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Calculate the molar mass of each of the following: (a) \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\) (b) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) (c) \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\) (d) \(\mathrm{BrF}_{3}\)

Short Answer

Expert verified
Molar masses: (a) 149.12 g/mol, (b) 84.93 g/mol, (c) 249.72 g/mol, (d) 136.90 g/mol.

Step by step solution

01

- Calculate the Molar Mass of \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\)

First, find the atomic masses of nitrogen (N), hydrogen (H), phosphorus (P), and oxygen (O). Then, calculate the total molar mass by adding up the contributions of each element as follows: For \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\): \(3\times(1\times\mathrm{N}+4\times \mathrm{H})\)+\(1\times \mathrm{P} + 4\times \mathrm{O})\) \[3\times(14.01 + 4\times1.01) + (30.97 + 4\times16.00)\] \[3\times18.05 + 30.97 + 64.00 \] \[54.15 + 30.97 + 64.00 = 149.12 \ \mathrm{g/mol}\]
02

- Calculate the Molar Mass of \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\)

Find the atomic masses of carbon (C), hydrogen (H), and chlorine (Cl). Then, calculate the molar mass by adding up the contributions of each element: For \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\): \(1 \times \mathrm{C} + 2 \times \mathrm{H} + 2 \times \mathrm{Cl} \) \[12.01 + 2\times 1.01 + 2\times35.45\] \[12.01 + 2.02 + 70.90 \] \[12.01 + 2.02 + 70.90 = 84.93 \ \mathrm{g/mol}\]
03

- Calculate the Molar Mass of \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\)

Find the atomic masses of copper (Cu), sulfur (S), oxygen (O), and hydrogen (H). Then, calculate the molar mass by adding up the contributions of each element: For \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\): \(1 \times \mathrm{Cu} + 1 \times \mathrm{S} + 4 \times \mathrm{O} + 5 \times(2 \times \mathrm{H} + \mathrm{O})\) \[63.55 + 32.07 + 4\times16.00 + 5\times(2\times 1.01 + 16.00)\] \[63.55 + 32.07 + 64.00 + 5\times18.02\] \[63.55 + 32.07 + 64.00 + 90.10\] \[63.55 + 32.07 + 64.00 + 90.10 = 249.72 \ \mathrm{g/mol}\]
04

- Calculate the Molar Mass of \(\mathrm{BrF}_{3}\)

Find the atomic masses of bromine (Br) and fluorine (F). Then, calculate the molar mass by adding up the contributions of each element: For \(\mathrm{BrF}_{3}\): \(1 \times \mathrm{Br} + 3 \times \mathrm{F}\) \[79.90 + 3\times19.00\] \[79.90 + 57.00\] \[79.90 + 57.00 = 136.90 \ \mathrm{g/mol}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Mass
To calculate the molar mass of a compound, you first need to understand the concept of atomic mass. Atomic mass is the mass of an individual atom, usually expressed in atomic mass units (amu). Each element has a unique atomic mass which can be found on the periodic table. For example:
- Hydrogen (H) has an atomic mass of approximately 1.01 amu.
- Carbon (C) has an atomic mass of approximately 12.01 amu.
- Oxygen (O) has an atomic mass of approximately 16.00 amu.
When you calculate the molar mass, you sum up the atomic masses of all atoms present in the molecule.
Molecular Formula
The molecular formula shows the exact number of each type of atom in a molecule. This is key for calculating the molar mass of the compound. For instance, in the compound \( \left( \mathrm{NH}_{4} \right)_{3} \mathrm{PO}_{4} \), the molecular formula tells us that there are:
- 3 nitrogen (N) atoms
- 12 hydrogen (H) atoms (since 4 hydrogen atoms are bonded to each nitrogen, and there are 3 nitrogen)
- 1 phosphorus (P) atom
- 4 oxygen (O) atoms
Each of these counts should be multiplied by their respective atomic masses and then summed together to get the total molar mass.
Stoichiometry
Stoichiometry involves the quantitative relationships between reactants and products in a chemical reaction. It also plays a role when calculating molar masses. For instance, water is often found in its hydrated form in many compounds (like \( \mathrm{CuSO}_{4} \cdot 5\mathrm{H}_{2} \mathrm{O} \)). The '5H2O' indicates that there are five water molecules for every formula unit of copper(II) sulfate. You need to account for these additional water molecules when calculating the molar mass of the hydrated compound.
In this example:
- Water (H2O) has a molar mass of approximately 18.02 amu (from 2 x H + 1 x O)
- This value needs to be multiplied by 5, the number of water molecules, and then added to the molar mass of anhydrous \( \mathrm{CuSO}_{4} \).
Chemical Compounds
Chemical compounds are made up of two or more elements chemically bonded together. Understanding the types of bonds and the way elements combine helps in calculating their molar mass. For example, in \( \mathrm{BrF}_{3} \) , bromine (Br) and fluorine (F) are bonded. The molecular formula lets you know there are one bromine and three fluorine atoms.
To calculate the molar mass:
- Find the atomic mass of bromine: 79.90
- Find the atomic mass of fluorine: 19.00
- Multiply the atomic mass of fluorine by 3, then add it to the atomic mass of bromine.This gives \[ 79.90\ + \ (3 \times 19.00) = 136.90 \ \text{g/mol} \]
Understanding these concepts ensures you correctly calculate the molar mass of any given chemical compound.

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Most popular questions from this chapter

List three ways compositional data may be given in a problem that involves finding an empirical formula.

Convert the following into balanced equations: (a) When lead(II) nitrate solution is added to potassium iodide solution, solid lead(II) iodide forms and potassium nitrate solution remains. (b) Liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas, and hydrogen gas. (c) When nitrogen dioxide is bubbled into water, a solution of nitric acid forms and gaseous nitrogen monoxide is released.

What advantage is there to using a counting unit (the mole), rather than a mass unit, for amount of substance?

When powdered zinc is heated with sulfur, a violent reaction occurs, and zinc sulfide forms: $$ \mathrm{Zn}(s)+\mathrm{S}_{8}(s) \longrightarrow \mathrm{ZnS}(s)[\text { unbalanced }] $$ Some of the reactants also combine with oxygen in air to form zinc oxide and sulfur dioxide. When \(83.2 \mathrm{~g}\) of Zn reacts with \(52.4 \mathrm{~g}\) of \(\mathrm{S}_{8}\), \(104.4 \mathrm{~g}\) of \(\mathrm{ZnS}\) forms. (a) What is the percent yield of \(\mathrm{ZnS}\) ? (b) If all the remaining reactants combine with oxygen, how many grams of each of the two oxides form?

Ethanol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\right),\) the intoxicant in alcoholic beverages, is also used to make other organic compounds. In concentrated sulfuric acid, ethanol forms diethyl ether and water: $$ 2 \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}(l) \longrightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}(l)+\mathrm{H}_{2} \mathrm{O}(g) $$ In a side reaction, some ethanol forms ethylene and water: $$ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}(l) \longrightarrow \mathrm{CH}_{2} \mathrm{CH}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g) $$ (a) If \(50.0 \mathrm{~g}\) of ethanol yields \(35.9 \mathrm{~g}\) of diethyl ether, what is the percent yield of diethyl ether? (b) If \(45.0 \%\) of the ethanol that did not produce the ether reacts by the side reaction, what mass (g) of ethylene is produced?

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