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What does it mean when we say that an ion is "hydrated?"

Short Answer

Expert verified
An ion is 'hydrated' when it's surrounded by water molecules arranged in a specific manner due to electrostatic interactions between the ions and the water's partial charges.

Step by step solution

01

Define Hydration of Ions

The process of surrounding an ion with water molecules is termed 'hydration'. In this process, the water molecules arrange themselves around the ion due to the ion's electric charge, which attracts the polar water molecules. The positive end (hydrogen atoms) of the water molecule is attracted to anions (negative ions), while the negative end (oxygen atom) is attracted to cations (positive ions).
02

Explain the Significance of Ion Hydration

Hydration of ions is important because it explains many properties of ions in solutions, such as their ability to conduct electricity. The water molecules that are bound to the ions help stabilize the ions in solution and facilitate their interaction with other ions or molecules. It also has an effect on the solubility of ionic compounds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solution Chemistry
Solution chemistry is a branch of chemistry focused on the study of solutions, which are homogeneous mixtures composed of two or more substances. In the context of aqueous solutions, the solvent is water, a polar molecule that can dissolve a wide range of substances, particularly ionic compounds.

During the dissolution process, water molecules interact with solute particles, such as ions, leading to a process known as hydration. This interaction is crucial because it determines the extent to which a compound can form a solution and affects properties like melting and boiling points, vapor pressure, and viscosity. Hydration is foundational in solution chemistry as it directly influences how substances behave in aqueous environments.
Ionic Solubility
Ionic solubility refers to the ability of ionic compounds to dissolve in a solvent, producing ions as part of a solution. The solubility of an ionic compound is mainly influenced by the lattice energy of the solid and the hydration energy of the ions that result from dissolving the substance.

Lattice energy is the energy released when ions bond to form a crystalline lattice, and it must be overcome for a compound to dissolve. On the other hand, hydration energy is the energy released when ions interact with the solvent, such as water, and become solvated or hydrated. When the hydration energy is sufficient to overcome the lattice energy, the compound is said to be soluble. This process is dynamic and is based on principles like 'like dissolves like,' which means polar solvents typically dissolve polar or ionic solutes effectively.
Electrical Conductivity in Ions
Electrical conductivity in ions is a measure of an ion's ability to conduct electricity through a solution. When ionic compounds dissolve in water, they dissociate into cations and anions, which are charged particles that move through the solution, carrying electrical current.

The degree of dissociation and the concentration of these ions determine the level of electrical conductivity. Highly soluble ionic compounds that dissociate completely tend to produce solutions with high electrical conductivity. The hydration of ions plays a significant role in this process by stabilizing the ions and enabling them to move more freely in solution, thus enhancing electrical conduction. Conductivity is a critical parameter in many industrial processes and is also used to measure the purity of water, as pure water does not conduct electricity well due to the absence of dissolved ions.

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Most popular questions from this chapter

Write balanced ionic and net ionic equations for these reactions. (a) \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}(a q)+\mathrm{BaCl}_{2}(a q) \longrightarrow\) $$ \mathrm{NH}_{4} \mathrm{Cl}(a q)+\mathrm{BaCO}_{3}(s) $$ (b) \(\mathrm{CuCl}_{2}(a q)+\mathrm{NaOH}(a q) \longrightarrow\) $$ \mathrm{Cu}(\mathrm{OH})_{2}(s)+\mathrm{NaCl}(a q) $$ (c) \(\mathrm{FeSO}_{4}(a q)+\mathrm{Na}_{3} \mathrm{PO}_{4}(a q) \longrightarrow\) \(\mathrm{Fe}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)+\mathrm{Na}_{2} \mathrm{SO}_{4}(a q)\) (d) \(\mathrm{AgC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{NiCl}_{2}(a q) \longrightarrow\) \(\mathrm{AgCl}(s)+\mathrm{Ni}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)\)

Which of the following are strong acids? (a) \(\mathrm{HCN},\) (b) \(\mathrm{HNO}_{3}\), (c) \(\mathrm{H}_{2} \mathrm{SO}_{3},\) (d) HCl, (e) \(\mathrm{HCHO}_{2}\), (f) \(\mathrm{HNO}_{2}\)

Calculate the molarity of a solution prepared by dissolving (a) \(4.00 \mathrm{~g}\) of sodium hydroxide in a total volume of \(100.0 \mathrm{~mL}\) of solution. (b) \(16.0 \mathrm{~g}\) of calcium chloride in a total volume of \(250.0 \mathrm{~mL}\) of solution.

A mixture was known to contain both \(\mathrm{KNO}_{3}\) and \(\mathrm{K}_{2} \mathrm{SO}_{3}\). To \(0.486 \mathrm{~g}\) of the mixture, dissolved in enough water to give \(50.00 \mathrm{~mL}\) of solution, was added \(50.00 \mathrm{~mL}\) of \(0.150 \mathrm{M} \mathrm{HCl}\) (an excess of \(\mathrm{HCl}\) ). The reaction mixture was heated to drive off all of the \(\mathrm{SO}_{2}\), and then \(25.00 \mathrm{~mL}\) of the reaction mixture was titrated with \(0.100 \mathrm{MKOH}\) The titration required \(13.11 \mathrm{~mL}\) of the \(\mathrm{KOH}\) solution to reach an end point. What was the percentage by mass of \(\mathrm{K}_{2} \mathrm{SO}_{3}\) in the original mixture of \(\mathrm{KNO}_{3}\) and \(\mathrm{K}_{2} \mathrm{SO}_{3}\) ?

What is a dynamic equilibrium? Using acetic acid as an example, describe why all the \(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) molecules are not ionized in water.

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