Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) Does the percent by mass of each element in a compound depend on the amount of compound? Explain. (b) Does the mass of each element in a compound depend on the amount of compound? Explain.

Short Answer

Expert verified
a) No, percent by mass is independent of amount. b) Yes, mass of each element depends on the compound amount.

Step by step solution

01

Understanding Percent by Mass

Percent by mass of an element in a compound is calculated using the formula: \[ \text{Percent by mass} = \frac{\text{Mass of the element}}{\text{Total mass of the compound}} \times 100 \text{%} \] This is a ratio and depends on the proportion of the element's mass to the total mass of the compound.
02

Analyzing Dependence on Amount for Percent by Mass

The percent by mass is a ratio. Ratios are dimensionless and independent of the amount of material. Therefore, the percent by mass of each element in a compound does not change with varying amounts of the compound.
03

Understanding Mass of Each Element

The mass of each element in a given amount of compound can be found by multiplying the percent by mass by the total mass of the compound: \[ \text{Mass of the element} = \frac{\text{Percent by mass}}{100} \times \text{Total mass of the compound} \]
04

Analyzing Dependence on Amount for Mass of Each Element

The mass of each element directly depends on the total mass of the compound. If the amount of the compound increases, the total mass increases, and so does the mass of each element in the compound.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

mass of elements in compounds
In chemistry, the concept of mass of elements in compounds is foundational. Every compound is made up of elements, and the mass of each element within a compound can be calculated.
For example, if you have a compound like water (Hâ‚‚O), you would find that the mass of hydrogen and oxygen contributes to the total mass. The mass of the elements can be determined using their atomic masses from the periodic table and the number of each type of atom in the compound.

Consider the formula for calculating percent by mass: \(\text{Percent by mass} = \frac{\text{Mass of the element}}{\text{Total mass of the compound}} \times 100 \text{%} \). Using this, you can figure out what fraction of the total mass comes from each constituent element.
  • For water, the atomic mass of hydrogen is approximately 1 amu (atomic mass unit) each, and oxygen is about 16 amu.
  • Since water has two hydrogen atoms and one oxygen atom, the total mass is 2(1 amu) + 16 amu = 18 amu.
It shows how individual atoms contribute to the mass of the compound.
ratios in chemistry
Ratios are crucial in chemistry since they help compare quantities. When analyzing compounds, chemists often focus on the ratios between the masses of different elements.
For example, the percent by mass of an element in a compound is essentially a ratio. It tells you how much of the compound's mass comes from a particular element, relative to the entire mass of the compound.
  • This is always the same, no matter how much of the compound you have.
Hence, if you have a small or large sample of the compound, the percent by mass ratio remains unchanged.
Imagine breaking a chocolate bar in half. Each piece has the same ratio of the ingredients as the whole bar. Similarly, in a pure chemical compound, the ratio of the masses of its elements stays constant regardless of quantity.
It's crucial to remember ratios are dimensionless, which means they don't change just because you change the size of the sample.
dependence on amount
Understanding dependence on amount is key to mastering chemistry concepts. Let's see how it impacts the mass of elements in a compound.
The mass of each element in a compound changes with the amount of the compound you have.
  • If you double the amount of the compound, you double the mass of each element in it.
  • This is because the elements' masses are directly proportional to the total mass of the compound.
For instance, think of water again. If you have 18 grams of water, it contains approximately 2 grams of hydrogen and 16 grams of oxygen. If you now take 36 grams of water (double the amount), it will hence contain 4 grams of hydrogen and 32 grams of oxygen.
Here, the percent by mass remains constant, but the actual masses of the elements increase with the increase in total mass of the compound. This direct proportionality is an important concept to grasp when dealing with quantities in chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Magnesium oxide (MgO) forms when the metal burns in air. (a) If \(1.25 \mathrm{~g}\) of \(\mathrm{MgO}\) contains \(0.754 \mathrm{~g}\) of \(\mathrm{Mg}\), what is the mass ratio of magnesium to magnesium oxide? (b) How many grams of \(\mathrm{Mg}\) are in \(534 \mathrm{~g}\) of \(\mathrm{MgO}\) ?

When barium (Ba) reacts with sulfur (S) to form barium sulfide (BaS), each Ba atom reacts with an \(\mathrm{S}\) atom. If \(2.50 \mathrm{~cm}^{3}\) of Ba reacts with \(1.75 \mathrm{~cm}^{3}\) of \(\mathrm{S},\) are there enough \(\mathrm{Ba}\) atoms to react with the \(\mathrm{S}\) atoms \(\left(d\right.\) of \(\mathrm{Ba}=3.51 \mathrm{~g} / \mathrm{cm}^{3} ; d\) of \(\left.\mathrm{S}=2.07 \mathrm{~g} / \mathrm{cm}^{3}\right) ?\)

Give the name and formula of the compound formed from each pair of elements: (a) sodium and nitrogen; (b) oxygen and strontium; (c) aluminum and chlorine.

Many chemical names are similar at first glance. Give the formulas of the species in each set: (a) Ammonium ion and ammonia (b) Magnesium sulfide, magnesium sulfite, and magnesium sulfate (c) Hydrochloric acid, chloric acid, and chlorous acid (d) Cuprous bromide and cupric bromide

State the mass law(s) demonstrated by the following experimental results, and explain your reasoning: Experiment 1: A student heats \(1.00 \mathrm{~g}\) of a blue compound and obtains \(0.64 \mathrm{~g}\) of a white compound and \(0.36 \mathrm{~g}\) of a colorless gas. Experiment 2: A second student heats \(3.25 \mathrm{~g}\) of the same blue compound and obtains \(2.08 \mathrm{~g}\) of a white compound and \(1.17 \mathrm{~g}\) of a colorless gas.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free