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Express Hess's law in your own words.

Short Answer

Expert verified
Hess's law states that the total enthalpy change for a reaction is the same, regardless of the pathway taken, provided the initial and final states are identical.

Step by step solution

01

Understand the Concept

Begin by recognizing that Hess's law is a principle in chemistry that allows the calculation of the total enthalpy change for a reaction. It states that the total enthalpy change of a reaction is the same, regardless of the path taken, as long as the initial and final conditions are identical.
02

Identify Key Components

Note the key components involved in Hess's law: enthalpy change (ΔH), different reaction paths, and initial and final states of the reactants and products.
03

Create a Simple Explanation

Using the identified components, express Hess's law in simpler terms: If you can transform reactants into products either directly or through some other series of reactions, the total enthalpy change (ΔH) will be the same in both cases.
04

Apply to an Example

Consider a hypothetical reaction where reactant A turns into product B. According to Hess's law, no matter if A turns directly into B or goes through intermediate steps such as A -> C -> B, the overall enthalpy change remains constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

enthalpy change
Enthalpy change, symbolized as \(\text{ΔH}\), signifies the amount of heat absorbed or released during a chemical reaction at constant pressure. It is crucial in thermochemistry for understanding energy transfers. When a reaction occurs:
  • \( \text{ΔH} < 0 \) : The reaction is exothermic, releasing heat.
  • \( \text{ΔH} > 0 \) : The reaction is endothermic, absorbing heat.

Enthalpy change can be influenced by several factors:
  • The nature of reactants and products.
  • The states of matter involved.
  • The external conditions such as temperature and pressure.

In the context of Hess's Law, understanding \( \text{ΔH} \) is essential, as it is the key value calculated and compared across different reaction pathways.
reaction pathways
A reaction pathway refers to the series of steps or intermediate stages through which reactants transform into products in a chemical reaction. The reaction pathway can vary, but according to Hess's Law:
''The total enthalpy change for a reaction is the same, irrespective of the pathway taken, provided the initial and final states are consistent.''

For example, if a reactant A converts to a product B through a direct reaction, or via intermediates (say A -> C -> B), the overall enthalpy change \( (\text{ΔH}) \) remains constant if the starting and ending materials are the same. This is because enthalpy is a state function, meaning it depends only on the initial and final states, not the route taken. This principle helps chemists use simpler or more feasible pathways to calculate \( \text{ΔH} \) when direct measurement is difficult.
thermochemistry
Thermochemistry is the branch of chemistry that deals with the study of heat changes accompanying chemical reactions and phase changes. Central to thermochemistry are concepts like enthalpy change \( (\text{ΔH}) \) and specific laws like Hess's Law.

Some key points about thermochemistry:
  • Focuses on the heat involved in chemical processes.
  • Includes the study of endothermic and exothermic reactions.
  • Helps predict energy requirements and transfer for reactions.

By applying Hess's Law, thermochemistry allows us to:
  • Calculate the enthalpy change for complex reactions by piecing together simpler steps.
  • Use known enthalpy changes for intermediary reactions to determine overall heat exchanges.
  • Understand and predict how reactions are affected by heat, aiding in practical applications such as energy production and material synthesis.

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Most popular questions from this chapter

What is the change in internal energy (in \(J\) ) of a system that releases \(675 \mathrm{~J}\) of thermal energy to its surroundings and has \(530 \mathrm{cal}\) of work done on it?

When \(25.0 \mathrm{~mL}\) of \(0.500 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) is added to \(25.0 \mathrm{~mL}\) of 1.00 \(M\) KOH in a coffee-cup calorimeter at \(23.50^{\circ} \mathrm{C}\), the temperature rises to \(30.17^{\circ} \mathrm{C}\). Calculate \(\Delta H\) in \(\mathrm{kJ}\) per mole of \(\mathrm{H}_{2} \mathrm{O}\) formed. (Assume that the total volume is the sum of the volumes and that the density and specific heat capacity of the solution are the same as for water.)

Stearic acid \(\left(\mathrm{C}_{18} \mathrm{H}_{36} \mathrm{O}_{2}\right)\) is a fatty acid, a molecule with a long hydrocarbon chain and an organic acid group (COOH) at the end. It is used to make cosmetics, ointments, soaps, and candles and is found in animal tissue as part of many saturated fats. In fact, when you eat meat, you are ingesting some fats containing stearic acid. (a) Write a balanced equation for the combustion of stearic acid to gaseous products. (b) Calculate \(\Delta H_{\mathrm{rm}}^{\circ}\) for this combustion \(\left(\Delta H_{\mathrm{i}}^{\circ}\right.\) of \(\mathrm{C}_{18} \mathrm{H}_{36} \mathrm{O}_{2}=\) \(-948 \mathrm{~kJ} / \mathrm{mol})\) (c) Calculate the heat \((q)\) released in \(\mathrm{kJ}\) and kcal when \(1.00 \mathrm{~g}\) of stearic acid is burned completely. (d) A candy bar contains \(11.0 \mathrm{~g}\) of fat and provides \(100 .\) Cal from fat; is this consistent with your answer for part (c)?

State two ways that you increase the internal energy of your body and two ways that you decrease it.

One piece of copper jewelry at \(105^{\circ} \mathrm{C}\) has twice the mass of another piece at \(45^{\circ} \mathrm{C}\). Both are placed in a calorimeter of negligible heat capacity. What is the final temperature inside the calorimeter \((c\) of copper \(=0.387 \mathrm{~J} / \mathrm{g} \cdot \mathrm{K}) ?\)

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