Balancing chemical equations is crucial for accurately representing the conservation of mass in chemical reactions. When writing a chemical equation, it's vital to ensure that the number of each type of atom on the reactants side equals the number on the products side. This is known as balancing the equation.
In the exercise involving sodium carbonate and stearic acid, we begin by listing the reactants and products: sodium carbonate and stearic acid as reactants, and sodium stearate, carbon dioxide, and water as products. Initially, the reaction equation might look incomplete or inaccurate in terms of atom counts.
- The next step is adjusting coefficients to balance atoms on both sides.
- For this reaction, it takes two stearic acid molecules to react with one sodium carbonate molecule.
- This produces two molecules of sodium stearate, along with one molecule each of carbon dioxide and water.
The final balanced equation is: \[ \mathrm{Na}_2\mathrm{CO}_3 + 2 \mathrm{C}_{17}\mathrm{H}_{35}\mathrm{COOH} \rightarrow 2 \mathrm{C}_{17}\mathrm{H}_{35}\mathrm{COONa} + \mathrm{CO}_2 + \mathrm{H}_2\mathrm{O} \] Ensuring each type of atom has equal numbers on both sides demonstrates understanding and precision in chemistry.