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Assuming acid strength relates directly to number of \(\mathrm{O}\) atoms bonded to the central atom, rank \(\mathrm{H}_{2} \mathrm{~N}_{2} \mathrm{O}_{2}\left[\mathrm{or}(\mathrm{HON})_{2}\right], \mathrm{HNO}_{3}\) (or HONO \(_{2}\) ), and \(\mathrm{HNO}_{2}\) (or HONO) in order of decreasing acid strength.

Short Answer

Expert verified
\text{HNO}_{3} > \text{HNO}_{2} > \text{H}_{2}\text{N}_{2}\text{O}_{2}.

Step by step solution

01

Identify the Central Atoms

Identify the central atom in each of the given acids: - \(\text{H}_{2}\text{N}_{2}\text{O}_{2}\) has nitrogen as the central atom \(\text{N}\).- \(\text{HNO}_{3}\) has nitrogen as the central atom \(\text{N}\).- \(\text{HNO}_{2}\) also has nitrogen as the central atom \(\text{N}\).
02

Count the Number of Oxygens

Count the number of oxygen atoms bonded to the central atom in each compound: - \(\text{H}_{2}\text{N}_{2}\text{O}_{2}\) has 2 oxygen atoms.- \(\text{HNO}_{3}\) has 3 oxygen atoms.- \(\text{HNO}_{2}\) has 2 oxygen atoms.
03

Rank the Acids

Since acid strength is directly related to the number of oxygen atoms, rank the acids in order of decreasing acid strength:1. \(\text{HNO}_{3}\) - 3 oxygens (strongest)2. \(\text{HNO}_{2}\) - 2 oxygens3. \(\text{H}_{2}\text{N}_{2}\text{O}_{2}\) - 2 oxygens (weakest)
04

Establish Final Ranking

Finalize the order of decreasing acid strength: \(\text{HNO}_{3}\) > \(\text{HNO}_{2}\) > \(\text{H}_{2}\text{N}_{2}\text{O}_{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Central Atom Identification
In any given compound, the central atom is the one to which all other atoms are bonded. Identifying the central atom is the first and crucial step in understanding the structure and behavior of a molecule.
In the exercise provided, we have three different acids: \(\text{H}_{2}\text{N}_{2}\text{O}_{2} \( \text{or}(\text{HON})_{2}\)\), \(\text{HNO}_{3} \( \text{or}\text{HONO}_{2}\)\), and \(\text{HNO}_{2} \( \text{or}\text{HONO}\)\). For each of these acids, the central atom is the one that forms bonds with oxygen atoms.
For example: \ - In \(\text{H}_{2}\text{N}_{2}\text{O}_{2}\), the central atom is nitrogen (N).
\ - In \(\text{HNO}_{3}\), the central atom is also nitrogen (N).
\ - In \(\text{HNO}_{2}\), the central atom remains nitrogen (N).
This identification is necessary to further analyze how the molecule interacts and to count the number of bonds with other atoms.
Number of Oxygen Atoms
The strength of an acid can often be determined by the number of oxygen atoms bonded to the central atom. This is because oxygen atoms are highly electronegative and can stabilize the negative charge that arises when the acid loses a proton \(\text{H}^{+}\).
By counting the oxygen atoms, we can get a good indication of the acid's strength. In our given examples:
\- \(\text{H}_{2}\text{N}_{2}\text{O}_{2}\) has 2 oxygen atoms.
\- \(\text{HNO}_{3}\) has 3 oxygen atoms.
\- \(\text{HNO}_{2}\) has 2 oxygen atoms.
From this analysis, \(\text{HNO}_{3}\) has the highest number of oxygen atoms bonded to its central atom, indicating it potentially has the highest acid strength.
Ranking Acids by Strength
Once we've identified the central atom and counted the number of oxygen atoms, we can rank the acids by their strength. The general rule is: the more oxygen atoms bonded to the central atom, the stronger the acid.
In our examples, we see:
\- \(\text{HNO}_{3}\) with 3 oxygens is the strongest.
\- \(\text{HNO}_{2}\) with 2 oxygens is next.
\- \(\text{H}_{2}\text{N}_{2}\text{O}_{2}\) with 2 oxygens is the weakest among the given acids.
Even though \(\text{HNO}_{2}\) and \(\text{H}_{2}\text{N}_{2}\text{O}_{2}\) both have 2 oxygen atoms, \(\text{HNO}_{2}\) is typically considered stronger than \(\text{H}_{2}\text{N}_{2}\text{O}_{2}\) due to the specific arrangement and bonding of atoms which influences the molecule's overall stability when it loses a proton.

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Most popular questions from this chapter

The oxygen and nitrogen families have some obvious similarities and differences. (a) State two general physical similarities between Group \(5 \mathrm{~A}(15)\) and \(6 \mathrm{~A}(16)\) elements. (b) State two general chemical similarities between Group \(5 \mathrm{~A}(15)\) and \(6 \mathrm{~A}(16)\) elements. (c) State two chemical similarities between \(\mathrm{P}\) and \(\mathrm{S}\). (d) State two physical similarities between \(\mathrm{N}\) and \(\mathrm{O}\). (e) State two chemical differences between \(\mathrm{N}\) and \(\mathrm{O}\).

The melting points of alkaline earth metals are many times higher than those of the alkali metals. Explain this difference on the basis of atomic properties. Name three other physical properties for which Group \(2 \mathrm{~A}(2)\) metals have higher values than the corresponding \(1 \mathrm{~A}(1)\) metals.

The bond angles in the nitrite ion, nitrogen dioxide, and the nitronium ion \(\left(\mathrm{NO}_{2}^{+}\right)\) are \(115^{\circ}, 134^{\circ},\) and \(180^{\circ},\) respectively. Explain these values using Lewis structures and VSEPR theory.

From its formula, one might expect \(\mathrm{CO}\) to be quite polar, but its dipole moment is actually small \((0.11 \mathrm{D})\). (a) Draw the Lewis structure for CO. (b) Calculate the formal charges. (c) Based on your answers to parts (a) and (b), explain why the dipole moment is so small.

Selenium tetrafluoride reacts with fluorine to form selenium hexafluoride. (a) Draw Lewis structures for both selenium fluorides, and predict any deviations from ideal bond angles. (b) Describe the change in orbital hybridization of the central Se during the reaction.

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