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For what type(s) of compound do we use roman numerals in the names?

Short Answer

Expert verified
Roman numerals are used for transition metal compounds to indicate the metal's oxidation state.

Step by step solution

01

- Identify the Use of Roman Numerals

Roman numerals are used in the names of compounds where the metal involved can have more than one possible charge or oxidation state. These types of metals are typically transition metals.
02

- Define Transition Metals

Transition metals are elements that have partially filled d orbitals. These elements can form cations with different charges, leading to a need for clarification in their naming.
03

- Provide Examples

Examples of compounds that use roman numerals include iron (Fe), which can form iron (II) oxide (FeO) and iron (III) oxide (Fe₂O₃), and copper (Cu), which can form copper (I) chloride (CuCl) and copper (II) chloride (CuCl₂).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

transition metals
Transition metals are unique elements found in the center block of the periodic table. These metals are characterized by partially filled d orbitals in their atoms. This means they can form various cations (positively charged ions) with different charges. Transition metals include elements like iron (Fe), copper (Cu), and manganese (Mn). Due to their ability to switch between multiple oxidation states, naming compounds that include these metals requires special notation, typically using Roman numerals.
Examples:
  • Iron (Fe) can form Fe²⁺ and Fe³⁺ cations.
  • Copper (Cu) can form Cu⁺ and Cu²⁺ cations.

The use of Roman numerals in naming compounds helps to specify which oxidation state the metal is in. For example, iron (II) oxide (FeO) indicates iron with a 2+ charge, while iron (III) oxide (Fe₂O₃) indicates iron with a 3+ charge.
oxidation states
An oxidation state, also known as oxidation number, signifies the degree of oxidation of an atom in a chemical compound. It refers to the number of electrons an atom gains, loses, or shares when it forms chemical bonds. In transition metals, multiple oxidation states are common due to their ability to lose different numbers of d electrons.
Examples:
  • Iron can exist in +2 or +3 oxidation states.
  • Copper can exist in +1 or +2 oxidation states.

When naming compounds with metals that have variable oxidation states, it’s critical to indicate which oxidation state the metal is in. This is done using Roman numerals. For example, in copper (I) chloride (CuCl), copper has a +1 oxidation state, while in copper (II) chloride (CuCl₂), copper has a +2 oxidation state.
cation charges
Cation charges refer to the positive charge carried by cations, which are ions that have lost one or more electrons. In the context of transition metals, these positive charges can vary, leading to different cationic forms of the same metal. Understanding the cation charge is essential for correctly naming chemical compounds.
Examples:
  • Fe²⁺ (iron with a 2+ charge)
  • Fe³⁺ (iron with a 3+ charge)
  • Cu⁺ (copper with a 1+ charge)
  • Cu²⁺ (copper with a 2+ charge)

The charge of a cation is indicated by the Roman numeral in the name of the compound. For instance, iron (II) oxide indicates Fe²⁺, while iron (III) oxide indicates Fe³⁺. This system of using Roman numerals is crucial to avoid confusion, especially when dealing with metals that can form multiple cations with different charges.

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Most popular questions from this chapter

Fluoride ion is poisonous in relatively low amounts: \(0.2 \mathrm{~g}\) of \(\mathrm{F}^{-}\) per \(70 \mathrm{~kg}\) of body weight can cause death. Nevertheless, in order to prevent tooth decay, \(\mathrm{F}^{-}\) ions are added to drinking water at a concentration of \(1 \mathrm{mg}\) of \(\mathrm{F}^{-}\) ion per \(\mathrm{L}\) of water. How many liters of fluoridated drinking water would a \(70-\mathrm{kg}\) person have to consume in one day to reach this toxic level? How many kilograms of sodium fluoride would be needed to treat an \(8.50 \times 10^{7}\) gal reservoir?

Boron trifluoride is used as a catalyst in the synthesis of organic compounds. When this compound is analyzed by mass spectrometry, several different \(1+\) ions form, including ions representing the whole molecule as well as molecular fragments formed by the loss of one, two, and three \(\mathrm{F}\) atoms. Given that boron has two naturally occurring isotopes, \({ }^{10} \mathrm{~B}\) and \({ }^{11} \mathrm{~B},\) and fluorine has one, \({ }^{19} \mathrm{~F}\), calculate the masses of all possible \(1+\) ions.

You are working in the laboratory, preparing sodium chloride. Consider the following results for three preparations of the compound: Case \(1: 39.34 \mathrm{~g} \mathrm{Na}+60.66 \mathrm{~g} \mathrm{Cl}_{2} \longrightarrow 100.00 \mathrm{~g} \mathrm{NaCl}\) Case \(2: 39.34 \mathrm{~g} \mathrm{Na}+70.00 \mathrm{~g} \mathrm{Cl}_{2} \longrightarrow\) $$ 100.00 \mathrm{~g} \mathrm{NaCl}+9.34 \mathrm{~g} \mathrm{Cl}_{2} $$ Case \(3: 50.00 \mathrm{~g} \mathrm{Na}+50.00 \mathrm{~g} \mathrm{Cl}_{2} \longrightarrow\) $$ 82.43 \mathrm{~g} \mathrm{NaCl}+17.57 \mathrm{~g} \mathrm{Na} $$ Explain these results in terms of the laws of conservation of mass and definite composition.

Before the use of systematic names, many compounds had common names. Give the systematic name for each of the following: (a) Blue vitriol, \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\) (b) Slaked lime, \(\mathrm{Ca}(\mathrm{OH})_{2}\) (c) Oil of vitriol, \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (d) Washing soda, \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) (e) Muriatic acid, HCl (f) Epsom salt, \(\mathrm{MgSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\)

Thomson was able to determine the mass/charge ratio of the electron but not its mass. How did Millikan's experiment allow determination of the electron's mass?

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