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Think of an experiment you could do to demonstrate that the equilibrium $$ 2 \mathrm{NO}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g}) $$ is a dynamic process in which the forward and reverse reactions continue to occur after equilibrium has been achieved. Describe how such an experiment might be carried out.

Short Answer

Expert verified
Observe color changes in \(\mathrm{NO}_2\) and \(\mathrm{N}_2\mathrm{O}_4\) when equilibrium conditions change and return, demonstrating ongoing reaction dynamics.

Step by step solution

01

Identify the Reactants and Products

In the equilibrium reaction \(2\mathrm{NO}_2(\mathrm{g}) \rightleftharpoons \mathrm{N}_2\mathrm{O}_4(\mathrm{g})\), the reactants are nitrogen dioxide (\(\mathrm{NO}_2\)) and the product is dinitrogen tetroxide (\(\mathrm{N}_2\mathrm{O}_4\)). Both are gases and can be observed for color changes.
02

Set Up the Experiment

Place a sample of \(\mathrm{NO}_2\) gas in a sealed, transparent container that allows you to observe the color of the gas mixture.
03

Observe Color Changes

\(\mathrm{NO}_2\) is brown, while \(\mathrm{N}_2\mathrm{O}_4\) is colorless. At equilibrium, a brownish color should appear, indicating the presence of both gases. The color intensity can provide qualitative insight into the concentrations of \(\mathrm{NO}_2\) and \(\mathrm{N}_2\mathrm{O}_4\).
04

Disturb the Equilibrium

Change the pressure or temperature of the container. For instance, decrease the temperature, which favors the formation of \(\mathrm{N}_2\mathrm{O}_4\) and should make the color lighter. Conversely, increasing the temperature should increase the concentration of \(\mathrm{NO}_2\), making the color darker.
05

Restore Conditions and Re-Observe

Return the container to its original temperature and pressure conditions. Over time, observe the return of the original equilibrium color. This shift and restoration confirm that both the forward and reverse reactions continue, even at equilibrium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dynamic Equilibrium
In a chemical reaction, equilibrium is reached when the forward and reverse reactions occur at the same rate. This does not mean the reactions stop; instead, they continue to occur simultaneously.
For the reaction between nitrogen dioxide (\(\text{NO}_2\)) and dinitrogen tetroxide (\(\text{N}_2\text{O}_4\)), even when it seems like nothing changes on a macroscopic level, the molecules are still actively interconverting.
If we consider a sealed container where this reaction takes place, the system illustrates dynamic equilibrium. Brown \(\text{NO}_2\) molecules keep turning into colorless \(\text{N}_2\text{O}_4\) and vice versa, but the total concentration of each gas remains constant.
This subtly hints at why we call it 'dynamic' - because it's an ever-moving, ongoing process even at stasis.
NO2 and N2O4 Equilibrium
The specific chemical equilibrium between nitrogen dioxide (\(\text{NO}_2\)) and dinitrogen tetroxide (\(\text{N}_2\text{O}_4\)) is a classic example illustrating the principles of equilibrium.
The reaction \(2 \text{NO}_2(\text{g}) \rightleftharpoons \text{N}_2\text{O}_4(\text{g})\) demonstrates how reactants and products coexist at given conditions.
\(\text{NO}_2\) is distinctive due to its noticeable brown color, while \(\text{N}_2\text{O}_4\) is colorless.
In a setup where equilibrium is achieved, a brownish hue indicates a mix of both gases. By manipulating factors like temperature, one can observe shifts in the equilibrium: cooler conditions favor the formation of \(\text{N}_2\text{O}_4\), while higher temperatures promote more \(\text{NO}_2\).
This hands-on experience helps in visualizing how equilibrium responds to external pressures, while maintaining its backward-forward nature.
Le Chatelier's Principle
Le Chatelier's Principle is a fundamental concept used to predict the effect of a change in conditions on a chemical equilibrium.
When an external change such as temperature or pressure influences a system at equilibrium, the system adjusts itself to counteract the change and restore a new equilibrium balance.
Applying this to the \(\text{NO}_2\) and \(\text{N}_2\text{O}_4\) system, lowering temperature results in the equilibrium position shifting to the right, forming more \(\text{N}_2\text{O}_4\) (lessening the brown color). On the other hand, increasing temperature shifts it to the left, producing more \(\text{NO}_2\) and intensifying the brown color.
Le Chatelier's Principle is vital in understanding how equilibrium adjusts and is an invaluable tool in chemistry for predicting reactions to changes.
Colorimetric Analysis in Chemistry
Colorimetric analysis involves assessing the color of a solution or gas to determine concentrations of certain substances. This method becomes a powerful tool when examining reactions like \(2 \text{NO}_2(\text{g}) \rightleftharpoons \text{N}_2\text{O}_4(\text{g})\), where color changes provide visible cues about the relative concentrations of \(\text{NO}_2\) and \(\text{N}_2\text{O}_4\).
The intensity of the color signals how much brown \(\text{NO}_2\) is present compared to colorless \(\text{N}_2\text{O}_4\).
This type of analysis is both qualitative, suggesting presence, and quantitative when correlated with standards for precise concentration measurements.
By carefully recording these changes, chemists can quantitatively analyze equilibrium positions and shifts, making it an essential technique in understanding dynamic equilibria.

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Most popular questions from this chapter

Write the equilibrium constant expression for each of these heterogeneous systems. (a) \(\mathrm{CaSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}(\mathrm{s}) \rightleftharpoons \mathrm{CaSO}_{4} \cdot 3 \mathrm{H}_{2} \mathrm{O}(\mathrm{s})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) (b) \(\mathrm{SiF}_{4}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{SiO}_{2}(\mathrm{~s})+4 \mathrm{HF}(\mathrm{g})\) (c) \(\mathrm{LaCl}_{3}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{LaClO}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{g})\)

At \(503 \mathrm{~K}\) the equilibrium constant \(K_{\mathrm{c}}\) for the dissociation of \(\mathrm{N}_{2} \mathrm{O}_{4}\) $$ \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_{2}(\mathrm{~g}) $$ has the value 40.0 . (a) Calculate the fraction of \(\mathrm{N}_{2} \mathrm{O}_{4}\) left undissociated when \(1.00 \mathrm{~mol}\) of this gas is heated to \(503 \mathrm{~K}\) in a \(10.0-\mathrm{L}\) sealed container. (b) If the volume is now reduced to \(2.0 \mathrm{~L},\) calculate the new fraction of \(\mathrm{N}_{2} \mathrm{O}_{4}\) that is undissociated. (c) Calculate all three equilibrium concentrations.

Consider the system $$ \begin{aligned} 4 \mathrm{NH}_{3}(\mathrm{~g})+3 \mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{~N}_{2}(\mathrm{~g})+6 \mathrm{H}_{2} \mathrm{O}(\ell) \\ \Delta_{\mathrm{r}} H^{\circ} &=-1530.4 \mathrm{~kJ} / \mathrm{mol} \end{aligned} $$ (a) How will the amount of ammonia at equilibrium be affected by (i) removing \(\mathrm{O}_{2}(\mathrm{~g})\) without changing the total gas volume? (ii) adding \(\mathrm{N}_{2}(\mathrm{~g})\) without changing the total gas volume? (iii) adding water without changing the total gas volume? (iv) expanding the container? (v) increasing the temperature? (b) Which of these changes (i to v) increases the value of \(K ?\) Which decreases it?

For each of these processes at \(25^{\circ} \mathrm{C}\), indicate whether the entropy effect, the energy effect, both, or neither favors the process. $$ \text { (a) } \begin{aligned} \mathrm{C}_{3} \mathrm{H}_{8}(\mathrm{~g})+5 \mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 3 \mathrm{CO}_{2}(\mathrm{~g})+4 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \\ \Delta_{t} H^{\circ}=&-2045 \mathrm{~kJ} / \mathrm{mol} \end{aligned} $$ (b) \(\mathrm{Br}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{Br}_{2}(\ell)\) $$ \Delta_{r} H^{\circ}=-31 \mathrm{~kJ} / \mathrm{mol} $$ $$ \text { (c) } 2 \mathrm{Ag}(\mathrm{s})+3 \mathrm{~N}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{AgN}_{3}(\mathrm{~s}) \quad \Delta_{\mathrm{r}} H^{\circ}=618 \mathrm{~kJ} / \mathrm{mol} $$

Phosphorus pentachloride decomposes at high temperatures. $$ \mathrm{PCl}_{5}(\mathrm{~g}) \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) $$ An equilibrium mixture at some temperature consists of \(3.120 \mathrm{~g} \mathrm{PCl}_{5}, 3.845 \mathrm{~g} \mathrm{PCl}_{3},\) and \(1.787 \mathrm{~g} \mathrm{Cl}_{2}\) in a sealed 1.00-L flask. (a) If you add \(1.418 \mathrm{~g} \mathrm{Cl}_{2}\) without changing the volume, how will the equilibrium be affected? (b) Calculate the concentrations of all three substances when equilibrium is reestablished.

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