Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write a balanced equation for the formation from its elements of sodium peroxide, an industrial bleach.

Short Answer

Expert verified
2 Na + O2 -> Na2O2

Step by step solution

01

- Identify the Elements

First, identify the elements involved in the formation of sodium peroxide. Sodium peroxide (Na2O2) is made from sodium (Na) and oxygen (O2).
02

- Write the Unbalanced Equation

Write the unbalanced chemical equation using the identified elements:Na + O2 -> Na2O2
03

- Balance Sodium Atoms

There are 2 sodium atoms in Na2O2 and 1 sodium atom on the reactants' side. To balance the sodium atoms, place a coefficient of 2 in front of Na:2 Na + O2 -> Na2O2
04

- Confirm Balanced Equation

Verify all elements are balanced. There are 2 Na atoms and 2 O atoms on both sides of the equation, indicating it is balanced.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

chemical reactions
In chemical reactions, substances known as reactants are transformed into new substances called products. This transformation involves breaking and forming chemical bonds.

For example, let's consider our exercise: forming sodium peroxide (Na2O2). The reactants are sodium (Na) and oxygen (O2), and the product is sodium peroxide (Na2O2). When sodium reacts with oxygen, their atoms rearrange to form the sodium peroxide compounds.

Here is the unbalanced chemical equation: Na + O2 -> Na2O2.

During this reaction, each sodium atom must pair with oxygen atoms in the correct proportions. This way, we can form a stable product. Such reactions are foundational to industrial chemistry, where creating specific compounds consistently and safely is essential.
stoichiometry
Stoichiometry is the quantitative study of reactants and products in a chemical reaction. It helps determine the proportions of elements in a reaction to ensure the equation is balanced.

To understand stoichiometry, consider this balanced equation for forming sodium peroxide: 2 Na + O2 -> Na2O2.

This equation tells us that two sodium atoms react with one oxygen molecule to form one molecule of sodium peroxide. The coefficients (the numbers before the chemical symbols) show the ratio of molecules or atoms involved in the reaction. It ensures mass conservation according to the Law of Conservation of Mass.

Without proper stoichiometry, we could end up with unreacted leftovers or incomplete reactions, which is not efficient for any industrial process. Being precise with the amount of each reactant used ensures that the desired product is created without waste.
industrial chemistry
Industrial chemistry focuses on manufacturing chemical products on a large scale. It's essential for producing materials like paints, pharmaceuticals, and bleaches like sodium peroxide.

In our example, sodium peroxide (Na2O2) is produced by carefully measuring reactants and applying the balanced chemical equation: 2 Na + O2 -> Na2O2.

For industrial purposes, controlling the reaction conditions such as temperature and pressure is vital to maximize yield and purity of the product.

Sodium peroxide is an effective bleach because it releases oxygen upon contact with water, breaking down stains through oxidation. Industrial chemists need to understand these chemical principles to ensure the bleach is effective and safe for use.

Thus, a deep understanding of chemical reactions and stoichiometry is crucial in industrial chemistry to create high-quality, reliable products on a large scale.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Give the name and symbol or formula of a Group \(6 \mathrm{~A}(16)\) element or compound that fits each description or use: (a) Unstable allotrope of oxygen (b) Oxide having sulfur with the same O.N. as in sulfuric acid (c) Air pollutant produced by burning sulfur-containing coal (d) Powerful dehydrating agent (e) Compound used in solution in the photographic process

Indium (In) reacts with \(\mathrm{HCl}\) to form a diamagnetic solid with the formula \(\ln \mathrm{Cl}_{2}\). (a) Write condensed electron configurations for \(\mathrm{In}, \mathrm{In}^{+}, \mathrm{In}^{2+}\) and \(\mathrm{In}^{3+}\) (b) Which of these species is (are) diamagnetic and which paramagnetic? (c) What is the apparent oxidation state of In in \(\mathrm{InCl}_{2}\) ? (d) Given your answers to parts (b) and (c), explain how \(\mathrm{InCl}_{2}\) can be diamagnetic.

(a) What is the range of oxidation states shown by the elements of Group \(5 \mathrm{~A}(15)\) as you move down the group? (b) How does this range illustrate the general rule for the range of oxidation states in groups on the right side of the periodic table?

The melting points of alkaline earth metals are many times higher than those of the alkali metals. Explain this difference on the basis of atomic properties. Name three other physical properties for which Group \(2 \mathrm{~A}(2)\) metals have higher values than the corresponding \(1 \mathrm{~A}(1)\) metals.

Rank the following acids in order of decreasing acid strength: \(\mathrm{HBrO}_{3}, \mathrm{HBrO}_{4}, \mathrm{HIO}_{3}, \mathrm{HClO}_{4-}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free