Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Lithium salts are often much less soluble in water than the corresponding salts of other alkali metals. For example, at \(18^{\circ} \mathrm{C}\). the concentration of a saturated LiF solution is \(1.0 \times 10^{-2} \mathrm{M}\) whereas that of a saturated KF solution is \(1.6 M .\) How can you explain this behavior?

Short Answer

Expert verified
LiF is less soluble due to its higher lattice energy compared to KF, even though both have favorable solvation energies.

Step by step solution

01

Understand the Problem

Lithium salts like LiF are much less soluble in water compared to salts of other alkali metals, such as KF. The given concentrations of saturated solutions are 1.0 x 10^{-2} M for LiF and 1.6 M for KF.
02

Analyze Lattice Energy

Consider the lattice energy, which is the energy required to separate the ions in an ionic solid. Lithium ions (Li+) are smaller in size compared to potassium ions (K+), which means the lattice energy of LiF is higher than that of KF.
03

Solvation Energy

Think about the solvation energy, which is the energy released when ions are solvated by water molecules. Smaller ions like Li+ also have higher solvation energy when compared to larger ions like K+.
04

Compare Lattice and Solvation Energies

The solubility of an ionic compound in water depends on the competition between lattice energy and solvation energy. Despite the higher solvation energy for smaller ions, the much higher lattice energy of LiF (because Li+ is very small) limits its solubility. For KF, the lower lattice energy relative to its solvation energy makes it more soluble.
05

Conclusion

Thus, the higher lattice energy of LiF compared to KF results in its much lower solubility despite the favorable solvation energy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lattice Energy
Lattice energy is a crucial factor influencing the solubility of ionic compounds. It is the energy released when oppositely charged ions in the gas phase come together to form an ionic solid. Smaller ions tend to release more energy when they form a lattice, which means their lattice energy is higher.

For lithium salts like LiF, the lithium ion (Li+) is much smaller compared to a potassium ion (K+). This small size leads to a high lattice energy because the ions can pack closely together, increasing the attraction between them.

High lattice energy makes it harder for the ionic compound to dissolve because more energy is required to break apart the solid crystal lattice into individual ions.

Solvation Energy
Solvation energy is the energy released when ions from an ionic compound are surrounded by solvent molecules, in this case, water.

Generally, smaller ions like Li+ exhibit higher solvation energies because they are more attracted to the polar water molecules. This attraction results in the release of more energy when they are solvated. For example, Li+'s smaller size allows it to interact more closely with the water molecules, enhancing the solvation process.

Despite the higher solvation energy, in some cases, this is not sufficient to overcome the lattice energy, affecting the ionic compound's overall solubility.

Ionic Compounds Solubility
The solubility of ionic compounds in water is a balancing act between lattice energy and solvation energy.

For salts like LiF, the high lattice energy due to the small size of Li+ ions means that a lot of energy is required to disrupt the solid structure. Even though Li+ ions have a high solvation energy, it often isn't enough to overcome the large lattice energy, leading to lower solubility.

Conversely, in salts like KF, K+ ions are larger, resulting in lower lattice energy. The energy required to separate K+ and F ions is less, and although the solvation energy of K+ is lower compared to Li+, it is adequate to dissolve more KF in water.

In summary, the solubility of ionic compounds is determined by the relative magnitudes of lattice energy and solvation energy.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two substances with the empirical formula HNO are hyponitrous acid \((\mathscr{A}=62.04 \mathrm{~g} / \mathrm{mol})\) and nitroxyl \((\mathscr{A}=31.02 \mathrm{~g} / \mathrm{mol}) .\) (a) What is the molecular formula of each species? (b) For each species, draw the Lewis structure having the lowest formal charges. (Hint: Hyponitrous acid has an \(\mathrm{N}=\mathrm{N}\) bond. \()\) (c) Predict the shape around the \(\mathrm{N}\) atoms of each species. (d) When hyponitrous acid loses two protons, it forms the hyponitrite ion. Draw cis and trans forms of this ion.

From its formula, one might expect \(\mathrm{CO}\) to be quite polar, but its dipole moment is actually small \((0.11 \mathrm{D})\). (a) Draw the Lewis structure for CO. (b) Calculate the formal charges. (c) Based on your answers to parts (a) and (b), explain why the dipole moment is so small.

Nitrous oxide \(\left(\mathrm{N}_{2} \mathrm{O}\right),\) the "laughing gas" used as an anesthetic by dentists, is made by thermal decomposition of solid \(\mathrm{NH}_{4} \mathrm{NO}_{3}\). Write a balanced equation for this reaction. What are the oxidation states of \(\mathrm{N}\) in \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) and in \(\mathrm{N}_{2} \mathrm{O} ?\)

Compounds such as \(\mathrm{NaBH}_{4}, \mathrm{Al}\left(\mathrm{BH}_{4}\right)_{3},\) and \(\mathrm{LiAlH}_{4}\) are com- plex hydrides used as reducing agents in many syntheses. (a) Give the oxidation state of each element in these compounds. (b) Write a Lewis structure for the polyatomic anion in \(\mathrm{NaBH}_{4}\), and predict its shape.

The melting points of alkaline earth metals are many times higher than those of the alkali metals. Explain this difference on the basis of atomic properties. Name three other physical properties for which Group \(2 \mathrm{~A}(2)\) metals have higher values than the corresponding \(1 \mathrm{~A}(1)\) metals.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free