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The formula for a compound is correctly given as \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\). State two reasons why we expect this to be a molecular compound, rather than an ionic compound.

Short Answer

Expert verified
The compound \(\mathrm{C}_{6}\mathrm{H}_{12}\mathrm{O}_{6}\) is likely a molecular compound because it's composed of only nonmetals, which typically form covalent bonds, not ionic bonds.

Step by step solution

01

Identify the Elements Present

Examine the formula \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) to determine which elements are involved. In this case, the compound is composed of carbon (C), hydrogen (H), and oxygen (O).
02

Analyze the Types of Elements

Note that carbon, hydrogen, and oxygen are all nonmetals. Ionic compounds typically consist of metals and nonmetals, whereas molecular compounds consist of nonmetals only.
03

Consider the Nature of the Bonding between Atoms

Recall that molecular (covalent) compounds are formed when nonmetal atoms share electrons. The presence of only nonmetal elements in \(\mathrm{C}_{6}\mathrm{H}_{12}\mathrm{O}_{6}\) suggests that the atoms are likely to be held together by covalent bonds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Formula Interpretation
Understanding the language of chemistry begins with the interpretation of chemical formulas, such as \(\mathrm{C}_{6}\mathrm{H}_{12}\mathrm{O}_{6}\). This notation specifies the types and quantities of atoms present in a compound. The subscript numbers indicate the number of atoms for each element: six carbon atoms, twelve hydrogen atoms, and six oxygen atoms compose this compound.

Interpreting chemical formulas requires knowledge of the periodic table and the nature of the elements involved. A pattern recognized in ionic and molecular compounds is crucial to classify them correctly. Ionic compounds are formed from metals and nonmetals exchanging electrons, while molecular compounds consist of nonmetals sharing electrons. The formula in question lacks metallic elements, pointing toward a molecular structure. When you encounter a formula, closely examine the participating elements to deduce the type of compound you're dealing with.
Nonmetal Elements in Compounds
Nonmetal elements have a propensity to form molecular compounds through the sharing of electrons, as opposed to transferring electrons, which is a characteristic of metals in ionic bonding. In a compound like \(\mathrm{C}_{6}\mathrm{H}_{12}\mathrm{O}_{6}\), the combination of carbon, hydrogen, and oxygen - all nonmetals - indicates the likelihood of a molecular compound.

  • Carbon, a key element in organic compounds, prefers to create stable covalent bonds.
  • Hydrogen, while having an electron configuration akin to alkali metals, forms covalent bonds in most organic contexts.
  • Oxygen, highly electronegative, also engages in covalent bonding to fulfill its valence shell.

These behaviors reflect how nonmetal elements interact to form intricate molecular structures rather than ionic lattices.
Covalent Bonding
Covalent bonding is the foundation of molecular compounds and occurs when two or more nonmetal atoms share pairs of electrons in order to achieve the full outer shell configuration of the noble gases. This sharing allows each atom to gain more stability.

In the case of \(\mathrm{C}_{6}\mathrm{H}_{12}\mathrm{O}_{6}\), covalent bonds are formed due to the inherent nature of the involved nonmetals seeking stability through shared electron pairs. Carbon, with four electrons in its outer shell, is known for forming four covalent bonds. Hydrogen, with only one valence electron, covalently bonds to achieve a duet configuration, similar to helium. Oxygen, on the other hand, typically forms two covalent bonds to complete its valence shell.

The resulting network of shared electrons is what gives molecular compounds their unique properties, such as lower melting and boiling points compared to ionic compounds, and why substances like glucose (\(\mathrm{C}_{6}\mathrm{H}_{12}\mathrm{O}_{6}\)) exist as discrete molecules.

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