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You and your lab partner are each given metal cubes that look similar. Your assignment is to make length and mass measurements and use only these data to determine whether the metal is the same in each cube. Your cube is \(1.32 \mathrm{~cm}\) on each edge and has a mass of \(16.23 \mathrm{~g}\). Your partner's cube has a mass of \(24.64 \mathrm{~g}\) and each edge measures \(1.46 \mathrm{~cm}\). Your partner says that the metal is the same in each cube; you don't agree. Refute your partner's conclusion.

Short Answer

Expert verified
The cubes are made of different metals; their densities are different: 7.06 g/cm³ vs. 7.92 g/cm³.

Step by step solution

01

Calculate Volume of Your Cube

The formula for the volume of a cube is \( V = ext{side}^3 \). For your cube, each side is \( 1.32 \text{ cm} \). Therefore, the volume is \( V = 1.32^3 \text{ cm}^3 \). Calculating this, \( V = 2.30 \text{ cm}^3 \).
02

Calculate Density of Your Cube

Density is given by the formula \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \). For your cube, the mass is \( 16.23 \text{ g} \), and the volume is \( 2.30 \text{ cm}^3 \). So, the density is \( \frac{16.23}{2.30} = 7.06 \text{ g/cm}^3 \).
03

Calculate Volume of Your Partner's Cube

Using the formula for the volume of a cube again, for your partner's cube with a side of \( 1.46 \text{ cm} \), the volume is \( 1.46^3 \text{ cm}^3 \). Calculating this, \( V = 3.11 \text{ cm}^3 \).
04

Calculate Density of Your Partner's Cube

Similarly, calculate the density of your partner's cube. The mass is \( 24.64 \text{ g} \) and the volume is \( 3.11 \text{ cm}^3 \). Thus, the density is \( \frac{24.64}{3.11} = 7.92 \text{ g/cm}^3 \).
05

Compare Densities

Your cube has a density of \( 7.06 \text{ g/cm}^3 \) and your partner's cube has a density of \( 7.92 \text{ g/cm}^3 \). Since the densities are different, the metal in each cube cannot be the same.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volume Calculation
Volume is a measure of the amount of space an object occupies. Calculating the volume of a cube is straightforward because all sides are equal in length. To compute the volume, use the formula:\[ V = ext{side}^3 \] This means you multiply the length of one side by itself twice. It's quite simple as it only requires knowing the length of one edge. For example, if a cube has a side that measures 1.32 cm, as in our exercise, the volume is calculated by raising this length to the power of three:- Your cube's volume: \( V = 1.32^3 \) - Performing the calculation results in a volume of 2.30 cm³.For your partner's cube, the process is identical:- Partner's cube's volume: \( V = 1.46^3 \) - The volume, when calculated, is 3.11 cm³.Both of these measures provide a vital piece of the puzzle when determining the material's identity.
Mass Measurement
Mass is the amount of matter in an object and is a crucial component in density determination. In this exercise, measuring the mass accurately is essential since it's used to derive the material density. Both you and your partner were given cubes with specific masses: - Your cube’s mass: 16.23 g - Partner's cube’s mass: 24.64 g When measuring mass, - Ensure the scales are calibrated correctly - Measure in a unit consistent with volume for ease of calculation (grams, in this case) Precision is necessary, as even slight variations in mass can affect the calculated density, thereby influencing the determination of the material type.
Material Identification
Identifying the material of an object based on measurements often involves calculating its density. Density is defined as mass per unit volume and is a distinguishing property for materials. Here's how you calculate density:\[ ext{Density} = \frac{ ext{Mass}}{ ext{Volume}} \]For your cube, given a mass of 16.23 g and a volume of 2.30 cm³, the density is:- Your density: \( \frac{16.23}{2.30} \approx 7.06 \text{ g/cm}^3 \)Your partner’s cube, with a mass of 24.64 g and a volume of 3.11 cm³, yields:- Partner's density: \( \frac{24.64}{3.11} \approx 7.92 \text{ g/cm}^3 \)By examining the densities, it's clear that they do not match:- Your cube: 7.06 g/cm³- Partner's cube: 7.92 g/cm³This significant difference indicates that the cubes are made of different materials, refuting your partner's conclusion of similarity.

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Most popular questions from this chapter

Classify the information in each of these statements as quantitative or qualitative and as relating to a physical or chemical property. (a) A white chemical compound has a mass of \(1.456 \mathrm{~g}\). When placed in water containing a dye, it causes the red color of the dye to fade to colorless. (b) A sample of lithium metal, with a mass of \(0.6 \mathrm{~g}\), was placed in water. The metal reacted with the water to produce the compound lithium hydroxide and the element hydrogen.

Write a chemical formula for each substance and draw a picture of how the nanoscale particles are arranged at room temperature. (a) Iodine, a solid that consists of diatomic molecules (b) Ozone, a gas that consists of triatomic molecules (c) Helium (d) Carbon dioxide

For each of the changes described, decide whether two or more elements formed a compound or if a compound decomposed (to form elements or other compounds). Explain your reasoning in each case. (a) Upon heating, a blue powder turned white and lost mass. (b) A white solid forms three different gases when heated. The total mass of the gases is the same as that of the solid.

Fritz Haber, a German chemist, proposed extracting gold from seawater as a way to pay off Germany's debt, \(\$ 28.8 \times 10^{6}\), after World War I. The value of gold at the time was \(\$ 21.25 /\) troy oz \((1\) troy \(o z=31.103 \mathrm{~g})\). The gold concentration in seawater is \(0.15 \mathrm{mg}\) gold/ton seawater \((1\) ton \(=2000 \mathrm{lb}\) ). Assume the density of seawater is \(1.03 \mathrm{~g} / \mathrm{cm}^{3}\) (a) Calculate the volume (in cubic kilometers) of seawater that would have had to be processed to obtain the required mass of gold. (b) By comparison, an Olympic-sized swimming pool is \(50 \mathrm{~m} \times 25 \mathrm{~m} \times 2.0 \mathrm{~m} .\) Calculate the number of Olympic-sized swimming pools required to hold the volume of seawater needed in part (a).

Ten of the elements are \(\mathrm{O}, \mathrm{H}, \mathrm{Ar}, \mathrm{Al}, \mathrm{Ca}, \mathrm{Br}, \mathrm{Ge}, \mathrm{K}, \mathrm{Cu}\) and \(P\). Pick the one that best fits each description: (a) an alkali metal; (b) a noble gas; (c) a transition metal; (d) a metalloid; (e) a Group 1 nonmetal; (f) an alkaline-earth metal; \((\mathrm{g})\) a halogen; (h) a nonmetal that is a solid.

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