Calculate \(\Delta H^{\circ}\) in kilojoules for the following reaction, the
preparation of the unstable acid nitrous acid, \(\mathrm{HNO}_{2}\).
$$
\mathrm{HCl}(g)+\mathrm{NaNO}_{2}(s) \longrightarrow
\mathrm{HNO}_{2}(l)+\mathrm{NaCl}(s)
$$
Use the following thermochemical equations
\(2 \mathrm{NaCl}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2
\mathrm{HCl}(g)+\mathrm{Na}_{2} \mathrm{O}(s)\)
\(\Delta H^{\circ}=+507.31 \mathrm{~kJ}\)
\(\mathrm{NO}(g)+\mathrm{NO}_{2}(g)+\mathrm{Na}_{2} \mathrm{O}(s)
\longrightarrow 2 \mathrm{NaNO}_{2}(s)\)
$$
\begin{aligned}
\Delta H^{\circ} &=-427.14 \mathrm{~kJ} \\
\mathrm{NO}(g)+\mathrm{NO}_{2}(g) \longrightarrow \mathrm{N}_{2}
\mathrm{O}(g)+\mathrm{O}_{2}(g) & \\
\Delta H^{\circ} &=-42.68 \mathrm{~kJ}
\end{aligned}
$$
\(2 \mathrm{HNO}_{2}(l) \longrightarrow \mathrm{N}_{2}
\mathrm{O}(g)+\mathrm{O}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)\)
\(\Delta H^{\circ}=+34.35 \mathrm{~kJ}\)