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In humans, blood \(\mathrm{pH}\) is maintained within a narrow range: acidosis occurs if the blood \(\mathrm{pH}\) is below \(7.35,\) and alkalosis occurs if the \(\mathrm{pH}\) is above 7.45 . Given that the \(\mathrm{p} K_{\mathrm{w}}\) of blood is 13.63 at \(37^{\circ} \mathrm{C}\) (body temperature), what is the normal range of \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) and of \(\left[\mathrm{OH}^{-}\right]\) in blood?

Short Answer

Expert verified
Normal \( [\text{H}_3\text{O}^+] \) range: 3.55 to 4.47 \times 10^{-8} \text{M}, Normal \( [\text{OH}^-] \) range: 5.24 to 6.59 \times 10^{-7} \text{M}.

Step by step solution

01

- Identify the pH range for normal and abnormal conditions

Normal blood pH ranges from 7.35 to 7.45. Acidosis occurs when pH is below 7.35, and alkalosis occurs when pH is above 7.45.
02

- Define the relationship between pH and hydronium ion concentration \(\text{[}\text{H}_3\text{O}^+\text{]}\text{)}

The pH is defined by the equation \( \text{pH} = -\text{log}[\text{H}_3\text{O}^+] \). To find the concentration of \( [\text{H}_3\text{O}^+] \), use the formula \( [\text{H}_3\text{O}^+] = 10^{-\text{pH}} \).
03

- Calculate the concentration of \( [\text{H}_3\text{O}^+] \) for lower and upper pH limits

For pH = 7.35: \[ [\text{H}_3\text{O}^+] = 10^{-7.35} \approx 4.47 \times 10^{-8} \text{M} \] For pH = 7.45: \[ [\text{H}_3\text{O}^+] = 10^{-7.45} \approx 3.55 \times 10^{-8} \text{M} \]
04

- Determine the relationship between \( [\text{H}_3\text{O}^+] \) and \( [\text{OH}^-] \)

Use the ion product constant \( \text{K}_\text{w} \), defined by the equation \[ [\text{H}_3\text{O}^+][\text{OH}^-] = 10^{-\text{p}\text{K}_\text{w}} = 10^{-13.63} \] This simplifies to \text{K}_\text{w} = 2.34 \times 10^{-14} \text{M}^2 \.
05

- Calculate \( [\text{OH}^-] \) using the pH limits

For pH = 7.35: \ [\text{H}_3\text{O}^+] \times [\text{OH}^-] = \text{K}_\text{w} \ \( 4.47 \times 10^{-8} \text{M} \times [\text{OH}^-] = 2.34 \times 10^{-14} \text{M}^2 \) \[ [\text{OH}^-] \approx 5.24 \times 10^{-7} \text{M} \] For pH = 7.45: \ [\text{H}_3\text{O}^+] \times [\text{OH}^-] = \text{K}_\text{w} \ \( 3.55 \times 10^{-8} \text{M} \times [\text{OH}^-] = 2.34 \times 10^{-14} \text{M}^2 \) \[ [\text{OH}^-] \approx 6.59 \times 10^{-7} \text{M} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acidosis
Acidosis is a condition where the blood pH drops below the normal range.
Normal blood pH ranges from 7.35 to 7.45.
When blood becomes too acidic, dropping below 7.35, this condition is termed as acidosis.
Acidosis can occur due to various factors, including kidney failure, respiratory conditions, or metabolic issues.
It is important to monitor and manage this condition as it can lead to severe health issues if left unchecked.
Alkalosis
Alkalosis is the opposite of acidosis; it occurs when blood pH rises above 7.45.
If the blood becomes too alkaline, it is termed as alkalosis.
Possible causes include hyperventilation, certain medications, or metabolic conditions.
Like acidosis, alkalosis requires proper attention to prevent complications.
Hydronium Ion Concentration
Hydronium ion concentration \(\left[\text{H}_3\text{O}^+\right]\) is directly related to pH.
pH is defined by the formula \(\text{pH} = -\log{\left[\text{H}_3\text{O}^+\right]}\).
To find the hydronium ion concentration from pH, use: \(\left[\text{H}_3\text{O}^+\right] = 10^{-\text{pH}}\).
Normal blood pH results in \(\left[\text{H}_3\text{O}^+\right]\) between approximately \(4.47 \times 10^{-8}\) M (for pH 7.35) and \(3.55 \times 10^{-8}\) M (for pH 7.45).
Ion Product Constant
The ion product constant, denoted as \(K_w\), relates the concentrations of hydronium and hydroxide ions in water.
At 37°C, \(K_w\) for blood is given as \(10^{-13.63}\), or \(2.34 \times 10^{-14} \text{M}^2\).
This equation helps in determining the relationship between \(\left[\text{H}_3\text{O}^+\right]\) and \(\left[\text{OH}^-\right]\): \[\left[\text{H}_3\text{O}^+\right] \left[\text{OH}^-\right] = K_w\].
By knowing \(\left[\text{H}_3\text{O}^+\right]\), you can calculate \(\left[\text{OH}^-\right]\) and vice versa.
pH Calculation
To calculate pH, use the hydronium ion concentration formula.
The formula is \(\text{pH} = -\log{\left[\text{H}_3\text{O}^+\right]}\).
For normal blood, pH values range from 7.35 to 7.45.
You can convert these pH values to hydronium ion concentrations, \(4.47 \times 10^{-8} \text{M}\) for pH 7.35 and \(3.55 \times 10^{-8} \text{M}\) for pH 7.45.
These values are crucial for maintaining healthy bodily functions and ensuring optimal metabolic and physiological processes.

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Most popular questions from this chapter

Hemoglobin (Hb) transports oxygen in the blood: $$ \mathrm{HbH}^{+}(a q)+\mathrm{O}_{2}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{HbO}_{2}(a q)+\mathrm{H}_{3} \mathrm{O}^{+}(a q) $$ In blood, \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) is held nearly constant at \(4 \times 10^{-8} \mathrm{M}\) (a) How does the equilibrium position change in the lungs? (b) How does it change in \(\mathrm{O}_{2}\) -deficient cells? (c) Excessive vomiting may lead to metabolic alkalosis, in which \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) in blood decreases. How does this condition affect the ability of Hb to transport \(\mathrm{O}_{2} ?\) (d) Diabetes mellitus may lead to metabolic acidosis, in which \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) in blood increases. How does this condition affect the ability of Hb to transport \(\mathrm{O}_{2} ?\)

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The Group \(5 \mathrm{~A}(15)\) hydrides react with boron trihalides in a reversible Lewis acid-base reaction. When \(0.15 \mathrm{~mol}\) of \(\mathrm{PH}_{3} \mathrm{BCl}_{3}(s)\) is introduced into a \(3.0-\mathrm{L}\) container at a certain temperature, \(8.4 \times 10^{-3} \mathrm{~mol}\) of \(\mathrm{PH}_{3}\) is present at equilibrium: $$ \mathrm{PH}_{3} \mathrm{BCl}_{3}(s) \rightleftharpoons \mathrm{PH}_{3}(g)+\mathrm{BCl}_{3}(g) $$ (a) Find \(K_{c}\) for the reaction at this temperature. (b) Draw a Lewis structure for the reactant.

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