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Why might the expression " 1 mol of chlorine" be confusing? What change would remove any uncertainty? For what other elements might a similar confusion exist? Why?

Short Answer

Expert verified
The expression '1 mol of chlorine' is confusing because it is unclear if it refers to Cl atoms or Cl_{2} molecules. Replacing it with '1 mol of Cl atoms' or '1 mol of Cl_{2} molecules' removes the ambiguity. Similar confusion exists for oxygen, nitrogen, and hydrogen due to their diatomic forms.

Step by step solution

01

Understand the term 'mol'

One 'mol' is a unit in chemistry that represents a quantity of Avogadro's number (approximately 6.022 x 10^{23}) of entities, such as atoms, ions, or molecules.
02

Identify the ambiguity in '1 mol of chlorine'

The term '1 mol of chlorine' is ambiguous because chlorine can exist as Cl atoms or Cl_{2} molecules. It is unclear whether it refers to one mole of individual Cl atoms or one mole of Cl_{2} molecules.
03

Clarify the expression

To remove uncertainty, specify the chemical form of chlorine. Use '1 mol of Cl atoms' for individual chlorine atoms or '1 mol of Cl_{2} molecules' for diatomic chlorine molecules.
04

Identify other potentially confusing elements

Similar confusion might exist for elements like oxygen (O and O_{2}), nitrogen (N and N_{2}), and hydrogen (H and H_{2}) because these elements also commonly form diatomic molecules.
05

Explain why the confusion exists

The confusion arises because these elements can exist both as individual atoms and as diatomic molecules. Without specifying the form, it is unclear what the term '1 mol' refers to.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Avogadro's number
Avogadro's number is a fundamental constant in chemistry and represents the number of particles (atoms, ions, or molecules) in one mole. The value of Avogadro's number is approximately 6.022 x 10^{23}.
This large number helps chemists understand and measure substances at the molecular scale, enabling precise calculations and conversions between mass, particles, and volume.
For example, if you have one mole of water (H_{2}O), it means you have 6.022 x 10^{23} water molecules. The importance of this concept cannot be overstated as it provides a bridge between the macroscopic and microscopic worlds.
To make things easier:
  • One mole of any element contains approximately 6.022 x 10^{23} entities.
  • This allows for easier balancing of chemical equations and computation of reactant and product quantities.
Understanding Avogadro's number is essential to mastering the mole concept.
Diatomic molecules
Some elements, like chlorine, exist naturally as diatomic molecules, meaning each molecule is composed of two atoms. For chlorine, the chemical formula is Cl_{2}. This means that when we refer to '1 mole of chlorine molecules,' we actually mean '1 mole of Cl_{2} molecules,' containing 2 moles of Cl atoms.

In chemistry, common diatomic molecules include:
  • Oxygen (O_{2})
  • Hydrogen (H_{2})
  • Nitrogen (N_{2})
  • Fluorine (F_{2})
  • Bromine (Br_{2})
The presence of diatomic molecules can lead to potential confusion when dealing with amounts. For example, saying '1 mol of oxygen' could ambiguously mean 1 mole of O atoms or O_{2} molecules. This ambiguity must be clarified to avoid errors in chemical calculations.
Always explicitly state the chemical form to avoid confusion.
Chemical ambiguity
Chemical ambiguity arises when a term can refer to multiple different forms of a substance. For example, '1 mol of chlorine' can refer to either 1 mole of Cl atoms or 1 mole of Cl_{2} molecules. Such ambiguity can lead to significant errors in experiments and calculations.
To avoid this:
  • Be specific about the molecular or atomic form—say '1 mole of Cl atoms' or '1 mole of Cl_{2} molecules.'
  • This practice clarifies what exactly is being measured or utilized in a reaction.
This issue can also occur with other diatomic molecules like oxygen, nitrogen, and hydrogen. These elements naturally form diatomic molecules (O_{2}, N_{2}, H_{2}), but they can also exist as individual atoms in certain conditions. Clarifying whether you're talking about molecules or atoms ensures accurate and reproducible results.
Developing good habits of precise terminology helps foster clear communication and understanding in chemistry.

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Most popular questions from this chapter

Ethanol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\right),\) the intoxicant in alcoholic beverages, is also used to make other organic compounds. In concentrated sulfuric acid, ethanol forms diethyl ether and water: $$ 2 \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}(l) \longrightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}(l)+\mathrm{H}_{2} \mathrm{O}(g) $$ In a side reaction, some ethanol forms ethylene and water: $$ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}(l) \longrightarrow \mathrm{CH}_{2} \mathrm{CH}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g) $$ (a) If \(50.0 \mathrm{~g}\) of ethanol yields \(35.9 \mathrm{~g}\) of diethyl ether, what is the percent yield of diethyl ether? (b) If \(45.0 \%\) of the ethanol that did not produce the ether reacts by the side reaction, what mass (g) of ethylene is produced?

Many metals react with oxygen gas to form the metal oxide. For example, calcium reacts as follows: $$ 2 \mathrm{Ca}(s)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CaO}(s) $$ You wish to calculate the mass (g) of calcium oxide that can be prepared from \(4.20 \mathrm{~g}\) of \(\mathrm{Ca}\) and \(2.80 \mathrm{~g}\) of \(\mathrm{O}_{2}\). (a) What amount (mol) of CaO can be produced from the given mass of Ca? (b) What amount (mol) of CaO can be produced from the given mass of \(\mathrm{O}_{2} ?\) (c) Which is the limiting reactant? (d) How many grams of CaO can be produced?

High-temperature superconducting oxides hold great promise in the utility, transportation, and computer industries. (a) One superconductor is \(\mathrm{La}_{2-x} \mathrm{Sr}_{x} \mathrm{CuO}_{4} .\) Calculate the molar masses of this oxide when \(x=0, x=1,\) and \(x=0.163\). (b) Another common superconducting oxide is made by heating a mixture of barium carbonate, copper(II) oxide, and yttrium(III) oxide, followed by further heating in \(\mathrm{O}_{2}\) : \(4 \mathrm{BaCO}_{3}(s)+6 \mathrm{CuO}(s)+\mathrm{Y}_{2} \mathrm{O}_{3}(s) \longrightarrow\) $$ \begin{array}{c} 2 \mathrm{YBa}_{2} \mathrm{Cu}_{3} \mathrm{O}_{6.5}(s)+4 \mathrm{CO}_{2}(g) \\\ 2 \mathrm{YBa}_{2} \mathrm{Cu}_{3} \mathrm{O}_{6.5}(s)+\frac{1}{2} \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{YBa}_{2} \mathrm{Cu}_{3} \mathrm{O}_{7}(s) \end{array} $$ When equal masses of the three reactants are heated, which reactant is limiting? (c) After the product in part (b) is removed, what is the mass \(\%\) of each reactant in the remaining solid mixture?

When powdered zinc is heated with sulfur, a violent reaction occurs, and zinc sulfide forms: $$ \mathrm{Zn}(s)+\mathrm{S}_{8}(s) \longrightarrow \mathrm{ZnS}(s)[\text { unbalanced }] $$ Some of the reactants also combine with oxygen in air to form zinc oxide and sulfur dioxide. When \(83.2 \mathrm{~g}\) of Zn reacts with \(52.4 \mathrm{~g}\) of \(\mathrm{S}_{8}\), \(104.4 \mathrm{~g}\) of \(\mathrm{ZnS}\) forms. (a) What is the percent yield of \(\mathrm{ZnS}\) ? (b) If all the remaining reactants combine with oxygen, how many grams of each of the two oxides form?

Propane is widely used in liquid form as a fuel for barbecue grills and camp stoves. For \(85.5 \mathrm{~g}\) of propane, calculate (a) moles of compound; (b) grams of carbon.

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