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How is the term reaction quotient defined? What symbol is it given?

Short Answer

Expert verified
The reaction quotient, represented by the symbol 'Q', describes the ratio of products to reactants at any point during a chemical reaction, before reaching equilibrium.

Step by step solution

01

Understanding the Reaction Quotient

The reaction quotient (Q) is a number that describes the relative amounts of products and reactants present during a reaction at any point in time. It is calculated similarly to the equilibrium constant, but for a reaction that has not necessarily reached equilibrium.
02

Expression for the Reaction Quotient

To calculate Q, we use the concentrations of the chemical species involved in the reaction. For a general reaction aA + bB ⇄ cC + dD, the reaction quotient Q is given by: \[ Q = \frac{[C]^c [D]^d}{[A]^a [B]^b} \]where the letters in brackets represent the concentrations of the products and reactants at a particular moment in time, and the lowercase letters are the stoichiometric coefficients of the balanced chemical equation.
03

Identifying the Symbol for Reaction Quotient

The symbol for the reaction quotient is 'Q'.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant
The equilibrium constant, symbolized as 'K', is a pivotal concept in understanding chemical reactions and stoichiometry. It is a numerical value that represents the ratio of concentrations of products to reactants at equilibrium for a given chemical reaction. For the generic chemical equation ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline ewline \[ aA + bB \rightleftharpoons cC + dD \]the equilibrium constant is given by the equation:\[ K = \frac{[C]^c [D]^d}{[A]^a [B]^b} \]This expression is very similar to that of the reaction quotient, but while 'Q' describes the ratio at any point in time, 'K' specifically describes this ratio at the point when the reaction is in equilibrium. At equilibrium, the rate of the forward reaction equals the rate of the backward reaction, and the concentrations of reactants and products remain constant over time. If 'Q' equals 'K', the system is at equilibrium. If 'Q' is less than 'K', the reaction will proceed in the forward direction to reach equilibrium. Conversely, if 'Q' is greater than 'K', the reaction will proceed in the backward direction towards equilibrium. Understanding the relationship between 'Q' and 'K' helps predict the direction of the reaction's shift when it's not at equilibrium.
Chemical Reaction
A chemical reaction is a process where substances, also known as reactants, transform into different substances, called products. During these transformations, bonds between atoms are broken and reformed, hence showing a change in the properties of substances. Chemical reactions can be represented by chemical equations, which are symbolic representations of the reactants and products involved in the reaction. For example, the reaction of hydrogen and oxygen to produce water is represented as:\[ 2H_2 + O_2 \rightarrow 2H_2O \]In an equation, the reactants are written on the left side, and the products on the right side. Coefficients before the molecular formulas indicate the stoichiometric amount of each substance involved. It's important to balance chemical equations because they must obey the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a chemical reaction.Various factors can affect the rate and direction of chemical reactions including temperature, pressure, concentration, and the presence of catalysts. For students seeking to fully grasp chemical reactions, diving into the intricacies of these factors, as well as the concept of reaction energetics and kinetics, would greatly deepen understanding.
Stoichiometry
Stoichiometry is the quantitative relationship between the reactants and products in a chemical reaction. It concerns the calculation of the quantities, often measured in moles, and the determination of the limiting reagents in a reaction. The stoichiometric coefficients – the numbers in front of molecular formulas in a chemical equation – represent the ratio in which substances react and form products.Here is an example to understand stoichiometry. If the balanced chemical equation is:\[ 4NH_3 + 5O_2 \rightarrow 4NO + 6H_2O \]it tells us that four moles of ammonia (\( NH_3 \)) react with five moles of oxygen (\( O_2 \)) to produce four moles of nitrogen monoxide (\( NO \)) and six moles of water (\( H_2O \)). Using these ratios, one can predict the amounts of reactants needed and products formed.Mastering stoichiometry is fundamental for students as it applies to all fields of chemistry. By understanding these ratios and the method to calculate moles, mass, and volume of substances, students can interpret and predict the outcomes of reactions accurately. Practical applications of stoichiometry include calculating yields, understanding purity of substances, and the intricate planning required in chemical manufacturing.

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Most popular questions from this chapter

At a certain temperature, \(K_{\mathrm{c}}=0.18\) for the equilibrium \(\mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{PCl}_{5}(g)\) Suppose a reaction vessel at this temperature contained these three gases at the following concentrations: \(\left[\mathrm{PCl}_{3}\right]=\) \(0.0420 \mathrm{M},\left[\mathrm{Cl}_{2}\right]=0.0240 \mathrm{M},\left[\mathrm{PCl}_{5}\right]=0.00500 \mathrm{M}\) (a) Compute the reaction quotient and use it to determine whether the system is in a state of equilibrium. (b) If the system is not at equilibrium, in which direction will the reaction proceed to get to equilibrium?

Consider the equilibrium \(2 \mathrm{NaHSO}_{3}(s) \rightleftharpoons \mathrm{Na}_{2} \mathrm{SO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{SO}_{2}(g)\) How will the position of equilibrium be affected by the following changes? (a) Adding \(\mathrm{NaHSO}_{3}\) to the reaction vessel (b) Removing \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) from the reaction vessel (c) Adding \(\mathrm{H}_{2} \mathrm{O}\) to the reaction vessel (d) Increasing the volume of the reaction vessel at con- stant temperature

Ethylene, \(\mathrm{C}_{2} \mathrm{H}_{4}\), and water react under appropriate conditions to give ethanol. The reaction is: $$ \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(g) $$ An equilibrium mixture of these gases at a certain temperature had the following partial pressures: \(P_{\mathrm{C}_{2} \mathrm{H}_{4}}=\) $$ 0.575 \mathrm{~atm}, P_{\mathrm{H}_{2} \mathrm{O}}=1.30 \mathrm{~atm}, \text { and } P_{\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}}=6.99 \mathrm{~atm} $$ What is the value of \(K_{\mathrm{P}}\) ?

The heterogeneous reaction \(2 \mathrm{HCl}(g)+\mathrm{I}_{2}(s) \rightleftharpoons\) \(2 \mathrm{HI}(g)+\mathrm{Cl}_{2}(g)\) has \(K_{\mathrm{c}}=1.6 \times 10^{-34}\) at \(25^{\circ} \mathrm{C}\). Suppose \(0.100 \mathrm{~mol}\) of \(\mathrm{HCl}\) and solid \(\mathrm{I}_{2}\) are placed in a \(1.00 \mathrm{~L}\) container. What will be the equilibrium concentrations of HI and \(\mathrm{Cl}_{2}\) in the container?

A 0.050 mol sample of formaldehyde vapor, \(\mathrm{CH}_{2} \mathrm{O}\), was placed in a heated \(500 \mathrm{~mL}\) vessel and some of it decomposed. The reaction is $$ \mathrm{CH}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{CO}(g) $$ At equilibrium, the \(\mathrm{CH}_{2} \mathrm{O}(g)\) concentration was \(0.066 \mathrm{~mol} \mathrm{~L}^{-1}\). Calculate the value of \(K_{\mathrm{c}}\) for this reaction.

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