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Heating a metal carbonate leads to decomposition. $$ \mathrm{BaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{BaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}) $$ Predict the effect on the equilibrium of each change listed below. Answer by choosing (i) no change, (ii) shifts left, or (iii) shifts right. (Except for part (e), assume that the volume is constant.) (a) Add \(\mathrm{BaCO}_{3}\) (b) Add \(\mathrm{CO}_{2}\) (c) Add \(\mathrm{BaO}\) (d) Raise the temperature (e) Increase the volume of the reaction flask

Short Answer

Expert verified
(a) No change; (b) Shifts left; (c) No change; (d) Shifts right; (e) Shifts right.

Step by step solution

01

Understanding Equilibrium

A chemical equilibrium is reached when the rate of the forward reaction equals the rate of the reverse reaction. In this dynamic state, the concentrations of reactants and products remain constant.
02

Le Chatelier's Principle

Le Chatelier's Principle states that if a system at equilibrium is subjected to a change in concentration, temperature, volume, or pressure, the system will adjust itself to partially counteract the effect of the change and reach a new equilibrium.
03

Analyze Effect of Adding BaCO3

Adding more solid \(\mathrm{BaCO}_{3}\) does not affect the position of the equilibrium because solids do not change ion concentrations in solution. Thus, the equilibrium position shows 'no change'.
04

Analyze Effect of Adding CO2

Adding more \(\mathrm{CO}_{2}\) increases the concentration of the product, which will shift the equilibrium to the left to reestablish equilibrium according to Le Chatelier's Principle.
05

Analyze Effect of Adding BaO

Adding more solid \(\mathrm{BaO}\) also does not affect the equilibrium position as solids are not part of the equilibrium expression in this context. Therefore, it results in 'no change'.
06

Analyze Effect of Increasing Temperature

Since the decomposition of \(\mathrm{BaCO}_{3}\) is an endothermic process, increasing the temperature shifts the equilibrium to favor the formation of products. Thus, the equilibrium shifts to the right.
07

Analyze Effect of Increasing Volume

Increasing the volume of the flask decreases the pressure, thus favoring the side with more moles of gas, i.e., the formation of \(\mathrm{CO}_{2}\). Consequently, the equilibrium shifts to the right.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Le Chatelier's Principle
Le Chatelier's Principle is a fundamental idea that helps us understand how an equilibrium system responds to changes. Imagine a playground see-saw that's perfectly balanced. If you push on one side, the see-saw tilts to regain balance. Similarly, Le Chatelier's Principle states that if a disturbance is applied to a system at equilibrium, the system will adjust to counteract that disturbance and reestablish equilibrium.

Some common disturbances include changes in concentrations of reactants or products, changes in temperature, and changes in volume or pressure. When we add or remove substances, adjust temperatures, or change volumes, we are essentially "pushing" the equilibrium one way or another. The system "shifts" in the direction needed to restore balance, either by producing more products, more reactants, or adjusting their ratios to minimize the change. It's a beautiful example of nature's tendency to find balance.
Effect of Temperature on Equilibrium
Temperature changes can significantly affect a chemical equilibrium. They alter the rates of both the forward and reverse reactions, depending on whether the reaction is exothermic or endothermic. An endothermic reaction absorbs heat, similar to how an ice pack absorbs warmth from your body. Conversely, an exothermic reaction releases heat, like a warm blanket.

When the temperature increases, Le Chatelier's Principle tells us that the equilibrium will shift in a direction that absorbs extra heat. If the reaction is endothermic, increasing temperature adds energy to the system, shifting the equilibrium toward the products, as seen with the decomposition of \(\mathrm{BaCO}_{3}\) to \(\mathrm{BaO}\) and \(\mathrm{CO}_{2}\). This is because the system "favors" the endothermic direction to absorb the added heat. Conversely, lowering the temperature would favor the exothermic direction, shifting the equilibrium to the reactants.
Effect of Volume on Equilibrium
Volume changes impact equilibria involving gases because they affect pressure within the system. According to Le Chatelier's Principle, if you increase the volume of the container, the pressure decreases. Gaseous equilibria shift to the direction that produces more gas molecules to counteract this change.

In our example involving \(\mathrm{CO}_{2}\), if the container's volume increases, the system tries to increase the pressure by producing more gas molecules. As a result, the equilibrium shifts toward the side with more gaseous moles—in this case, towards the products, \(\mathrm{BaO}\) and \(\mathrm{CO}_{2}\), because of the increase in volume or decrease in pressure.

This concept is essential in industrial chemistry, where controlling pressures and volumes is necessary to optimize the production of desired chemicals.

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Most popular questions from this chapter

Consider the equilibrium $$ \mathrm{N}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g}) $$ At \(2300 \mathrm{~K}\) the equilibrium constant \(K_{\mathrm{c}}=1.7 \times 10^{-3}\). If \(0.15 \mathrm{~mol} \mathrm{NO}(\mathrm{g})\) is placed into an empty, sealed \(10.0-\mathrm{L}\) flask and heated to \(2300 \mathrm{~K},\) calculate the equilibrium concentrations of all three substances at this temperature.

Imagine yourself to be the size of ions and molecules inside a beaker containing this equilibrium mixture with a \(K_{\mathrm{c}}\) greater than \(1 .\) $$ \mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}(\mathrm{aq})+4 \mathrm{Cl}^{-}(\mathrm{aq}) \rightleftharpoons \mathrm{CoCl}_{4}^{2-}(\mathrm{aq})+6 \mathrm{H}_{2} \mathrm{O}(\ell)$$ pink blue Write a brief description of what you observe around you before and after additional water is added to the mixture.

Decomposition of ammonium dichromate is shown in the designated series of photos. In a closed container this process reaches an equilibrium state. Write a balanced chemical equation for the equilibrium reaction. How is the equilibrium affected if (a) more ammonium dichromate is added to the equilibrium system? (b) more water vapor is added? (c) more chromium(III) oxide is added?

Write the expression for \(K_{\mathrm{c}}\) for each reaction. (a) \(\mathrm{PCl}_{5}(\mathrm{~s}) \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g})\) (b) \(\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}(\mathrm{aq})+4 \mathrm{Cl}^{-}(\mathrm{aq}) \rightleftharpoons\) \(\mathrm{CoCl}_{4}^{2-}(\mathrm{aq})+6 \mathrm{H}_{2} \mathrm{O}(\ell)\) (c) \(\mathrm{CH}_{3} \mathrm{COOH}(\mathrm{aq}) \rightleftharpoons \mathrm{CH}_{3} \mathrm{COO}^{-}(\mathrm{aq})+\mathrm{H}^{+}(\mathrm{aq})\) (d) \(2 \mathrm{~F}_{2}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{OF}_{2}(\mathrm{~g})+2 \mathrm{HF}(\mathrm{g})\)

Mustard gas was used in chemical warfare in World War I. Mustard gas can be produced according to this reaction: $$ \mathrm{SCl}_{2}(\mathrm{~g})+2 \mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{~g}) \rightleftharpoons \mathrm{S}\left(\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Cl}\right)_{2}(\mathrm{~g}) $$ An evacuated 5.00 -L flask at \(20.0^{\circ} \mathrm{C}\) is filled with \(0.258 \mathrm{~mol} \mathrm{SCl}_{2}\) and \(0.592 \mathrm{~mol} \mathrm{C}_{2} \mathrm{H}_{4}\) and sealed. After equilibrium is established, 0.0349 mol mustard gas is present. (a) Calculate the partial pressure of each gas at equilibrium. (b) Calculate \(K_{\mathrm{c}}\) at \(20.0^{\circ} \mathrm{C}\).

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