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Suppose coal-fired power plants used water in scrubbers to remove \(\mathrm{SO}_{2}\) from smokestack gases (see Chemical Connections, Section 6.6). (a) If the partial pressure of \(\mathrm{SO}_{2}\) in the stack gases is \(2.0 \times 10^{-3} \mathrm{~atm},\) what is the solubility of \(\mathrm{SO}_{2}\) in the scrubber liquid \(\left(k_{\mathrm{H}}\right.\) for \(\mathrm{SO}_{2}\) in water is \(1.23 \mathrm{~mol} / \mathrm{L} \cdot\) atm at \(\left.200 .{ }^{\circ} \mathrm{C}\right) ?\) (b) From your answer to part (a), why are basic solutions, such as limewater slurries \(\left[\mathrm{Ca}(\mathrm{OH})_{2}\right],\) used in scrubbers?

Short Answer

Expert verified
Solubility is \2.46 \times 10^{-3}\ mol/L. Basic solutions remove \(\text{SO}_2\) to maintain low concentration.

Step by step solution

01

- Identify Known Variables

Given data includes the partial pressure of \(\text{SO}_2\), which is \(2.0 \times 10^{-3}\) atm, and the Henry's law constant, \k_{\text{H}}\ for \(\text{SO}_2\) in water, which is \(1.23 \text{ mol/L} \cdot \text{ atm}\).
02

- Apply Henry's Law to Find Solubility

Use Henry's law to find the solubility of \(\text{SO}_2\) in water. Henry's Law is given by \C = k_{\text{H}} \cdot P_{\text{gas}}\, where \C\ is the concentration (solubility) of the gas, \k_{\text{H}}\ is the Henry's law constant, and \P_{\text{gas}}\ is the partial pressure of the gas. Plug in the values: \[ C = (1.23 \text{ mol} / \text{L} \cdot \text{ atm}) \cdot (2.0 \times 10^{-3} \text{ atm}) = 2.46 \times 10^{-3} \text{ mol/L} \]
03

- Understand the Role of Limewater Slurries

Limewater slurries \[ \text{Ca(OH)}_2 \] are used in scrubbers because they are basic solutions that react with \( \text{SO}_2 \) to form solid calcium sulfite \[ \text{CaSO}_3 \]. This reaction removes \( \text{SO}_2 \) from the water, maintaining its low concentration and allowing more \( \text{SO}_2 \) to dissolve.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Henry's Law
Henry's Law explains the relationship between the partial pressure of a gas and its solubility in a liquid. This law can be expressed with the formula: \[ C = k_{\text{H}} \times P_{\text{gas}} \] where \( C \) is the solubility (concentration) of the gas in the liquid, \( k_{\text{H}} \) is the Henry's law constant, and \( P_{\text{gas}} \) is the partial pressure of the gas. In the given exercise, we used Henry’s Law to determine the solubility of \( \text{SO}_2 \) in water. With \( k_{\text{H}} = 1.23 \text{ mol/L} \times \text{ atm} \) and \( P_{\text{gas}} = 2.0 \times 10^{-3} \text{ atm} \), we calculated the solubility as: \[ C = (1.23 \text{ mol/L} \times \text{ atm}) \times (2.0 \times 10^{-3} \text{ atm}) = 2.46 \times 10^{-3} \text{ mol/L} \] This means that under a partial pressure of \( 2.0 \times 10^{-3} \text{ atm} \), \( \text{SO}_2 \) will dissolve in water to a concentration of \( 2.46 \times 10^{-3} \text{ mol/L} \).
Partial Pressure
The partial pressure of a gas is the pressure it would exert if it alone occupied the entire volume of the mixture. It is a crucial factor in determining the solubility of gases in liquids through Henry's Law. In our exercise, the partial pressure of \( \text{SO}_2 \) in the smokestack gases was given as \( 2.0 \times 10^{-3} \text{ atm} \). This value is relatively low, indicating that only a small amount of \( \text{SO}_2 \) is present in the mixture of gases coming from the power plant. By knowing the partial pressure, we can use Henry's Law to find the solubility of \( \text{SO}_2 \) in water, as we calculated earlier.
Limewater Slurries
Limewater slurries are basic solutions made from calcium hydroxide \( \text{Ca(OH)}_2 \). They are used in scrubbers to remove \( \text{SO}_2 \) from smokestack gases. The basicity of limewater slurries plays a crucial role in this process. When \( \text{SO}_2 \) dissolves in water, it forms sulfurous acid \( \text{H}_2\text{SO}_3 \), which is acidic. The basic limewater reacts with this acid to form calcium sulfite \( \text{CaSO}_3 \), a solid compound: \[ \text{Ca(OH)}_2 + \text{SO}_2 \rightarrow \text{CaSO}_3 + \text{H}_2\text{O} \] This reaction removes \( \text{SO}_2 \) from the water, keeping the concentration of \( \text{SO}_2 \) low. As a result, it allows more \( \text{SO}_2 \) to dissolve, effectively cleaning the smokestack gases. Limewater slurries are efficient in reducing \( \text{SO}_2 \) emissions from power plants, protecting the environment from sulfur dioxide pollution.

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Most popular questions from this chapter

A pharmaceutical preparation made with ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) is contaminated with methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right) .\) A sample of vapor above the liquid mixture contains a \(97 / 1\) mass ratio of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) to \(\mathrm{CH}_{3} \mathrm{OH}\). What is the mass ratio of these alcohols in the liquid mixture? At the temperature of the liquid mixture, the vapor pressures of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) and \(\mathrm{CH}_{3} \mathrm{OH}\) are 60.5 torr and 126.0 torr, respectively.

Besides being used in black-and-white film, silver nitrate \(\left(\mathrm{AgNO}_{3}\right)\) is used similarly in forensic science. The \(\mathrm{NaCl}\) left behind in the sweat of a fingerprint is treated with \(\mathrm{AgNO}_{3}\) solution to form \(\mathrm{AgCl}\). This precipitate is developed to show the black-andwhite fingerprint pattern. Given that \(\Delta H_{\text {lattice }}=822 \mathrm{~kJ} / \mathrm{mol}\) and \(\Delta H_{\text {hydr }}=-799 \mathrm{~kJ} / \mathrm{mol}\) for \(\mathrm{AgNO}_{3},\) calculate its \(\Delta H_{\text {soln }}\).

Which ion in each pair has greater charge density? Explain. (a) \(\mathrm{Na}^{+}\) or \(\mathrm{Cs}^{+}\) (b) \(\mathrm{Sr}^{2+}\) or \(\mathrm{Rb}^{+}\) (c) \(\mathrm{Na}^{+}\) or \(\mathrm{Cl}^{-}\) (d) \(\mathrm{O}^{2-}\) or \(\mathrm{F}^{-}\) (e) \(\mathrm{OH}^{-}\) or \(\mathrm{SH}^{-}\) (f) \(\mathrm{Mg}^{2+}\) or \(\mathrm{Ba}^{2+}\) (g) \(\mathrm{Mg}^{2+}\) or \(\mathrm{Na}^{+}\) (h) \(\mathrm{NO}_{3}^{-}\) or \(\mathrm{CO}_{3}^{2-}\)

The release of volatile organic compounds into the atmosphere is regulated to limit ozone formation. In a laboratory simulation, \(5 \%\) of the ethanol in a liquid detergent is released. Thus, a "down-the-drain" factor of 0.05 is used to estimate ethanol emissions from the detergent. The \(k_{\mathrm{H}}\) values for ethanol and 2-butoxyethanol \(\left(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{OCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) are \(5 \times 10^{-6} \mathrm{~atm} \cdot \mathrm{m}^{3} / \mathrm{mol}\) and \(1.6 \times 10^{-6} \mathrm{~atm} \cdot \mathrm{m}^{3} / \mathrm{mol}\), respectively. (a) Estimate a "down-the-drain" factor for 2 -butoxyethanol in the detergent. (b) What is the \(k_{\mathrm{H}}\) for ethanol in units of \(\mathrm{L} \cdot \mathrm{atm} / \mathrm{mol} ?\) (c) Is the value found in part (b) consistent with a value given as \(0.64 \mathrm{~Pa} \cdot \mathrm{m}^{3} / \mathrm{mol} ?\)

Calculate the molarity of each aqueous solution: (a) \(32.3 \mathrm{~g}\) of table sugar \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\) in \(100 . \mathrm{mL}\) of solution (b) \(5.80 \mathrm{~g}\) of \(\mathrm{LiNO}_{3}\) in \(505 \mathrm{~mL}\) of solution

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