Distinguish between the ion product \((Q)\) expression and the solubility product constant expression of a sparingly soluble solute.

Short Answer

Expert verified
Q is a variable product of ion concentrations; Ksp is a constant at equilibrium. Comparing Q to Ksp predicts solubility status.

Step by step solution

01

Define Ion Product (Q)

The ion product (Q) is a measure of the concentrations of the ions of a sparsely soluble salt in a solution at any given moment, expressed as the product of their molar concentrations, each raised to the power of their stoichiometric coefficients in the balanced chemical equation.
02

Define Solubility Product (Ksp)

The solubility product constant ( K_{sp} ) is a specific form of equilibrium constant applied to sparingly soluble compounds. It represents the maximum product of the ion concentrations (each raised to their respective powers according to the balanced dissolution equation) that can exist in a saturated solution at a given temperature.
03

Form the Q Expression

For a generic sparingly soluble salt AB that dissociates into A^+ and B^- in solution, the ion product Q is calculated as: Q = [A^+][B^-] . In cases where dissociation is more complex with stoichiometry other than 1:1, adjust the exponents: for A_mB_n , it would be Q = [A^+]^m[B^-]^n .
04

Form the Ksp Expression

Similarly, the solubility product constant for AB in a saturated solution is outlined as: K_{sp} = [A^+]_{eq}[B^-]_{eq} , where the concentrations are at equilibrium in a saturated solution. For a salt A_mB_n , K_{sp} = [A^+]_{eq}^m[B^-]_{eq}^n .
05

Compare Q and Ksp

The ion product Q and K_{sp} can be compared to predict the state of a solution. If Q < K_{sp} , the solution is unsaturated and more solute can dissolve. If Q = K_{sp} , the solution is saturated, at equilibrium. If Q > K_{sp} , the solution is supersaturated and precipitation may occur.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ion Product
Understanding the ion product \(Q\), is crucial when dealing with sparingly soluble compounds.
The ion product measures the concentrations of the individual ions in a solution that originates from the dissolution of a sparingly soluble salt.
Each concentration is raised to the power of its stoichiometric coefficient in the balanced chemical equation of the salt.
For example, if we have a salt \(AB\) that dissolves into one \([A^+]\) and one \([B^-]\), then the ion product is simply calculated as:
  • \(Q = [A^+][B^-]\)
However, if the salt has a different stoichiometry, such as \(A_mB_n\), the ion product equation adapts:
  • \(Q = [A^+]^m[B^-]^n\)
The concept of ion product is a snapshot of ion concentrations at any moment before the system reaches equilibrium. It's a dynamic way to describe the solution's current state.
By comparing this to the solubility product constant \(K_{sp}\), one can evaluate whether the solution is still capable of dissolving more solute, or if precipitation may occur.
Equilibrium Constant
The equilibrium constant \(K_{sp}\), known as the solubility product constant, is distinctly applicable to sparingly soluble compounds.
Unlike the ion product, \(K_{sp}\) is exclusively defined for a saturated solution at equilibrium, indicating the limited amount of solute that can dissolve at a specific temperature.
It is calculated similarly to the ion product, but the ion concentrations here are the maximum concentrations possible because the solution is at saturation.
For a simple salt \(AB\) at equilibrium, this constant can be represented as:
  • \(K_{sp} = [A^+]_{eq}[B^-]_{eq}\)
If the salt has a stoichiometry \(A_mB_n\), the \(K_{sp}\) expression becomes:
  • \(K_{sp} = [A^+]_{eq}^m[B^-]_{eq}^n\)
The value of \(K_{sp}\) provides a benchmark for comparing with the ion product. It helps predict the state of the solution:
  • If \(Q < K_{sp}\), the solution is unsaturated and more solute can be dissolved.
  • If \(Q = K_{sp}\), the solution is at equilibrium and cannot dissolve more solute.
  • If \(Q > K_{sp}\), the solution is supersaturated, and excess solute might precipitate out.
This constant helps chemists understand the solubility limits and processes happening within a solution.
Sparingly Soluble Compounds
Sparingly soluble compounds are those that dissolve in water to only a very limited extent.
This means only a small amount of these substances can dissolve to form a saturated solution.
They have characteristically low solubility product constants \(K_{sp}\).When these compounds dissolve in water, they reach a point of saturation where the rate of dissolution equals the rate of precipitation. This dynamic equilibrium is essential to understanding their behavior in solutions.
Examples include salts like calcium sulfate (\(CaSO_4\)) and silver chloride (\(AgCl\)). Understanding the delicate balance between the ion product and the solubility product constant is key:
  • It helps predict whether more of the compound can dissolve in solution.
  • It's useful in determining conditions under which a precipitate might form.
  • It aids in designing systems where controlled precipitation is necessary, such as water purification.
Chemists utilize the concepts of \(Q\) and \(K_{sp}\) in practical applications, exploiting the limiting solubility to drive desirable reactions and processes.

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