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The triatomic molecular ion \(\mathrm{H}_{3}^{+}\) was first detected and characterized by J. J. Thomson using mass spectrometry. Use the bond energy of \(\mathrm{H}_{2}(432 \mathrm{~kJ} / \mathrm{mol})\) and the proton affinity of \(\mathrm{H}_{2}\left(\mathrm{H}_{2}+\mathrm{H}^{+} \longrightarrow \mathrm{H}_{3}^{+} ; \Delta H=-337 \mathrm{~kJ} / \mathrm{mol}\right)\) to calculate the en thalpy of reaction for \(\mathrm{H}+\mathrm{H}+\mathrm{H}^{+} \longrightarrow \mathrm{H}_{3}^{+}\)

Short Answer

Expert verified
The enthalpy of the reaction is 95 kJ/mol.

Step by step solution

01

- Understand the Information Given

We are given the bond energy of \(\text{H}_2 \) as 432 kJ/mol, and the enthalpy change for the reaction \( \text{H}_2 + \text{H}^+ \rightarrow \text{H}_3^+ \) as -337 kJ/mol. These values will be used to calculate the enthalpy of the target reaction \( \text{H} + \text{H} + \text{H}^+ \rightarrow \text{H}_3^+ \).
02

- Determine the Energy Required to Break One Molecule of \(\text{H}_2\)

To break one molecule of \(\text{H}_2\), 432 kJ/mol of energy is required. This represents the energy needed to split \(\text{H}_2\) into two hydrogen atoms.
03

- Calculate the Energy Change for Producing \(\text{H} + \text{H}\)

Divide the bond energy of \(\text{H}_2\) by 2 since breaking one \( \text{H}_2\) molecule gives two hydrogen atoms: \(\frac{432 \text{ kJ}}{2} = 216 \text{ kJ}\) per hydrogen atom.
04

- Combine Two \(\text{H}\) Atoms and One Proton

Now form \(\text{H}_2\) from two H atoms, which releases -432 kJ/mol. Then add \(\text{H}^+\) (proton) to \(\text{H}_2\) to form \(\text{H}_3^+\) with an enthalpy change of -337 kJ/mol.
05

- Calculate Total Enthalpy Change

Combine the energy values: \( \text{Energy required to break one \(\text{H}_2\)} + \text{Enthalpy change to form \(\text{H}_3^+\)} = 432 \text{ kJ} - 337 \text{ kJ} = 95 \text{ kJ} \).
06

- Final Verification

Add the energies: \( 216 \text{ kJ} (to break \(\text{H}_2\)) + (-337 \text{ kJ} (to add \(\text{H}^+\) to \(\text{H}_2\)) = 95 \text{ kJ} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bond Energy
Bond energy is the measure of the amount of energy required to break a chemical bond between atoms in a molecule. For example, the bond energy of \(H_2\) is 432 kJ/mol. This means that it takes 432 kJ to break one mole of hydrogen molecules (\text{H}_2\text\text) into individual hydrogen atoms (H).

In the exercise, we need to consider this bond energy to understand how much energy is required to break \(H_2\) into two H atoms. This is crucial for further calculations, as it sets the stage to determine the total energy change involved in forming \(H_3^+\) from \(H + H + H^+\).
Proton Affinity
Proton affinity refers to the energy change when a proton (\text{H}^+\text) is added to a molecule. In simpler terms, it’s a measure of how strongly a molecule attracts a proton. For \(H_2\), the proton affinity is represented by the enthalpy change of the reaction: \(H_2 + H^+ \rightarrow H_3^+\).

The problem states that the proton affinity of \(H_2\) is \(-337 kJ/mol\), meaning when a proton is added to \(H_2\), energy is released. This negative value indicates an exothermic reaction, where energy is given off.

In our exercise, this information helps us understand the energy change when \(H_2\) combines with \(H^+\) to form \(H_3^+\). This value is crucial for calculating the overall enthalpy change.
Mass Spectrometry
Mass spectrometry is an analytical technique used to measure the mass-to-charge ratio of ions. It's a powerful tool in detecting and characterizing molecules and ions. The instrument produces ions from the sample and sorts them based on their mass-to-charge ratios to produce signals for analysis.

J. J. Thomson used mass spectrometry to first detect \(H_3^+\), the triatomic molecular ion. Detection through mass spectrometry confirmed the existence of \(H_3^+\), providing insights into its formation and stability. This technique supports our understanding of the formation of \(H_3^+\) and helps in calculating the enthalpy change by analyzing the ions involved.
Enthalpy Change
Enthalpy change (∆H) is the difference in heat content between reactants and products in a chemical reaction at constant pressure. It is a crucial concept in understanding reaction energetics.

If ∆H is negative, the reaction is exothermic (releases heat), whereas if it’s positive, the reaction is endothermic (absorbs heat).

To calculate the enthalpy change for the formation of \H_3^+\ from \(H + H + H^+\), we consider the bond energy of \(H_2\) and the proton affinity of \(H_2\), as outlined in the steps.

For instance, we first determine the energy needed to break \(H_2\) (432 kJ/mol), and then the energy change when adding \(H^+\) to \(H_2\) (-337 kJ/mol). Combining these values gives the total enthalpy change, helping us understand the energy dynamics of the reaction.

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Most popular questions from this chapter

Compounds such as \(\mathrm{NaBH}_{4}, \mathrm{Al}\left(\mathrm{BH}_{4}\right)_{3},\) and \(\mathrm{LiAlH}_{4}\) are com- plex hydrides used as reducing agents in many syntheses. (a) Give the oxidation state of each element in these compounds. (b) Write a Lewis structure for the polyatomic anion in \(\mathrm{NaBH}_{4}\), and predict its shape.

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