Chapter 17: Problem 106
The overall formation constant for \(\mathrm{Ag}(\mathrm{CN})_{2}^{-}\) equals \(5.3 \times 10^{18}\), and the \(K_{\text {sp }}\) for \(\mathrm{AgCN}\) equals \(6.0 \times 10^{-17}\) Calculate \(K_{\mathrm{c}}\) for the following reaction: \(\mathrm{AgCN}(s)+\) \(\mathrm{CN}^{-}(a q) \rightleftharpoons \mathrm{Ag}(\mathrm{CN})_{2}^{-}(a q)\).
Short Answer
Step by step solution
Identify the Relevant Equations
Understand the Relationship Between \(K_{f}\), \(K_{\text{sp}}\), and \(K_{c}\)
Solve for \(K_{c}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solubility Product Constant (Ksp)
Complex Ion Formation
When considering the chemical equilibrium in complex ion formation, one should take note that the stability of the complex ion is reflected by its formation constant, Kf, often also referred to as the stability constant. This constant is indicative of the affinity between the metal ion and the ligands, with a higher value corresponding to a more stable complex ion. In the exercise, the high value of the overall formation constant for Ag(CN)2− suggests that the complex ion is significantly favored in the chemical equilibrium. The formation of complex ions can be crucial in processes such as chelation therapy, water softening, and the stabilization of ionic species in solution.
Equilibrium Constant Calculation
For the reaction AgCN(s) + CN−(aq) ⇌ Ag(CN)2−(aq), the equilibrium constant (Kc) can be calculated provided we have the solubility product constant (Ksp) for AgCN and the formation constant (Kf) for the complex ion Ag(CN)2−. The relationship between these constants is given by the equation Kf = Ksp ⋅ Kc. By rearranging this equation, we can solve for the equilibrium constant that governs the formation of the complex ion from the insoluble salt and an additional ligand ion.
To calculate Kc for the given reaction, you divide the overall formation constant Kf by the solubility product constant Ksp. Following this process as outlined in the provided exercise results in a clear understanding of how these constants interrelate and offers insight into the solubility behavior and stability of specific compounds within a solution at equilibrium.