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(a) What are the relationships among bond order, bond length, and bond energy? (b) According to molecular orbital theory, would either \(\mathrm{Be}\), or \(\mathrm{Be}_{2}^{+}\) be expected to exist? Explain.

Short Answer

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(a) Bond order, bond length, and bond energy are interconnected. Higher bond order corresponds to shorter bond length and higher bond energy, while lower bond order corresponds to longer bond length and lower bond energy. (b) According to molecular orbital theory, Be can exist, but Be2+ is not expected to exist due to its zero bond order and the presence of an unpaired electron, making it unstable.

Step by step solution

01

Part (a): Relationship between bond order, bond length, and bond energy

1. Bond Order: Bond order is defined as the number of chemical bonds between a pair of atoms in a molecule. It can take both integer and fractional values. Bond order can be calculated using molecular orbital theory by taking the difference between the number of bonding electrons and the number of antibonding electrons, divided by 2. The bond order is related to the bond length and bond energy as follows: - Higher bond order leads to a shorter bond length and higher bond energy. - Lower bond order leads to a longer bond length and lower bond energy. 2. Bond Length: Bond length, the distance between the nuclei of two bonded atoms, is determined by the balance between attractive forces (due to the shared electrons) and repulsive forces (due to the positively charged nuclei). As bond order increases, the bond length decreases because there is a stronger attraction between the atoms, which pulls the nuclei closer together. 3. Bond Energy: Bond energy is the energy required to break a chemical bond between two atoms. As bond order increases, the bond strength increases due to a larger electron concentration between the two bonded atoms. Consequently, the bond energy increases, requiring more energy to break the bond. In summary, bond order, bond length, and bond energy are interconnected. Higher bond order is associated with shorter bond length and higher bond energy, while lower bond order corresponds to longer bond length and lower bond energy.
02

Part (b): Existence of Be or Be2+ according to molecular orbital theory

1. Consider Be atom: Beryllium (Be) has an atomic number of 4, which means it has 4 electrons. Its ground state electronic configuration is \(1s^{2}2s^{2}\). Since the electronic configuration does not violate any rules of atomic structure, Be atom can indeed exist. 2. Consider Be2+ ion: To determine the existence of the Be2+ ion, we need to draw its molecular orbital diagram and examine its stability. The molecular orbital diagram for the Be2+ ion would include: - Two 1s orbitals (one from each Be atom) overlapping to form a sigma1s bonding orbital and a sigma*1s antibonding orbital. - Two 2s orbitals (one from each Be atom) overlapping to form a sigma2s bonding orbital and a sigma*2s antibonding orbital. The 9 electrons in Be2+ would fill the molecular orbitals in the following order: 1. Two electrons fill the sigma1s bonding orbital. 2. Two electrons fill the sigma*1s antibonding orbital. 3. Two electrons fill the sigma2s bonding orbital. 4. One electron fills the sigma*2s antibonding orbital (leaving one unpaired electron). The bond order for Be2+ ion is: \(\frac{(2 - 2)}{2} = 0\) Since the bond order of Be2+ is zero, this means that there is no net bond between the two Be atoms. Therefore, Be2+ is not expected to exist according to molecular orbital theory as it is not stable due to the presence of the unpaired electron and zero bond order. In conclusion, while Be can exist, Be2+ is not expected to exist according to the molecular orbital theory.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bond Length
Bond length is an important concept in chemistry that describes the distance between the nuclei of two bonded atoms. It is influenced by the type of chemical bond between the atoms. When two atoms form a bond, they achieve a balance between the attractive forces, which are due to the sharing of electrons, and the repulsive forces, which come from the positively charged atomic nuclei.

A higher bond order, which indicates more shared electrons between atoms, typically results in a shorter bond length. This is because the increased electron density pulls the atomic nuclei closer together, strengthening the bond. Conversely, a lower bond order often leads to a longer bond length, as the nuclei are not pulled as tightly together. Understanding bond length is crucial for determining the characteristics of the molecule, such as its size and shape. - **Higher Bond Order**: Shorter bond length - **Lower Bond Order**: Longer bond length These relationships help predict the stability and reactivity of molecules, providing insights into how molecules interact with one another.
Bond Energy
Bond energy is the measure of the energy required to break a chemical bond between two atoms, indicating the strength of that bond. The stronger the bond, the more energy will be needed to break it. Bond energy is a direct reflection of the bond order; a higher bond order means that more electrons are involved in bonding, thus creating a stronger bond that takes more energy to break.

Energy is needed to overcome the attraction between the bonded atoms' shared electrons and their positively charged nuclei. When bond energy is high, it suggests the bond is stable and the molecule is less reactive. Conversely, lower bond energy indicates a weaker bond, often leading to greater reactivity as bonds are more easily broken. The relationship is as follows: - **Higher Bond Order**: Higher bond energy - **Lower Bond Order**: Lower bond energy Understanding bond energy is important not only for predicting reactivity but also for practical applications such as energy release in combustion reactions or stability in drug molecules.
Molecular Orbital Theory
Molecular Orbital Theory (MOT) is a fundamental concept in chemistry that explains how atoms bond by considering the formation of molecular orbitals. Unlike simple atomic orbitals which belong to individual atoms, molecular orbitals are spread over a molecule and belong to the molecule as a whole.

This theory helps to explain the existence or non-existence of molecules like \(Be\) or \(Be_{2}^{+}\). According to MOT, electrons in molecules occupy molecular orbitals that are either bonding (which help to hold the atoms together) or antibonding (which can weaken or break a bond). The bond order is calculated by taking the number of electrons in bonding orbitals minus the number in antibonding orbitals, divided by two.

For a species like \(Be_{2}^{+}\), the molecular orbital diagram shows that the bond order is zero. This means there is no effective bond present, rendering the molecule unstable and hence, it is not expected to exist:- **Bond Order Calculation**: \(\frac{(number\ of\ bonding\ electrons - number\ of\ antibonding\ electrons)}{2}\)- **Be_{2}^{+} Example**: Bond order is 0Molecular Orbital Theory provides a more nuanced and accurate picture of bonding compared to other models (like the valence bond theory), especially for molecules with unusual bonding or those that are ionically charged.

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Most popular questions from this chapter

(a) What does the term paramagnetism mean? (b) How can one determine experimentally whether a substance is paramagnetic? (c) Which of the following ions would you expect to be paramagnetic: \(\mathrm{O}_{2}^{+}, \mathrm{N}_{2}{ }^{2-}, \mathrm{Li}_{2}^{+}, \mathrm{O}_{2}^{2-} ?\) For those ions that are paramagnetic, determine the number of unpaired electrons.

The structure of borazine, \(\mathrm{B}_{3} \mathrm{~N}_{3} \mathrm{H}_{6},\) is a six-membered ring of alternating \(\mathrm{B}\) and \(\mathrm{N}\) atoms. There is one \(\mathrm{H}\) atom bonded to each \(B\) and to each \(\mathrm{N}\) atom. The molecule is planar. (a) Write a Lewis structure for borazine in which the formal charge on every atom is zero. (b) Write a Lewis structure for borazine in which the octet rule is satisfied for every atom. (c) What are the formal charges on the atoms in the Lewis structure from part (b)? Given the electronegativities of \(B\) and \(N,\) do the formal charges seem favorable or unfavorable? (d) Do either of the Lewis structures in parts (a) and (b) have multiple resonance structures? (e) What are the hybridizations at the \(\mathrm{B}\) and \(\mathrm{N}\) atoms in the Lewis structures from parts (a) and (b)? Would you expect the molecule to be planar for both Lewis structures? (f) The six \(\mathrm{B}-\mathrm{N}\) bonds in the borazine molecule are all identical in length at \(144 \mathrm{pm} .\) Typical values for the bond lengths of \(\mathrm{B}-\mathrm{N}\) single and double bonds are \(151 \mathrm{pm}\) and \(131 \mathrm{pm},\) respectively. Does the value of the \(\mathrm{B}-\mathrm{N}\) bond length seem to favor one Lewis structure over the other? (g) How many electrons are in the \(\pi\) system of botazine?

Would you expect the nonbonding electron-pair domain in \(\mathrm{NCl}_{3}\) to be greater or smaller in size than the corresponding one in \(\mathrm{PCl}_{3} ?\)

Dichloroethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{Cl}_{2}\right)\) has three forms (isomers), each of which is a different substance. (a) Draw Lewis structures of the three isomers, all of which have a carbon-carbon double bond. \((\mathbf{b})\) Which of these isomers has a zero dipole moment? (c) How many isomeric forms can chloroethylene, \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}\), have? Would thev be expected to have dipole moments?

Draw sketches illustrating the overlap between the following orbitals on two atoms: (a) the \(2 s\) orbital on each atom, (b) the \(2 p_{z}\) orbital on each atom (assume both atoms are on the \(z\) -axis), \((\mathbf{c})\) the 2 s orbital on one atom and the \(2 p_{2}\) orbital on the other atom.

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