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Radon- 220 is radioactive, and decays into polonium- 216 by emitting an alpha particle. This is a first-order process with a rate constant of \(0.0125 \mathrm{~s}^{-1}\). When the concentration of radon- 220 is \(1.0 \times 10^{-9} \mathrm{~mol} \mathrm{~L}^{-1}\), what is the rate of the reaction?

Short Answer

Expert verified
The rate of the reaction is \(1.25 \times 10^{-11}\mathrm{~mol} \mathrm{~L}^{-1} \mathrm{s}^{-1}\).

Step by step solution

01

Understand the Rate Law for First-Order Reactions

For a first-order reaction, the rate law is given by the equation: \( rate = k[\text{A}] \), where \( k \) is the rate constant and \([\text{A}]\) is the concentration of the reactant. In this case, \( k = 0.0125\mathrm{~s}^{-1} \) and the concentration of Radon-220 is \( 1.0 \times 10^{-9}\mathrm{~mol} \mathrm{~L}^{-1} \).
02

Plug in the Values into the Rate Law Equation

Substitute the given values into the rate law equation: \( rate = 0.0125\mathrm{~s}^{-1} \times 1.0 \times 10^{-9}\mathrm{~mol} \mathrm{~L}^{-1} \).
03

Calculate the Rate of the Reaction

Perform the multiplication to find the rate of the reaction: \( rate = 0.0125\mathrm{~s}^{-1} \times 1.0 \times 10^{-9}\mathrm{~mol} \mathrm{~L}^{-1} = 1.25 \times 10^{-11}\mathrm{~mol} \mathrm{~L}^{-1} \mathrm{s}^{-1} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
Understanding the rate law is crucial for studying the speed of chemical reactions. It is a mathematical equation that relates the rate of a reaction to the concentration of its reactants. For first-order reactions, the rate law has a simple form:
\[ rate = k[\text{A}] \]
In this equation, \( k \) represents the rate constant, a unique value for each reaction that depends on factors like temperature, and \( [\text{A}] \) symbolizes the concentration of the reactant. Focusing on our example with Radon-220, by knowing the rate constant \( k \) and the initial concentration of Radon-220, we can easily apply the formula to calculate the reaction rate. Through this process, it becomes transparent how the concentration directly influences the rate at which the reaction proceeds. This equation is a powerful tool because once the rate constant is determined, it allows us to predict the reaction rate at any given concentration of reactants.
Radioactive Decay
Radioactive decay is a spontaneous process by which an unstable atomic nucleus loses energy by emitting radiation. This phenomenon is a natural occurrence found in elements such as Uranium, Carbon-14, and as mentioned in our example, Radon-220. The decay of these unstable isotopes follows a first-order reaction, where each nucleus has a fixed probability of decaying per unit time, hence the use of the rate law.
In our exercise, Radon-220 decays by emitting an alpha particle, transforming into Polonium-216. The rate constant (\( 0.0125 \text{s}^{-1} \)) tells us how quickly this decay process occurs. Radioactive decay is not only crucial for the field of nuclear chemistry but also for applications such as radiometric dating, cancer treatment, and understanding the behavior of naturally occurring and man-made radionuclides.
Half-Life
The concept of half-life is intimately connected with radioactive decay and chemical kinetics. Half-life, often represented by the symbol \( t_{1/2} \), is the time required for half the amount of a reactant to be consumed or for half of a radioactive substance to decay. For a first-order reaction, the half-life is given by the equation:
\[ t_{1/2} = \frac{\ln(2)}{k} \]
It is a constant value that does not depend on the initial concentration of reactant. This property makes it particularly useful since knowing the half-life and rate constant allows you to understand the longevity and decay profile of a substance. For many real-life applications, such as pharmaceuticals and environmental monitoring, knowing the half-life is crucial for safety and effectiveness analysis.
Chemical Kinetics
Chemical kinetics is the branch of chemistry that studies the speed of chemical reactions and the factors that influence this rate. It encompasses not just the rate law but a broader set of principles that dictate how and why chemical reactions occur as they do. Factors such as temperature, catalysts, surface area, and concentration all play integral roles in reaction kinetics. Understanding kinetics is essential for controlling processes like synthesizing new materials, degrading pollutants, and even digesting food. Kinetics also helps researchers develop better catalysts that increase reaction efficiency, which is critical in industries ranging from pharmaceuticals to energy production. The study of chemical kinetics bridges the gap between knowing a reaction can occur and understanding how it can be harnessed practically.

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Most popular questions from this chapter

Can a reaction have a negative activation energy? Explain your response.

For the reaction, \(2 A+B \longrightarrow 3 C\), it was found that the rate of disappearance of \(B\) was \(0.30 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\). What were the rates of disappearance of \(A\) and the rate of appearance of \(C\) ?

Suppose a reaction occurs with the following mechanism: (1) \(2 A \rightleftharpoons A_{2}\) \((\) fast \()\)(2) \(A_{2}+E \longrightarrow B+C\)(slow) in which the first step is a very rapid reversible reaction that can be considered to be essentially an equilibrium (forward and reverse reactions occurring at the same rate) and the second is a slow step. (a) Write the rate law for the forward reaction in step (1). (b) Write the rate law for the reverse reaction in step (1). (c) Write the rate law for the rate-determining step. (d) What is the chemical equation for the net reaction that occurs in this chemical change? Use the results of parts (a) and (b) to rewrite the rate law of the rate- determining step in terms of the concentrations of the reactants in the overall balanced chemical equation for the reaction.

What is a rate-determining step?

Carbon-14 dating can be used to estimate the age of formerly living materials because the uptake of carbon-14 from carbon dioxide in the atmosphere stops once the organism dies. If tissue samples from a mummy contain about \(81.0 \%\) of the carbon-14 expected in living tissue, how old is the mummy? The half- life for decay of carbon-14 is 5730 years.

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