Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Describe the type and nature of the bonding that occurs between reactive metals and nonmetals.

Short Answer

Expert verified
Reactive metals and nonmetals form ionic bonds through electron transfer, resulting in cations and anions held together by electrostatic attraction.

Step by step solution

01

Understanding Metal and Nonmetal Reactivity

Begin by recognizing that metals, particularly those in Group 1 and Group 2 of the periodic table, are highly reactive. Nonmetals, especially those in Group 17, are also highly reactive but in a different way. Metals tend to lose electrons, while nonmetals tend to gain electrons.
02

Electron Transfer

When a reactive metal comes into contact with a nonmetal, the metal atom will lose one or more of its outer electrons. These electrons are transferred to the nonmetal atom. This process results in the formation of ions: a positively charged metal ion (cation) and a negatively charged nonmetal ion (anion).
03

Formation of Ionic Bonds

As a result of this electron transfer, the metal and nonmetal form an ionic bond. An ionic bond is the electrostatic attraction between the positively charged cation and the negatively charged anion. This bond holds the ions together in a crystal lattice structure.
04

Nature of Ionic Compounds

Ionic compounds typically have high melting and boiling points due to the strong electrostatic forces between the ions. They conduct electricity when dissolved in water or melted because the ions are free to move and carry electric current.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reactive Metals
Metals, especially those in Group 1 (alkali metals) and Group 2 (alkaline earth metals) of the periodic table, are known as reactive metals. These metals are eager to lose electrons to achieve a stable electron configuration, similar to the nearest noble gas. This urge to lose electrons makes them highly reactive.
Examples of reactive metals include:
  • Sodium (Na)
  • Potassium (K)
  • Calcium (Ca)
  • Magnesium (Mg)
Due to their high reactivity, these metals are often found in compounds rather than in their pure elemental form in nature.
Nonmetals
In contrast to reactive metals, nonmetals, particularly those in Group 17 (halogens) of the periodic table, have a strong tendency to gain electrons. This behavior is driven by their desire to complete their outer electron shell, achieving a stable electron configuration.
Common nonmetals include:
  • Fluorine (F)
  • Chlorine (Cl)
  • Bromine (Br)
  • Iodine (I)
Unlike metals, nonmetals have high electronegativity, which means they attract electrons strongly. This ability makes them highly reactive, but in the opposite manner to metals.
Electrostatic Attraction
Electrostatic attraction is the force that holds ions together in an ionic bond. When a reactive metal and a nonmetal react, the metal loses electrons and becomes a positively charged ion, known as a cation.
The nonmetal, on the other hand, gains these electrons and becomes a negatively charged ion, called an anion.
  • Cations: Positive ions, e.g., Na+, Ca2+
  • Anions: Negative ions, e.g., Cl-, O2-
The oppositely charged ions attract each other due to electrostatic forces. This attraction is what forms the ionic bond, keeping the ions together.
Electron Transfer
The process of electron transfer is key to forming ionic bonds. When a reactive metal atom encounters a nonmetal atom, the metal atom tends to lose one or more electrons from its outer shell.
These electrons are then transferred to the nonmetal atom, leading to the formation of ions.
  • The reactive metal becomes a cation by losing electrons, e.g., Na → Na+ + e-
  • The nonmetal becomes an anion by gaining electrons, e.g., Cl + e- → Cl-
This transfer process is crucial in the formation of ionic compounds, as it enables the electrostatic attraction between the resultant ions.
Crystal Lattice Structure
In ionic compounds, ions arrange themselves in a repeating pattern known as a crystal lattice structure. This arrangement maximizes the attraction between oppositely charged ions (cations and anions) while minimizing repulsive forces.
The highly ordered structure gives ionic compounds several characteristic properties:
  • High melting and boiling points due to strong electrostatic forces
  • Brittleness, as shifting the arrangement can cause ions of like charges to repel each other
  • Electrical conductivity when melted or dissolved in water, as ions are free to move
This crystal lattice structure is what gives ionic compounds their distinctive physical properties.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Correct each of the following formulas: (a) Barium oxide is \(\mathrm{BaO}_{2}\). (b) Iron(II) nitrate is \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) (c) Magnesium sulfide is \(\mathrm{MnSO}_{3}\). (d) Potassium iodide is \(\mathrm{P}_{2} \mathrm{I}_{3}\).

How can ionic compounds be neutral if they consist of positive and negative ions?

Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe. (a) The radius of a helium atom is \(3.1 \times 10^{-11} \mathrm{~m} ;\) the radius of its nucleus is \(2.5 \times 10^{-15} \mathrm{~m} .\) What fraction of the spherical atomic volume is occupied by the nucleus ( \(V\) of a sphere \(\left.=\frac{4}{3} \pi r^{3}\right) ?\) (b) The mass of a helium-4 atom is \(6.64648 \times 10^{-24} \mathrm{~g}\), and each of its two electrons has a mass of \(9.10939 \times 10^{-28} \mathrm{~g}\). What fraction of this atom's mass is contributed by its nucleus?

Can the relative amounts of the components of a mixture vary? Can the relative amounts of the components of a compound vary? Explain.

Give the number of atoms of the specified element in a formula unit of each of the following compounds, and calculate the molecular (formula) mass: (a) Oxygen in aluminum sulfate, \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\) (b) Hydrogen in ammonium hydrogen phosphate, \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\) (c) Oxygen in the mineral azurite, \(\mathrm{Cu}_{3}(\mathrm{OH})_{2}\left(\mathrm{CO}_{3}\right)_{2}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free