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Distinguish between an absorption spectrum and an emission spectrum. With which did Bohr work?

Short Answer

Expert verified
An absorption spectrum has dark lines, and an emission spectrum has bright lines. Bohr worked with the emission spectrum.

Step by step solution

01

- Define Absorption Spectrum

An absorption spectrum is formed when photons are absorbed by matter, such as a gas, causing electrons to jump to higher energy levels. The result is a spectrum with dark lines or bands superimposed on a continuous spectrum, corresponding to the wavelengths of the absorbed light.
02

- Define Emission Spectrum

An emission spectrum occurs when excited electrons in an atom return to lower energy levels, releasing energy in the form of photons. This results in bright lines or bands at specific wavelengths against a dark background, representing the emitted light.
03

- Compare the Two Spectra

An absorption spectrum shows dark lines where light has been absorbed by electrons moving to higher energy levels, while an emission spectrum shows bright lines where light has been emitted by electrons returning to lower energy levels.
04

- Identify Bohr’s Work

Bohr worked with the emission spectrum of hydrogen to develop his model of the atom. By studying the discrete lines in the hydrogen emission spectrum, he was able to propose that electrons exist in quantized energy levels.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Absorption Spectrum
Imagine shining a beam of white light through a gas. Some of that light gets absorbed by the gas particles. This absorbed light makes the gas particles' electrons jump to higher energy levels. The result of this process is called an absorption spectrum.

In an absorption spectrum, you'll see a continuous spectrum of colors with dark lines or gaps. These dark lines appear at the wavelengths where light has been absorbed. These specific wavelengths identify which elements are present in the gas.
  • Absorption occurs when light is absorbed by electrons moving to higher energy levels.
  • The appearance is generally a continuous spectrum with dark lines.
  • The dark lines precisely match the energy needed to move electrons from one level to a higher one.
Emission Spectrum
Now, imagine that same gas whose electrons were excited by absorbing photons. When those excited electrons fall back down to lower energy levels, they release energy in the form of light. This process creates an emission spectrum.

An emission spectrum looks like a series of bright lines on a dark background. Each bright line corresponds to the energy released as an electron jumps from a higher to a lower energy level. This spectrum tells us the specific energy levels in an atom and can be used to identify the chemical elements present.
  • Emission occurs when excited electrons lose energy and fall to lower levels.
  • The appearance is a dark background with bright lines.
  • The bright lines match the specific energies released during the electron transitions.
Bohr Model
The Bohr Model is a revolutionary concept in atomic physics, developed by Niels Bohr. He studied the emission spectrum of hydrogen, the simplest atom, and devised a model that explained the discrete lines seen in the spectrum.

According to the Bohr Model:
  • Electrons orbit the nucleus in fixed paths or energy levels.
  • These energy levels are quantized, meaning electrons can only occupy specific, discrete levels.
  • When an electron jumps from a higher to a lower energy level, it emits a photon with energy equal to the difference between the two levels.
  • Conversely, absorbing a photon can make an electron jump to a higher energy level.
By applying these concepts, Bohr was able to explain the lines in the hydrogen emission spectrum. Specifically, these lines correspond to the energy differences between the quantized orbits of the electron. This model was groundbreaking as it combined classical physics with quantum mechanics to better understand atomic structure.

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Most popular questions from this chapter

Refractometry is based on the difference in the speed of light through a substance (v) and through a vacuum ( \(c\) ). In the procedure, light of known wavelength passes through a fixed thickness of the substance at a known temperature. The index of refraction equals \(c / v\). Using yellow light \((\lambda=589 \mathrm{nm})\) at \(20^{\circ} \mathrm{C}\). for example, the index of refraction of water is 1.33 and that of diamond is \(2.42 .\) Calculate the speed of light in (a) water and (b) diamond.

In the course of developing his model, Bohr arrived at the following formula for the radius of the electron's orbit: \(r_{n}=\) \(n^{2} h^{2} \varepsilon_{0} / \pi m_{0} e^{2},\) where \(m_{c}\) is the electron's mass, \(e\) is its charge, and \(\varepsilon_{0}\) is a constant related to charge attraction in a vacuum. Given that \(m_{\mathrm{z}}=9.109 \times 10^{-31} \mathrm{~kg}, e=1.602 \times 10^{-19} \mathrm{C},\) and \(\varepsilon_{0}=8.854 \times 10^{-12} \mathrm{C}^{2} / \mathrm{J} \cdot \mathrm{m}\) calculate the following: (a) The radius of the first \((n=1)\) orbit in the \(\mathrm{H}\) atom (b) The radius of the tenth \((n=10)\) orbit in the \(\mathrm{H}\) atom

A radio wave has a frequency of \(3.8 \times 10^{10} \mathrm{~Hz}\). What is the energy (in \(J\) ) of one photon of this radiation?

Cobalt- 60 is a radioactive isotope used to treat cancers. A gamma ray emitted by this isotope has an energy of \(1.33 \mathrm{MeV}\) (million electron volts; \(1 \mathrm{eV}=1.602 \times 10^{-19} \mathrm{~J}\) ). What are the frequency (in \(\mathrm{Hz}\) ) and the wavelength (in \(\mathrm{m}\) ) of this gamma ray?

A sodium flame has a characteristic yellow color due to emission of light of wavelength \(589 \mathrm{nm}\). What is the mass equivalence of one photon with this wavelength \(\left(1 \mathrm{~J}=1 \mathrm{~kg} \cdot \mathrm{m}^{2} / \mathrm{s}^{2}\right) ?\)

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