Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

For each pair, choose the compound with the larger lattice energy, and explain your choice: (a) \(\mathrm{CaO}\) or CaS (b) \(\mathrm{BaO}\) or \(\mathrm{SrO}\)

Short Answer

Expert verified
The compounds with larger lattice energies are \(\text{CaO}\) for pair (a) and \(\text{SrO}\) for pair (b).

Step by step solution

01

Understanding Lattice Energy

Lattice energy is a measure of the strength of the forces between the ions in an ionic solid. It is affected by the charges on the ions and the distances between them. Higher charges and shorter distances result in larger lattice energy.
02

Compare the Charges of the Ions

Examine the charges of the ions in both pairs. For (a) \(\text{CaO}\) has \(\text{Ca}^{2+}\) and \(\text{O}^{2-}\). CaS has \(\text{Ca}^{2+}\) and \(\text{S}^{2-}\). For (b) \(\text{BaO}\) has \(\text{Ba}^{2+}\) and \(\text{O}^{2-}\). \(\text{SrO}\) has \(\text{Sr}^{2+}\) and \(\text{O}^{2-}\).
03

Compare the Sizes of the Ions

Smaller ions result in shorter distances between them, leading to a larger lattice energy. In (a), \(\text{S}^{2-}\) is larger than \(\text{O}^{2-}\), making \(\text{CaO}\) have a larger lattice energy than CaS. In (b), \(\text{Sr}^{2+}\) is smaller than \(\text{Ba}^{2+}\), making \(\text{SrO}\) have a larger lattice energy than \(\text{BaO}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

ionic bonds
Ionic bonds are a fundamental concept in chemistry. They involve the transfer of electrons from one atom to another. This transfer creates two oppositely charged ions.
The positive ion (cation) and the negative ion (anion) attract each other through electrostatic forces.
This attraction forms the ionic bond. Ionic bonds usually occur between metals and nonmetals.
For example, in the exercise you are dealing with compounds like \(\text{CaO}\), \(\text{CaS}\), \(\text{BaO}\), and \(\text{SrO}\).All these compounds are formed through ionic bonds.
ionic compounds
When ionic bonds form, they create ionic compounds. These compounds are typically solid at room temperature and have high melting points and boiling points.
The strong electrostatic force between the oppositely charged ions makes these points very high.
For example, \(\text{CaO}\) and \(\text{CaS}\) mentioned in the exercise are both ionic compounds.
Moreover, ionic compounds tend to dissolve in water and conduct electricity in molten or dissolved state because the ions are free to move and carry an electrical charge once they are in solution or melted state.
ion size
Ion size, also known as ionic radius, impacts many properties of ionic compounds, particularly lattice energy.
Smaller ions can get closer together, which increases the strength of the attraction between them. This proximity leads to larger lattice energies.
In the given exercise, for pair (a), \(\text{O}^{2-}\) is smaller than \(\text{S}^{2-}\), so \(\text{CaO}\) has a larger lattice energy compared to \(\text{CaS}\).
Similarly, for pair (b), \(\text{Sr}^{2+}\) is smaller than \(\text{Ba}^{2+}\), making \(\text{SrO}\) have a larger lattice energy than \(\text{BaO}\).
charge of ions
The charge of ions is another critical factor in determining lattice energy. Higher charges result in stronger electrostatic forces between the ions.
For example, all mentioned compounds in the exercise contain ions with charges of \(\text{2+}\) and \(\text{2-}\), but it is essential to consider both the charge and size to determine the lattice energy.
More precisely, when combining smaller ions with high charges, the resulting lattice energy will be significantly higher than that of larger ions with the same charges.
This understanding helps explain why \(\text{CaO}\) has a larger lattice energy than \(\text{CaS}\) and why \(\text{SrO}\) has a larger lattice energy than \(\text{BaO}\).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Rank the members of each set of compounds in order of increasing ionic character of their bonds. Use polar arrows to indicate the bond polarity of each: (a) \(\mathrm{HBr}, \mathrm{HCl}, \mathrm{HI}\) (b) \(\mathrm{H}_{2} \mathrm{O}, \mathrm{CH}_{4}, \mathrm{HF}\) (c) \(\mathrm{SCl}_{2}, \mathrm{PCl}_{3}, \mathrm{SiCl}_{4}\)

Using the periodic table only, arrange the elements in each set in order of decreasing EN: (a) \(\mathrm{N}, \mathrm{P}, \mathrm{Si}\) (b) \(\mathrm{Ca}, \mathrm{Ga},\) As

The text points out that, for similar types of substances, one with weaker bonds is usually more reactive than one with stronger bonds. Why is this generally true?

For each pair, choose the compound with the smaller lattice energy, and explain your choice: (a) CaS or BaS (b) NaF or MgO

9.86 Lattice energies can also be calculated for covalent network solids using a Born-Haber cycle, and the network solid silicon dioxide has one of the highest \(\Delta H_{\text {latice }}^{\circ}\) values. Silicon dioxide is found in pure crystalline form as transparent rock quartz. Much harder than glass, this material was once prized for making lenses for optical devices and expensive spectacles. Use Appendix \(\mathrm{B}\) and the following data to calculate \(\Delta H_{\text {lattioe }}^{\circ}\) of \(\mathrm{SiO}_{2}\) $$ \begin{array}{ll} \operatorname{Si}(s) \longrightarrow \operatorname{Si}(g) & \Delta H^{\circ}=454 \mathrm{~kJ} \\ \mathrm{Si}(g) \longrightarrow \mathrm{Si}^{4+}(g)+4 \mathrm{e}^{-} & \Delta H^{\circ}=9949 \mathrm{~kJ} \\ \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{O}(g) & \Delta H^{\circ}=498 \mathrm{~kJ} \\ \mathrm{O}(g)+2 \mathrm{e}^{-} \longrightarrow \mathrm{O}^{2-}(g) & \Delta H^{\circ}=737 \mathrm{~kJ} \end{array} $$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free