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Which of these atoms cannot serve as a central atom in a Lewis structure: (a) \(\mathrm{O} ;\) (b) \(\mathrm{He} ;\) (c) \(\mathrm{F} ;\) (d) \(\mathrm{H} ;\) (e) \(\mathrm{P}\) ? Explain.

Short Answer

Expert verified
(b) Helium (He), (c) Fluorine (F), and (d) Hydrogen (H) cannot serve as central atoms.

Step by step solution

01

- Understand the concept of a central atom

A central atom in a Lewis structure is typically the atom that can form the most bonds. This atom is usually the least electronegative (other than hydrogen) and has available orbitals to accommodate bonding pairs of electrons.
02

- Analyze each atom's ability to form bonds

Evaluate the valence electrons and bonding capabilities for each atom:(a) Oxygen (O): Oxygen has 6 valence electrons and can form up to 2 bonds.(b) Helium (He): Helium has 2 valence electrons and is a noble gas with a full valence shell, so it doesn't form bonds. (c) Fluorine (F): Fluorine has 7 valence electrons and can form only 1 bond. (d) Hydrogen (H): Hydrogen has 1 valence electron and can only form 1 bond. (e) Phosphorus (P): Phosphorus has 5 valence electrons and can form up to 5 bonds.
03

- Determine which atoms cannot serve as central atoms

From the analysis in Step 2, identify the atoms that cannot serve as central atoms because they either do not form bonds or can form only one bond. These atoms are Helium (He), Fluorine (F), and Hydrogen (H).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Valence Electrons
Valence electrons are the electrons in the outermost shell of an atom. These electrons play a crucial role in chemical bonding. Atoms with a full valence shell are generally stable and less likely to participate in bonding.

For instance, helium (He) has 2 valence electrons and a full outer shell, making it stable and unlikely to form bonds. Most other elements, however, seek to fill or empty their valence shell by forming bonds with other atoms. This concept is essential in understanding why certain atoms can or cannot be central atoms in a Lewis structure. Central atoms tend to have more room in their valence shell to accommodate multiple bonds.
Bonding Capabilities
Bonding capability refers to an atom's ability to form chemical bonds with other atoms. This ability is largely determined by the number of valence electrons an atom has. Atoms with fewer than four valence electrons often lose electrons to form positive ions, while those with more than four valence electrons tend to gain electrons to form negative ions.

For example:
  • Hydrogen (H) has 1 valence electron and can form only one bond.
  • Oxygen (O), with 6 valence electrons, can form two bonds.
  • Phosphorus (P), with 5 valence electrons, can form up to five bonds.
The central atom in a Lewis structure is usually the one that can form the most bonds, based on its valence electrons. Hence, hydrogen, fluorine (F) with 7 valence electrons, and helium cannot act as central atoms because they cannot form multiple bonds.
Electronegativity
Electronegativity is a measure of an atom's ability to attract and hold onto electrons. In a molecule, electronegativity helps determine how electrons are distributed.

Elements with high electronegativity, such as fluorine (F), tend to attract electrons strongly, whereas elements with lower electronegativity, like phosphorus (P), are less effective at attracting electrons. In a Lewis structure, the central atom is usually the least electronegative atom (except for hydrogen).

This is because less electronegative atoms are more willing to share their electrons to form bonds, making them suitable to act as central atoms. Fluorine, being highly electronegative and able to form only one bond, is not suitable as a central atom, unlike phosphorus, which is less electronegative and can form multiple bonds.

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Most popular questions from this chapter

Oxalic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)\) is found in toxic concentrations in rhubarb leaves. The acid forms two ions, \(\mathrm{HC}_{2} \mathrm{O}_{4}^{-}\) and \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-},\) by the sequential loss of \(\mathrm{H}^{+}\) ions. Draw Lewis structures for the three species, and comment on the relative lengths and strengths of their carbon-oxygen bonds. The connections among the atoms are shown below with single bonds only.

Except for nitrogen, the elements of Group \(5 \mathrm{~A}(15)\) all form pentafluorides, and most form pentachlorides. The chlorine atoms of \(\mathrm{PCl}_{5}\) can be replaced with fluorine atoms one at a time to give, successively, \(\mathrm{PCl}_{4} \mathrm{~F}, \mathrm{PCl}_{3} \mathrm{~F}_{2}, \ldots, \mathrm{PF}_{5} .\) (a) Given the sizes of \(\mathrm{F}\) and Cl, would you expect the first two F substitutions to be at axial or equatorial positions? Explain. (b) Which of the five fluorinecontaining molecules have no dipole moment?

Cryolite \(\left(\mathrm{Na}_{3} \mathrm{AlF}_{6}\right)\) is an indispensable component in the electrochemical production of aluminum. Draw a Lewis structure for the \(\mathrm{AlF}_{6}^{3-}\) ion.

In each of the following compounds, the \(\mathrm{C}\) atoms form a single ring. Draw a Lewis structure for each molecule, identify cases for which resonance exists, and determine the carbon-carbon bond order(s): (a) \(\mathrm{C}_{3} \mathrm{H}_{4} ;\) (b) \(\mathrm{C}_{3} \mathrm{H}_{6} ;\) (c) \(\mathrm{C}_{4} \mathrm{H}_{6} ;\) (d) \(\mathrm{C}_{4} \mathrm{H}_{4} ;\) (e) \(\mathrm{C}_{6} \mathrm{H}_{6}\).

Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following: (a) \(\mathrm{O}_{3}\) (b) \(\mathrm{H}_{3} \mathrm{O}^{+}\) (c) \(\mathrm{NF}_{3}\)

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