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How does an instantaneous rate of reaction differ from an average rate of reaction?

Short Answer

Expert verified
The average rate of reaction is measured over a time interval and reflects the overall change, while the instantaneous rate is the rate at a specific moment, derived from the slope of the tangent to the concentration-time curve at that point.

Step by step solution

01

Concept of Average Rate of Reaction

Understand that the average rate of reaction is calculated over a specific time interval. This time interval can be from the start of the reaction until a particular time point or between any two time points. The average rate is defined as the change in concentration of a reactant or product divided by the change in time for that interval.
02

Concept of Instantaneous Rate of Reaction

Identify that the instantaneous rate of reaction refers to the rate at a particular moment in the reaction. It is the change in concentration at a specific time and can be determined by taking the derivative of the concentration with respect to time, or graphically, as the slope of the tangent to the concentration-time curve at that point.
03

Comparison of Instantaneous and Average Rates

Compare both concepts by highlighting differences. While the average rate gives an overall idea of the speed of the reaction over a larger time period, the instantaneous rate provides the rate at an exact moment, reflecting how fast the reaction proceeds at that specific point in time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Rate of Reaction
When we talk about the average rate of reaction, we're referring to how quickly reactants are converted into products over a certain period of time. It's kind of like measuring the speed of a car over a long road trip - you can calculate the average speed by looking at the total distance traveled over the time taken. Similarly, in chemistry, the average rate is determined by the amount a reactant's concentration decreases or a product's concentration increases, divided by the time interval during which this change occurs.

This concept is pivotal as it gives you a broad idea of how fast the reaction is happening. So if you're looking at the reaction over a ten-minute timeframe, the average rate tells you how much it has progressed overall, but it won't reveal the variations that might have happened along the way - periods where it might have sped up or slowed down.
Instantaneous Rate of Reaction
Now, if average rate is like the overall speed of a car on a trip, the instantaneous rate of reaction is like glancing at the speedometer at a specific moment. It pinpoints how rapidly the reaction is moving at an exact point in time, which could be entirely different from its average speed. To get this rate, chemists take a 'snapshot' of the reaction at a particular moment and calculate how quickly the concentration changes at that instant.

If you're comfortable with calculus, it's essentially taking the derivative of the concentration with respect to time. Or, if you prefer a more visual approach, envision drawing a straight line that just grazes the curve on a graph of concentration versus time - this line represents the instantaneous rate. It is especially useful when you want to understand the kinetics of a reaction at a particular stage - perhaps when a reactant is half consumed, or right before a product starts to form.
Concentration-Time Curve
Discussing rates is much easier when we visualize the reaction, and that's where concentration-time curves come in handy. Imagine you can plot the concentration of a reactant on the y-axis and time on the x-axis. As the reaction proceeds, the graph will show a curve that typically slopes downwards, indicating the reactant being used up. This curve is like a story that illustrates every twist and turn of the reaction's progression over time.

By examining the shape of this curve, you can get insights not just into the average and instantaneous rates, but also into the reaction's dynamics. The steeper the slope, the faster the reaction at that moment. If you find flat sections, that suggests the reaction is in a period of inactivity or equilibrium. In learning chemistry, these curves are essential tools in predicting and understanding the behavior of chemical reactions.
Chemical Kinetics
Understanding rates is a big part of the broader study of chemical kinetics, which is all about the speed at which reactions occur and the pathways they take. Chemical kinetics dives into the factors that affect reaction rates, like temperature, pressure, concentration, and catalysts, drawing from both physics and chemistry to explain why certain reactions zip by while others trudge along slowly.

It's a fascinating area because it combines the theoretical with the practical. For example, scientists use kinetics to design faster, more efficient reactions for industrial processes, and to understand natural phenomena like the metabolism of food in our bodies. In a nutshell, chemical kinetics provides a comprehensive view of how reactions unfold and how we can control them to our advantage.

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Most popular questions from this chapter

The decomposition of phosphine, a very toxic gas, forms phosphorus and hydrogen in the following reaction: $$4 \mathrm{PH}_{3}(g) \longrightarrow \mathrm{P}_{4}(g)+6 \mathrm{H}_{2}(g)$$ (a) Express the rate with respect to each of the reactants and products. (b) If the instantaneous rate with respect to \(\mathrm{PH}_{3}\) is \(0.34 M \mathrm{~s}^{-1}\), what is the instantaneous rate of the reaction?

Hydrogen iodide decomposes according to the equation, $$2 \mathrm{HI}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{I}_{2}(g)$$The reaction is second order and has a rate constant equal to \(1.6 \times 10^{-3} \mathrm{~L} \mathrm{~mol}^{-1} \mathrm{~s}^{-1}\) at \(750^{\circ} \mathrm{C}\). If the initial concentration of HI in a container is \(3.4 \times 10^{-2} M\), how many minutes will it take for the concentration to be reduced $$\text { to } 8.0 \times 10^{-4} \mathrm{M}$$.

At a certain moment in the reaction, $$2 \mathrm{~N}_{2} \mathrm{O}_{5} \longrightarrow 4 \mathrm{NO}_{2}+\mathrm{O}_{2}$$ \(\mathrm{N}_{2} \mathrm{O}_{5}\), is decomposing at a rate of \(2.5 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\). What are the rates of formation of \(\mathrm{NO}_{2}\) and \(\mathrm{O}_{2}\) ?

The rate law for the decomposition of \(\mathrm{N}_{2} \mathrm{O}_{5}\) is rate \(=\) \(k\left[\mathrm{~N}_{2} \mathrm{O}_{5}\right] .\) If \(k=1.0 \times 10^{-5} \mathrm{~s}^{-1},\) what is the reaction rate when the \(\mathrm{N}_{2} \mathrm{O}_{5}\) concentration is \(0.0010 \mathrm{~mol} \mathrm{~L}^{-1}\) ?

What is a homogeneous catalyst? How does it function, in general terms?

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