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Predict the sign of \(\Delta S\) for each process: (a) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(g)(350 \mathrm{~K}\) and 500 torr \() \longrightarrow\) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(g)(350 \mathrm{~K}\) and 250 torr \()\) (b) \(\mathrm{N}_{2}(g)(298 \mathrm{~K}\) and \(1 \mathrm{~atm}) \longrightarrow \mathrm{N}_{2}(a q)(298 \mathrm{~K}\) and \(1 \mathrm{~atm})\) (c) \(\mathrm{O}_{2}(a q)(303 \mathrm{~K}\) and \(1 \mathrm{~atm}) \longrightarrow \mathrm{O}_{2}(g)(303 \mathrm{~K}\) and \(1 \mathrm{~atm})\)

Short Answer

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(a) Positive, (b) Negative, (c) Positive.

Step by step solution

01

Process (a) Entropy Change

Analyze the process where \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(g)\) (ethanol vapor) at 350 K and 500 torr goes to ethanol vapor at 350 K and 250 torr. Since the temperature remains constant and the pressure decreases, the gas will expand. Expansion of a gas increases randomness or disorder, hence the entropy \(\Delta S\) will be positive.
02

Process (b) Entropy Change

Consider the process where \(\mathrm{N}_{2}(g)\) (nitrogen gas) at 298 K and 1 atm transitions to \(\mathrm{N}_{2}(a q)\) (aqueous nitrogen) at the same temperature and pressure. Dissolving a gas into a solvent generally decreases the entropy because the gas molecules are more constrained in the liquid phase than in the gas phase. Therefore, \(\Delta S\) will be negative for this process.
03

Process (c) Entropy Change

Examine the process where \(\mathrm{O}_{2}(a q)\) (aqueous oxygen) at 303 K and 1 atm goes to \(\mathrm{O}_{2}(g)\) (oxygen gas) at the same temperature and pressure. When a gas is released from an aqueous solution, the molecules go from a more ordered state to a less ordered state. Thus, the entropy \(\Delta S\) will be positive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entropy
Entropy is a measure of the randomness or disorder of a system. It is a fundamental concept in thermodynamics used to predict the spontaneity of chemical processes. When predicting the sign of \(\text{ΔS}\) for a chemical reaction, remember:
  • An increase in the number of gas molecules usually increases entropy.
  • Phase transitions from solid to liquid to gas increase entropy.
  • Dissolving a solid or liquid into solution usually increases entropy.
  • Dissolving a gas into a liquid usually decreases entropy.
For our examples: In process (a), the expansion of ethanol vapor increases entropy because gas molecules occupy a larger volume, increasing randomness. Hence, \(\text{ΔS} > 0\).
In process (b), dissolving nitrogen gas in water decreases entropy as the gas molecules become more ordered in the liquid phase. Therefore, \(\text{ΔS} < 0\).
In process (c), releasing oxygen gas from an aqueous solution increases entropy, as the gas phase is more disordered compared to the aqueous phase. Thus, \(\text{ΔS} > 0\).
Thermodynamics
Thermodynamics deals with energy changes and the equilibrium of systems. The second law of thermodynamics states that for any spontaneous process, the total entropy of a system and its surroundings always increases. This principle helps us determine whether a process will occur naturally:
  • Spontaneous processes generally increase the entropy of the universe.
  • Processes that increase the system's entropy are often favorable.
For example, in process (a), the gas expansion is spontaneous and increases system entropy. In contrast, process (b) is less favorable because dissolving nitrogen gas into water decreases system entropy. Process (c) is also spontaneous, as releasing gas molecules into the air increases the system's entropy.
Phase Transitions
Phase transitions involve changes between different states of matter (solid, liquid, gas). They are accompanied by changes in entropy:
  • Solid to liquid and liquid to gas transitions increase entropy.
  • Gas to liquid and liquid to solid transitions decrease entropy.
When analyzing entropy changes, examine the phase transition type:
In process (a), there is no phase transition (ethanol remains in gas form), but the expansion still increases entropy.
Process (b) features a phase-like transition from gas to liquid, reducing system entropy.
Process (c) involves a phase transition from aqueous (dissolved) form to gas, significantly increasing entropy as molecules move to a more disordered state.
Gas Expansion
Gas expansion occurs when gas molecules spread out to occupy a larger volume. This process always increases entropy due to the increase in disorder:
  • Lowering pressure allows gas to expand, increasing entropy.
  • At constant temperature, expanding gas means molecules have more accessible microstates.
In our specific exercise:
In process (a), decreasing pressure causes ethanol vapor to expand, resulting in greater randomness and higher entropy. This is a classic example of how gas expansion positively affects entropy values.
Dissolution of Gases
Dissolution involves dissolving a gas into a liquid, which generally decreases system entropy:
  • Gas molecules free in the air are more disordered compared to when dissolved in a liquid.
  • Dissolution confines gas molecules to a smaller volume, increasing order.
For instance, in process (b), \(\text{N}_2(g) \to \text{N}_2(aq)\), entropy decreases, indicating the gas molecules become more ordered in the aqueous state.
Conversely, in process (c), the dissolution process is reversed. When \(\text{O}_2(aq) \to \text{O}_2(g)\), entropy increases as the gas is released from the liquid, resulting in less order and greater randomness.

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Most popular questions from this chapter

State qualitatively the relationship between entropy and freedom of particle motion. Use this idea to explain why you will probably never (a) suffocate because all the air near you has moved to the other side of the room; (b) see half the water in your cup of tea freeze while the other half boils.

Without using Appendix B, predict the sign of \(\Delta S^{\circ}\) for (a) \(2 \mathrm{~K}(s)+\mathrm{F}_{2}(g) \longrightarrow 2 \mathrm{KF}(s)\) (b) \(\mathrm{NH}_{3}(g)+\mathrm{HBr}(g) \longrightarrow \mathrm{NH}_{4} \mathrm{Br}(s)\) (c) \(\mathrm{NaClO}_{3}(s) \longrightarrow \mathrm{Na}^{+}(a q)+\mathrm{ClO}_{3}^{-}(a q)\)

When heated, the DNA double helix separates into two random coil single strands. When cooled, the random coils re-form the double helix: double helix \(\Longrightarrow 2\) random coils. (a) What is the sign of \(\Delta S\) for the forward process? Why? (b) Energy must be added to break \(\mathrm{H}\) bonds and overcome dispersion forces between the strands. What is the sign of \(\Delta G\) for the forward process when \(T \Delta S\) is smaller than \(\Delta H ?\) (c) Write an expression for \(T\) in terms of \(\Delta H\) and \(\Delta S\) when the reaction is at equilibrium. (This temperature is called the melting temperature of the nucleic acid.)

Calculate \(\Delta G^{\circ}\) at \(298 \mathrm{~K}\) for each reaction: (a) \(\mathrm{CO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{COCl}_{2}(g) ; K=5.62 \times 10^{35}\) (b) \(\mathrm{H}_{2} \mathrm{SO}_{4}(l) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{SO}_{3}(g) ; K=4.46 \times 10^{-15}\)

The equilibrium constant for the reaction $$ 2 \mathrm{Fe}^{3+}(a q)+\mathrm{Hg}_{2}^{2+}(a q) \rightleftharpoons 2 \mathrm{Fe}^{2+}(a q)+2 \mathrm{Hg}^{2+}(a q) $$ is \(K_{c}=9.1 \times 10^{-6}\) at \(298 \mathrm{~K}\) (a) What is \(\Delta G^{\circ}\) at this temperature? (b) If standard-state concentrations of the reactants and products are mixed, in which direction does the reaction proceed? (c) Calculate \(\Delta G\) when \(\left[\mathrm{Fe}^{3+}\right]=0.20 M,\left[\mathrm{Hg}_{2}^{2+}\right]=0.010 \mathrm{M}\) \(\left[\mathrm{Fe}^{2+}\right]=0.010 \mathrm{M},\) and \(\left[\mathrm{Hg}^{2+}\right]=0.025 \mathrm{M} .\) In which direction will the reaction proceed to achieve equilibrium?

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