Chapter 17: Problem 4
With respect to \(K_{\mathrm{sp}}\), what conditions must be met if a precipitate is going to form in a solution?
Short Answer
Expert verified
A precipitate will form if the ion product (Q) of the solution exceeds the solubility product constant (Ksp) indicating a supersaturated state.
Step by step solution
01
Understanding Saturation
To determine if a precipitate will form, one must understand the concept of a saturated solution, which occurs when the maximum amount of a solute has been dissolved in a solvent at a given temperature. The point at which this occurs is represented by the solubility product constant, or Ksp.
02
Comparing Q and Ksp
Calculate the reaction quotient, Q, which is the product of the molar concentrations of the ionic species at any given moment. If Q is less than Ksp, the solution is unsaturated and no precipitate will form. If Q equals Ksp, the solution is exactly saturated and no change will occur. If Q is greater than Ksp, the solution is supersaturated and a precipitate will form.
03
Identifying the Conditions for Precipitation
For a precipitate to form, the solution must be supersaturated with respect to the solute. This means that the ion product (Q) of the ions in solution must exceed the solubility product constant (Ksp). When Q > Ksp, the excess solute will precipitate out of the solution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Saturated Solution
When a solution has reached the point where it can no longer dissolve additional solute, it is considered to be saturated. At this stage, the solution holds the maximum concentration of solute that can be dissolved at a given temperature. In the context of solubility, we refer to this balancing point with the term solubility product constant, denoted as (K_{sp}).
In a saturated solution, any addition of solute will not increase the concentration because the rate of the solute dissolving and precipitating are equal. This equilibrium is important because it defines the threshold at which the solution changes from being able to dissolve more solute to one where excess solute may start to precipitate out.
In a saturated solution, any addition of solute will not increase the concentration because the rate of the solute dissolving and precipitating are equal. This equilibrium is important because it defines the threshold at which the solution changes from being able to dissolve more solute to one where excess solute may start to precipitate out.
Reaction Quotient (Q)
The reaction quotient, represented by the symbol Q, is a snapshot of a solution's condition at a given moment. It resembles the (K_{sp}) in form, being the product of the concentrations of the ionic species, each raised to a power equal to its coefficient in the balanced equation.
To find Q, simply multiply the molar concentrations of the ions involved in the dissolving process. It's vital to compare Q to the solubility product ((K_{sp})) to determine the solution's saturation state. When Q < (K_{sp}), the solution can hold more solute, hence it's unsaturated. If Q = (K_{sp}), the solution is perfectly saturated, and when Q > (K_{sp}), the solution is on the brink of precipitation as it's supersaturated.
To find Q, simply multiply the molar concentrations of the ions involved in the dissolving process. It's vital to compare Q to the solubility product ((K_{sp})) to determine the solution's saturation state. When Q < (K_{sp}), the solution can hold more solute, hence it's unsaturated. If Q = (K_{sp}), the solution is perfectly saturated, and when Q > (K_{sp}), the solution is on the brink of precipitation as it's supersaturated.
Precipitation Conditions
Understanding the conditions for precipitation is crucial when dealing with solutions of dissolved substances. Precipitation occurs when the reaction quotient (Q) surpasses the solubility product constant (Ksp). Specifically, this means that the actual concentration of ions in the solution is too large to be maintained in the dissolved state, and as a result, the excess solute begins to form a solid, or precipitate.
Identifying these conditions allows us to predict and control the formation of precipitates, which is valuable in many applications such as chemical synthesis, water treatment, and medicinal chemistry. Additionally, by manipulating variables like temperature and concentration, one can induce or avoid precipitation as required for specific purposes.
Identifying these conditions allows us to predict and control the formation of precipitates, which is valuable in many applications such as chemical synthesis, water treatment, and medicinal chemistry. Additionally, by manipulating variables like temperature and concentration, one can induce or avoid precipitation as required for specific purposes.
Supersaturated Solution
A supersaturated solution contains more dissolved solute than would be in equilibrium at a given temperature. This solution is stable only until a nucleus of solid can form, causing the excess solute to quickly precipitate out.
Achieving a supersaturated state usually requires a sequence where the solution is first saturated at a higher temperature and then cooled down slowly without disturbing the solution. Even with a slight disturbance like shaking or by introducing a small crystal of the solute, precipitation could occur instantly. This delicate state of supersaturation is essential in many processes, such as rock candy creation, where large sugar crystals form, and in certain industrial crystal growth procedures.
Achieving a supersaturated state usually requires a sequence where the solution is first saturated at a higher temperature and then cooled down slowly without disturbing the solution. Even with a slight disturbance like shaking or by introducing a small crystal of the solute, precipitation could occur instantly. This delicate state of supersaturation is essential in many processes, such as rock candy creation, where large sugar crystals form, and in certain industrial crystal growth procedures.