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Give the formulas of the compounds in each set: (a) Lead(II) oxide and lead(IV) oxide (b) Lithium nitride, lithium nitrite, and lithium nitrate (c) Strontium hydride and strontium hydroxide (d) Magnesium oxide and manganese(II) oxide

Short Answer

Expert verified
Lead(II) oxide: \( \text{PbO} \), Lead(IV) oxide: \( \text{PbO}_2 \). Lithium nitride: \( \text{Li}_3\text{N} \), Lithium nitrite: \( \text{LiNO}_2 \), Lithium nitrate: \( \text{LiNO}_3 \). Strontium hydride: \( \text{SrH}_2 \), Strontium hydroxide: \( \text{Sr(OH)}_2 \). Magnesium oxide: \( \text{MgO} \), Manganese(II) oxide: \( \text{MnO} \).

Step by step solution

01

Understand the problem

Identify the chemical compounds given in the problem for each set and find their chemical formulas.
02

Identify the elements and their oxidation states

Determine the elements involved in each compound and their respective oxidation states.
03

Write the formulas for Set (a)

Lead can have the oxidation state of +2 or +4. The formula for Lead(II) oxide is \( \text{PbO} \) and for Lead(IV) oxide is \( \text{PbO}_2 \).
04

Write the formulas for Set (b)

Lithium has an oxidation state of +1. The formulas are:\( \text{Li}_3\text{N} \) for Lithium nitride (combining Lithium and Nitrogen), \( \text{LiNO}_2 \) for Lithium nitrite (combining Lithium and the Nitrite ion, \( \text{NO}_2^- \)), \( \text{LiNO}_3 \) for Lithium nitrate (combining Lithium and the Nitrate ion, \( \text{NO}_3^- \)).
05

Write the formulas for Set (c)

Strontium has an oxidation state of +2. The formulas are:\( \text{SrH}_2 \) for Strontium hydride (combining Strontium and Hydrogen), \( \text{Sr(OH)}_2 \) for Strontium hydroxide (combining Strontium and the Hydroxide ion, \( \text{OH}^- \)).
06

Write the formulas for Set (d)

Magnesium has an oxidation state of +2. The formula for Magnesium oxide is \( \text{MgO} \). Manganese can have an oxidation state of +2. The formula for Manganese(II) oxide is \( \text{MnO} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Oxidation states, also known as oxidation numbers, are used to keep track of electron transfer in chemical reactions. These values represent the degree of oxidation of an atom in a compound. For example, in lead(II) oxide, the oxidation state of lead is +2, denoted as Pb(II). In lead(IV) oxide, the oxidation state is +4, shown as Pb(IV). Understanding oxidation states helps in determining the correct formula of a compound. For instance, lithium always has an oxidation state of +1 in compounds, leading to the formation of compounds like lithium nitride (Li3N), lithium nitrite (LiNO2), and lithium nitrate (LiNO3). Identifying and understanding oxidation states is a crucial step in writing and balancing chemical equations.
Chemical Nomenclature
Chemical nomenclature is the methodical naming of chemical compounds. There are rules established by IUPAC (International Union of Pure and Applied Chemistry) for naming compounds. For example, 'Lead(II) oxide' signifies a lead ion with a +2 charge combined with an oxide ion (O2-), resulting in the formula PbO. Similarly, 'Strontium hydride' (SrH2) indicates a compound made of strontium ions (Sr2+) and hydride ions (H-). Properly naming compounds ensures clear communication among scientists and helps in understanding the compound's composition and properties. For transition metals that have multiple possible oxidation states, Roman numerals in parentheses indicate the specific oxidation state of the metal, such as Manganese(II) oxide (MnO).
Compound Formulas
Chemical formulas represent the types and numbers of atoms in a molecule. They provide essential information about the composition of the compound. For instance, lead(II) oxide has a formula of PbO, showing one lead atom and one oxygen atom combining in a 1:1 ratio. In contrast, lead(IV) oxide's formula is PbO2, indicating one lead atom is combined with two oxygen atoms. Writing these formulas correctly requires knowledge of oxidation states and the ability to balance the charges. The formula for lithium nitrate is LiNO3, where one lithium ion (Li+) pairs with one nitrate ion (NO3-). Similarly, magnesium oxide (MgO) and manganese(II) oxide (MnO) illustrate simple, balanced expressions of elements and their combined states.
Transition Metals
Transition metals are elements found in groups 3-12 of the periodic table. They are notable for their ability to form multiple oxidation states and colorful compounds. For example, manganese can exhibit multiple oxidation states, including +2, +3, +4, +6, and +7, but in manganese(II) oxide, it has an oxidation state of +2, leading to the formula MnO. Transition metals often form complex ions and colored compounds, such as the bright colors observed in solutions of chromium or copper ions. These metals are also less reactive than alkali and alkaline earth metals, but they are crucial in many industrial and biological processes. Understanding transition metals' chemistry is essential in fields ranging from materials science to biochemistry.

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Most popular questions from this chapter

Which separation method is operating in each of the following procedures? (a) Pouring a mixture of cooked pasta and boiling water into a colander (b) Removing colored impurities from raw sugar to make refined sugar

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Before the use of systematic names, many compounds had common names. Give the systematic name for each of the following: (a) Blue vitriol, \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\) (b) Slaked lime, \(\mathrm{Ca}(\mathrm{OH})_{2}\) (c) Oil of vitriol, \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (d) Washing soda, \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) (e) Muriatic acid, HCl (f) Epsom salt, \(\mathrm{MgSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\)

Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe. (a) The radius of a helium atom is \(3.1 \times 10^{-11} \mathrm{~m} ;\) the radius of its nucleus is \(2.5 \times 10^{-15} \mathrm{~m} .\) What fraction of the spherical atomic volume is occupied by the nucleus ( \(V\) of a sphere \(\left.=\frac{4}{3} \pi r^{3}\right) ?\) (b) The mass of a helium-4 atom is \(6.64648 \times 10^{-24} \mathrm{~g}\), and each of its two electrons has a mass of \(9.10939 \times 10^{-28} \mathrm{~g}\). What fraction of this atom's mass is contributed by its nucleus?

Does the percent by mass of each element in a compound depend on the amount of that element used to make the compound? Explain.

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