Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

How many moles of \(\mathrm{H}^{+}\) ions are present in each of the following aqueous solutions? (a) \(1.4 \mathrm{~mL}\) of \(0.75 \mathrm{M}\) hydrobromic acid (b) \(2.47 \mathrm{~mL}\) of \(1.98 \mathrm{M}\) hydriodic acid (c) \(395 \mathrm{~mL}\) of \(0.270 \mathrm{M}\) nitric acid

Short Answer

Expert verified
0.00105 moles, 0.0048906 moles, 0.10665 moles

Step by step solution

01

- Understand the relationship between molarity, volume, and moles

Molarity (M) is defined as moles of solute per liter of solution. To find the number of moles, use the formula: \[ \text{Moles} = \text{Molarity} \times \text{Volume (in liters)} \]
02

- Convert the given volume to liters

Volumes are given in milliliters (mL), and we need to convert them to liters (L) since molarity is in moles per liter. Use the conversion: \[ 1 \text{ mL} = 0.001 \text{ L} \]
03

- Calculate moles for each solution

(a) Hydrobromic acid: Volume = 1.4 mL = 0.0014 L, Molarity = 0.75 M\[ \text{Moles} = 0.75 \text{ M} \times 0.0014 \text{ L} = 0.00105 \text{ moles} \] (b) Hydriodic acid: Volume = 2.47 mL = 0.00247 L, Molarity = 1.98 M\[ \text{Moles} = 1.98 \text{ M} \times 0.00247 \text{ L} = 0.0048906 \text{ moles} \] (c) Nitric acid: Volume = 395 mL = 0.395 L, Molarity = 0.270 M\[ \text{Moles} = 0.270 \text{ M} \times 0.395 \text{ L} = 0.10665 \text{ moles} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

molarity
Molarity is a fundamental concept in chemistry, especially when dealing with solutions. It measures the concentration of a solute in a given volume of solution, using the formula: \(M = \frac{\text{Moles of solute}}{\text{Volume of solution in liters}} \). This means that molarity (M) tells you how many moles of a substance are present in one liter of a solution. For example, a solution with 1 mole of table salt in 1 liter of water has a molarity of 1 M (1 mol/L). Molarity is essential in stoichiometry calculations and helps in predicting how different solutions will react with each other. Knowing the molarity of a solution allows you to determine the amount of solute present, which is the key to solving many chemistry problems.
volume conversion
Volume conversion is critical when working with solutions, especially because molarity is based on liters. Given volumes often come in milliliters (mL), which must be converted to liters (L). Take note that 1 liter is equivalent to 1,000 milliliters. Therefore, to convert milliliters to liters, you simply multiply the number of milliliters by 0.001. For example:
  • 1 mL = 0.001 L
  • 50 mL = 50 × 0.001 = 0.05 L
By ensuring the volume is in liters, you can correctly use the molarity formula: \(\text{Moles} = \text{Molarity} \times \text{Volume in liters} \). Let's use the example from the exercise:
  • 1.4 mL = 1.4 × 0.001 = 0.0014 L
  • 2.47 mL = 2.47 × 0.001 = 0.00247 L
  • 395 mL = 395 × 0.001 = 0.395 L
Once the conversion is complete, you can easily calculate the number of moles using the molarity formula.
aqueous solutions
An aqueous solution is simply a solution where water is the solvent. In other words, substances are dissolved in water to form these solutions. Water is a universal solvent, which means it can dissolve many compounds and is commonly used in chemistry. Aqueous solutions are particularly important in understanding how different substances react in water. Many reactions, such as acid-base reactions or ionic dissociations, happen in aqueous solutions. For example, acids like hydrobromic acid (HBr), hydriodic acid (HI), and nitric acid (HNO3) dissolve in water to release \(\mathrm{H}^{+}\) ions, contributing to the characteristics of stomach acid. To summarize, when dealing with problems involving aqueous solutions:
  • Determine the substance's molarity.
  • Convert the given volume to liters.
  • Use the molarity formula to find the number of moles desired.
Follow these steps, and you'll be able to navigate calculations involving aqueous solutions effectively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Calculate each of the following quantities: (a) Molarity of a solution prepared by diluting \(37.00 \mathrm{~mL}\) of \(0.250 \mathrm{M}\) potassium chloride to \(150.00 \mathrm{~mL}\) (b) Molarity of a solution prepared by diluting \(25.71 \mathrm{~mL}\) of \(0.0706 \mathrm{M}\) ammonium sulfate to \(500.00 \mathrm{~mL}\) (c) Molarity of sodium ion in a solution made by mixing \(3.58 \mathrm{~mL}\) of \(0.348 M\) sodium chloride with \(500 . \mathrm{mL}\) of \(6.81 \times 10^{-2} M\) sodium sulfate (assume volumes are additive)

Limestone (calcium carbonate) is insoluble in water but dissolves in aqueous hydrochloric acid. Write balanced total ionic and net ionic equations, showing hydrochloric acid as it actually exists in water and the reaction as a proton- transfer process.

Physicians who specialize in sports medicine routinely treat athletes and dancers. Ethyl chloride, a local anesthetic commonly used for simple injuries, is the product of the combination of ethylene with hydrogen chloride: $$ \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{HCl}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(g) $$ Assume that \(0.100 \mathrm{~kg}\) of \(\mathrm{C}_{2} \mathrm{H}_{4}\) and \(0.100 \mathrm{~kg}\) of \(\mathrm{HCl}\) react. (a) How many molecules of gas (reactants plus products) are present when the reaction is complete? (b) How many moles of gas are present when half the product forms?

Does an aqueous solution of each of the following conduct an electric current? Explain. (a) Cesium bromide (b) Hydrogen iodide

A student forgets to weigh a mixture of sodium bromide dihydrate and magnesium bromide hexahydrate. Upon strong heating, the sample loses \(252.1 \mathrm{mg}\) of water. The mixture of anhydrous salts reacts with excess AgNO \(_{3}\) solution to form \(6.00 \times 10^{-3} \mathrm{~mol}\) of solid AgBr. Find the mass \(\%\) of each compound in the original mixture.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free