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Does the reaction of a main-group nonmetal oxide in water produce an acidic or a basic solution? Write a balanced equation for the reaction of a Group \(6 \mathrm{~A}(16)\) nonmetal oxide with water.

Short Answer

Expert verified
Acidic; \(SO_3 + H_2O \rightarrow H_2SO_4\)

Step by step solution

01

Identify the Type of Oxide

Determine whether the main-group nonmetal oxide will form an acidic or basic solution when it reacts with water. Nonmetal oxides typically form acidic solutions.
02

Determine the Group 6A(16) Nonmetal Oxides

Identify a common nonmetal oxide from Group 6A(16). One of the well-known oxides for this group is Sulfur trioxide \((SO_3)\).
03

Write the Reaction Equation

Combine the identified oxide \(SO_3\) with water \(H_2O\) to form the acidic solution. The balanced equation is: \((SO_3 + H_2O \rightarrow H_2SO_4)\).
04

Balance the Equation Confirmation

Verify that the equation is balanced. Sulfur (S), oxygen (O), and hydrogen (H) atoms are balanced on both sides of the equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Group 6A Nonmetals
Group 6A elements, also known as the chalcogens, include oxygen, sulfur, selenium, tellurium, and polonium. These elements share similar chemical properties due to their position in the periodic table.
Nonmetals in this group, such as oxygen and sulfur, commonly form oxides when combined with oxygen. These oxides are usually acidic. For instance, sulfur can form sulfur dioxide \(SO_2\) and sulfur trioxide \(SO_3\).
When these oxides react with water, they typically produce acidic solutions.
This is because they yield acids, such as sulfurous acid \(H_2SO_3\) from \(SO_2\) and sulfuric acid \(H_2SO_4\) from \(SO_3\), upon reaction with water.
Here's a quick bullet point summary of Group 6A nonmetals:
  • Oxygen (O)
  • Sulfur (S)
  • Selenium (Se)
  • Tellurium (Te)
  • Polonium (Po) - Metalloids and metals further down the group
Sulfur Trioxide and Water Reaction
One of the primary reactions involving Group 6A nonmetals is the reaction of sulfur trioxide \(SO_3\) with water.
This reaction is significant in both chemistry and environmental science.
When \(SO_3\) reacts with water \(H_2O\), it forms sulfuric acid \(H_2SO_4\).
This can be expressed as:
\[SO_3 + H_2O \rightarrow H_2SO_4\] Sulfuric acid is a strong acid and dissociates completely in water.
This reaction is highly exothermic, releasing a significant amount of heat.
It's important in industrial processes and environmental contexts since it contributes to acid rain formation.
Here's a brief summary of the reaction:
  • Sulfur Trioxide: \(SO_3\)
  • Reaction with Water: Forms sulfuric acid (\(H_2SO_4\))
  • Type of Reaction: Exothermic
Writing Balanced Chemical Equations
Writing balanced chemical equations is an essential skill in chemistry.
It ensures that the same number of each type of atom appears on both sides of the equation.
Steps to balance a chemical equation:
  • Write down the unbalanced equation.
  • Count the number of atoms of each element on both sides.
  • Add coefficients to balance the atoms, starting with the most complex molecule.
  • Ensure all elements are balanced.
  • Check your work by counting the atoms again.
For example, the balanced reaction of \(SO_3\) with water:
\[SO_3 + H_2O \rightarrow H_2SO_4\] In this equation:
Sulfur (S), oxygen (O), and hydrogen (H) atoms are balanced on both sides.
There is one sulfur atom, four oxygen atoms, and two hydrogen atoms on both sides.
Balancing chemical equations ensures the principle of conservation of mass is met and the stoichiometry of the reaction is correct.

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Most popular questions from this chapter

Summarize the trend in metallic character as a function of position in the periodic table. Is it the same as the trend in atomic size? The trend in ionization energy?

What is penetration? How is it related to shielding? Use the penetration effect to explain the difference in relative orbital energies of a \(3 p\) and a \(3 d\) electron in the same atom.

Name the element described in each of the following: (a) Smallest atomic radius in Group \(6 \mathrm{~A}(16)\) (b) Largest atomic radius in Period 6 (c) Smallest metal in Period 3 (d) Highest IE \(_{1}\) in Group \(4 \mathrm{~A}(14)\) (e) Lowest IE \(_{1}\) in Period 5 (f) Most metallic in Group \(5 \mathrm{~A}(15)\) (g) Group \(3 \mathrm{~A}(13)\) element that forms the most basic oxide (h) Period 4 element with highest energy level filled (i) Condensed ground-state electron configuration of [Ne] \(3 s^{2} 3 p^{2}\) (j) Condensed ground-state electron configuration of \([\mathrm{Kr}] 5 s^{2} 4 d^{6}\) (k) Forms \(2+\) ion with electron configuration [Ar] \(3 d^{3}\) (1) Period 5 element that forms \(3+\) ion with pseudo-noble gas configuration (m) Period 4 transition element that forms \(3+\) diamagnetic ion (n) Period 4 transition element that forms \(2+\) ion with a half-filled \(d\) sublevel (o) Heaviest lanthanide (p) Period 3 element whose \(2-\) ion is isoelectronic with Ar (q) Alkaline earth metal whose cation is isoelectronic with \(\mathrm{Kr}\) (r) Group \(5 \mathrm{~A}(15)\) metalloid with the most acidic oxide

Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic: (a) \(\mathrm{V}^{3+}\) (b) \(\mathrm{Cd}^{2+}\) (c) \(\mathrm{Co}^{3+}\) (d) \(\mathrm{Ag}^{+}\)

Draw the partial (valence-level) orbital diagram, and write the symbol, group number, and period number of the element: (a) \([\mathrm{He}] 2 s^{2} 2 p^{4}\) (b) \([\mathrm{Ne}] 3 s^{2} 3 p^{3}\)

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