Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What is the average kinetic energy and rms speed of \(\mathrm{N}_{2}\) molecules at STP? Compare these values with those of \(\mathrm{H}_{2}\) molecules at STP. [Use \(R=8.314 \mathrm{~J} /(\mathrm{mol} \cdot \mathrm{K})\) and express \(\mathscr{M}\) in \(\mathrm{kg} / \mathrm{mol} .]\)

Short Answer

Expert verified
Average kinetic energies: 3406.84 J/mol for both \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2}\). RMS speeds: 493.1 m/s for \(\mathrm{N}_{2}\) and 1920 m/s for \(\mathrm{H}_{2}\).

Step by step solution

01

- Identify given values

Identify the given values needed for the calculations. For \(\mathrm{N}_{2}\): \mathscr{M} = 0.028 \,kg/mol, and for \(\mathrm{H}_{2}\): \mathscr{M} = 0.002 \,kg/mol. Use the gas constant R = 8.314 \,J/(mol \cdot \, K)
02

- Calculate the temperature at STP

The temperature at STP (Standard Temperature and Pressure) is 0°C, which is 273.15 K.
03

- Use the formula for average kinetic energy

The average kinetic energy of a gas molecule is given by \[ \frac{3}{2} k_B T \], where \ k_B \ is Boltzmann's constant (1.38 \times 10^{-23} \ J/K) and \ T \ is the temperature. However, use the mole-based formula \[ KE = \frac{3}{2} RT \] where R is the gas constant and T is the temperature.
04

- Compute the average kinetic energy for \(\mathrm{N}_{2}\)

Plug in the values: \[ KE_{N_2} = \frac{3}{2} \, (8.314 \, J/(mol \cdot \, K)) \, (273.15 \, K) = 3406.84 \, J/mol \]
05

- Compute the average kinetic energy for \(\mathrm{H}_{2}\)

Plug in the values: \[ KE_{H_2} = \frac{3}{2} \, (8.314 \, J/(mol \cdot \, K)) \, (273.15 \, K) = 3406.84 \, J/mol \]
06

- Use the formula for RMS speed

The root mean square (RMS) speed of molecules is given by the formula \[ v_{rms} = \sqrt{\frac{3RT}{\mathscr{M}}} \]
07

- Compute RMS speed for \(\mathrm{N}_{2}\)

Plug in the values: \[ v_{rms_{N2}} = \sqrt{\frac{3 \, \times 8.314 \, J/(mol \cdot \, K) \, \times 273.15 \, K}{0.028 \, kg/mol}} = 493.1 \, m/s \]
08

- Compute RMS speed for \(\mathrm{H}_{2}\)

Plug in the values: \[ v_{rms_{H2}} = \sqrt{\frac{3 \, \times 8.314 \, J/(mol \cdot \, K) \, \times 273.15 \, K}{0.002 \, kg/mol}} = 1920 \, m/s \]
09

- Compare values

Note that while the average kinetic energies of \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2}\) are the same at STP, the RMS speeds differ due to their masses, with \(\mathrm{H}_{2}\) having a higher RMS speed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

average kinetic energy
The average kinetic energy of gas molecules is a measure of the energy contained in their random motion. For a single molecule, it's given by the formula \[ \text{KE} = \frac{3}{2} k_B T \] where \( k_B \) is Boltzmann's constant and \( T \) is the temperature in Kelvin. However, when dealing with a mole of gas molecules, we use the formula \[ \text{KE} = \frac{3}{2} RT \] where \( R \) is the gas constant. This formula tells us how the average kinetic energy depends solely on temperature, not on the type of gas. At Standard Temperature and Pressure (STP), the computed average kinetic energy for both \( N_2 \) and \( H_2 \) is the same, 3406.84 J/mol, showing that kinetic energy is independent of the gas's identity.
RMS speed
Root Mean Square (RMS) speed gives a measure of the speed of gas molecules in a sample. It's defined by the equation \[ v_{\text{rms}} = \sqrt{\frac{3RT}{ \mathscr{M} }} \] Here, \( R \) is the gas constant, \( T \) is the temperature in Kelvin, and \( \mathscr{M} \) is the molar mass of the gas in kg/mol. RMS speed accounts for the different speeds of molecules due to their masses. For instance, at STP, \( N_2 \) molecules have an RMS speed of 493.1 m/s owing to their larger molar mass of 0.028 kg/mol, whereas \( H_2 \) molecules, which are lighter with a molar mass of 0.002 kg/mol, zip around faster with an RMS speed of 1920 m/s.
Standard Temperature and Pressure (STP)
Standard Temperature and Pressure (STP) is a set of conditions used in experiments to allow for consistent and comparable data. At STP, the temperature is defined as 0°C (273.15 K), and the pressure is 1 atm (101.325 kPa). These conditions are considered the standard for conducting and comparing gas experiments. By calculating values at STP, we can easily compare the behaviors of different gases without worrying about varying experimental conditions.
molar mass
Molar mass is a measure of the mass of one mole of a substance. It's expressed in kg/mol for these calculations. Molar mass significantly influences RMS speed because the heavier the gas molecules, the slower they move at a given temperature. For example, nitrogen (\( N_2 \)) has a molar mass of 0.028 kg/mol, while hydrogen (\( H_2 \)) has a much lower molar mass of 0.002 kg/mol, explaining why \( H_2 \) molecules travel faster than \( N_2 \) molecules at the same temperature.
gas constant
The gas constant, denoted as \( R \), is a fundamental constant that appears in various gas-related equations, such as the Ideal Gas Law and kinetic theory formulas. Its value is 8.314 J/(mol·K). This constant helps relate various properties of gases, such as volume, temperature, pressure, and energy. In our formulas for average kinetic energy and RMS speed, \( R \) assists in connecting the temperature and energy or speed of gas molecules, allowing us to perform calculations that demonstrate the behavior of gases under different conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A person inhales air richer in \(\mathrm{O}_{2}\) and exhales air richer in \(\mathrm{CO}_{2}\) and water vapor. During each hour of sleep, a person exhales a total of about \(300 \mathrm{~L}\) of this \(\mathrm{CO}_{2}\) -enriched and \(\mathrm{H}_{2} \mathrm{O}\) -enriched air. (a) If the partial pressures of \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) in exhaled air are each 30.0 torr at \(37.0^{\circ} \mathrm{C},\) calculate the mass \((\mathrm{g})\) of \(\mathrm{CO}_{2}\) and of \(\mathrm{H}_{2} \mathrm{O}\) exhaled in \(1 \mathrm{~h}\) of sleep. (b) How many grams of body mass does the person lose in \(8 \mathrm{~h}\) of sleep if all the \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) exhaled come from the metabolism of glucose? $$\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g) \longrightarrow 6 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(g)$$

A sample of methane is placed in a \(10.0-\mathrm{L}\) container at \(25^{\circ} \mathrm{C}\) and \(725 \mathrm{mmHg}\). The gas sample is then moved to a \(7.50-\mathrm{L}\) container at \(25^{\circ} \mathrm{C}\). What is the gas pressure in the second container?

A barometer tube is \(1.00 \times 10^{2} \mathrm{~cm}\) long and has a crosssectional area of \(1.20 \mathrm{~cm}^{2}\). The height of the mercury column is \(74.0 \mathrm{~cm},\) and the temperature is \(24^{\circ} \mathrm{C}\). A small amount of \(\mathrm{N}_{2}\) is introduced into the evacuated space above the mercury, which causes the mercury level to drop to a height of \(64.0 \mathrm{~cm}\). How many grams of \(\mathrm{N}_{2}\) were introduced?

A gaseous organic compound containing only carbon, hydrogen, and nitrogen is burned in oxygen gas, and the volume of each reactant and product is measured under the same conditions of temperature and pressure. Reaction of four volumes of the compound produces 4 volumes of \(\mathrm{CO}_{2}, 2\) volumes of \(\mathrm{N}_{2},\) and 10 volumes of water vapor. (a) How many volumes of \(\mathrm{O}_{2}\) were required? (b) What is the empirical formula of the compound?

At a height of \(300 \mathrm{~km}\) above Earth's surface, an astronaut finds that the atmospheric pressure is about \(10^{-8} \mathrm{mmHg}\) and the temperature is \(500 \mathrm{~K}\). How many molecules of gas are there per milliliter at this altitude?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free