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Write the equation that relates the standard cell potential to the standard free energy change for a reaction.

Short Answer

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The standard cell potential is related to the standard free energy change by the equation \( \Delta G^\circ = -nFE^\circ \).

Step by step solution

01

Identify the Relevant Equation

The equation that relates the standard cell potential, \( E^\circ \), to the standard free energy change, \( \Delta G^\circ \), for a reaction is known as the Gibbs free energy equation for electrochemical cells. This equation is derived from the principles of thermodynamics and electrochemistry.
02

Write the Gibbs Free Energy Equation

The equation that directly relates the standard cell potential to the standard free energy change is given by \[ \Delta G^\circ = -nFE^\circ \] where \( \Delta G^\circ \) is the standard free energy change, \( n \) is the number of moles of electrons transferred in the reaction, \( F \) is the Faraday's constant (approximately 96485 C/mol), and \( E^\circ \) is the standard cell potential.
03

Understanding the Components

The standard cell potential \( E^\circ \) is a measure of how much potential energy is available from the electrochemical reaction when all reactants and products are in their standard states. The standard free energy change \( \Delta G^\circ \) represents the maximum amount of work that the reaction can perform under standard conditions, and it's expressed in joules per mole. The Faraday's constant \( F \) converts the charge transferred in the reaction (in moles of electrons) to coulombs.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy Equation
The Gibbs free energy equation is fundamental to understanding the relationship between chemical spontaneity and the direction of a reaction. It is written as ewline \[ ewline \text{ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline} Delta G = -nFE \] where ewline \( ewline \text{ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline} G \) is the Gibbs free energy change, \(n\) stands for the number of moles of electrons transferred in the electronic reaction, \(F\) is Faraday's constant, measuring the electric charge per mole of electrons, and \(E\) represents the cell potential or electromotive force. The minus sign indicates that a spontaneous process (with a positive standard cell potential) will have a negative Gibbs free energy, meaning the process can do work on the surroundings.
Thermodynamics in Electrochemistry
Thermodynamics plays a crucial role in electrochemical reactions, dictating whether a reaction is energetically feasible.

Electrochemical cells convert chemical energy into electrical energy through redox reactions. Here, the Gibbs free energy change provides insight into the reaction's spontaneity. A negative ewline \(Delta G^circ circ \) indicates a spontaneous reaction, thus capable of producing an electric current.

Cells with a positive standard potential (\(E^circ \) > 0) can do work on the surroundings, as they have enough energy to move electrons against an external force, like in a battery. Conversely, cells with a negative standard potential require work, indicating a non-spontaneous reaction that needs an external voltage to proceed, such as in electrolysis.
Faraday's Constant
Faraday's constant (\(F\)) is a bridge between the macroscopic world of chemical reactions and the microscopic world of charge in physics.

It is approximately 96485 Coulombs per mole (C/mol), representing the total charge carried by one mole of electrons. This constant not only allows us to equate the chemical aspect (\(n\)) of our equations to the physical aspect (\(E\)), but it also scales the electron transfer in reactions to the amount of current produced or consumed. Without Faraday's constant, we would not be able to use electrochemical concepts to quantify real-world applications like the operation of batteries or the amount of substance produced in electrolysis.

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Most popular questions from this chapter

If two electrolytic cells are placed in series, the same number of electrons must pass through both cells. One student argues that you can get twice as much product if two cells are placed in series compared to a single cell and therefore the cost of production (i.e., the cost of electricity) will decrease greatly and profits will increase. Is the student correct? Explain your reasoning based on the principles of electrochemistry.

Determine whether the reaction: $$ \begin{aligned} \mathrm{S}_{2} \mathrm{O}_{8}^{2-}+\mathrm{Ni}(\mathrm{OH})_{2}+2 \mathrm{OH}^{-} & \longrightarrow \\ 2 \mathrm{SO}_{4}^{2-}+\mathrm{NiO}_{2}+2 \mathrm{H}_{2} \mathrm{O} \end{aligned} $$ will occur spontaneously under standard state conditions. Use \(E_{\text {cell }}^{\circ}\) calculated from the data below to answer the question. $$ \begin{aligned} \mathrm{NiO}_{2}+2 \mathrm{H}_{2} \mathrm{O}+2 e^{-} \rightleftharpoons \mathrm{Ni}(\mathrm{OH})_{2}+2 \mathrm{OH}^{-} \\ E_{\mathrm{NiO}_{2}}^{\circ}=0.49 \mathrm{~V} \\ \mathrm{~S}_{2} \mathrm{O}_{8}^{2-}+2 e^{-} \rightleftharpoons 2 \mathrm{SO}_{4}^{2-} & E_{\mathrm{SO}_{4}^{2-}}^{\circ}=2.01 \mathrm{~V} \end{aligned} $$

Write the cathode, anode, and net cell reaction in a hydrogen-oxygen fuel cell.

There are a variety of methods available for generating electricity. List as many methods as you can. Rank each of these methods based on your knowledge of (a) the efficiency of the method and (b) the environmental pollution caused by each method.

Suppose a galvanic cell was constructed at \(25^{\circ} \mathrm{C}\) using a \(\mathrm{Cu} / \mathrm{Cu}^{2+}\) half-cell (in which the molar concentration of \(\mathrm{Cu}^{2+}\) was \(1.00 \mathrm{M}\) ) and a hydrogen electrode having a partial pressure of \(\mathrm{H}_{2}\) equal to 1 atm. The hydrogen electrode dips into a solution of unknown hydrogen ionconcentration, and the two half- cells are connected by a salt bridge. The precise value of \(E_{\mathrm{cell}}^{\circ}\) is \(+0.3419 \mathrm{~V}\). (a) Derive an equation for the \(\mathrm{pH}\) of the solution with the unknown hydrogen ion concentration, expressed in terms of \(E_{\text {cell }}\) and \(E_{\text {cell }}^{\circ}\) (b) If the \(\mathrm{pH}\) of the solution were \(5.15,\) what would be the observed potential of the cell? (c) If the potential of the cell were \(0.645 \mathrm{~V}\), what would be the \(\mathrm{pH}\) of the solution?

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