Chapter 9: Problem 52
What is the hybridization of the central atom in (a) \(\mathrm{PBr}_{5}\), (b) \(\mathrm{CH}_{2} \mathrm{O},\) (c) \(\mathrm{O}_{3},(\mathbf{d}) \mathrm{NO}_{2} ?\)
Short Answer
Expert verified
The hybridization of the central atoms in the given molecules are as follows:
(a) \( PBr_5 \): sp3d
(b) \( CH_2O \): sp2
(c) \( O_3 \): sp3
(d) \( NO_2 \): sp2
Step by step solution
01
Determining the central atom
For each of the molecules, we need to identify the central atom which is the atom that is the least electronegative and has the highest connectivity to other atoms:
(a) PBr5: Phosphorus (P) is the central atom
(b) CH2O: Carbon (C) is the central atom
(c) O3: Oxygen (O) is the central atom
(d) NO2: Nitrogen (N) is the central atom
02
Calculate the electron domains
For each central atom, calculate the number of electron domains which is the sum of its bonds and lone pairs of electrons.
(a) PBr5: Phosphorus (P) has 5 bonds (one with each Br atom) and no lone pairs. So, electron domains = 5.
(b) CH2O: Carbon (C) has 2 bonds (one with each H atom) and 1 double bond (with the O atom). So, electron domains = 3.
(c) O3: Oxygen (O) has 4 electron domains. Two of them are bonds with Z type atoms (the other two O atoms) and two lone pairs.
(d) NO2: Nitrogen (N) has three electron domains: 1 double bond (with one O atom), 1 single bond (with the other O atom), and 1 unpaired electron (odd electron species). So, electron domains = 3.
03
Determine the Hybridization
Based on the number of electron domains, we can determine the hybridization of each central atom.
(a) PBr5: 5 electron domains correspond to sp3d hybridization.
(b) CH2O: 3 electron domains correspond to sp2 hybridization.
(c) O3: 4 electron domains correspond to sp3 hybridization.
(d) NO2: 3 electron domains correspond to sp2 hybridization.
To conclude, the hybridization of the central atoms in the given molecules are as follows:
(a) PBr5: sp3d
(b) CH2O: sp2
(c) O3: sp3
(d) NO2: sp2
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Domains
When discussing chemical hybridization, the concept of electron domains is incredibly important. Electron domains encapsulate the regions around a central atom where electrons are predominantly located. These include both bonds (single, double, or triple) and lone electron pairs.
- For example, if a central atom forms two single bonds and has one lone pair, it has three electron domains in total.
- Each bond counts as one electron domain, regardless of its type (single or multiple).
- Lone pairs of electrons also contribute a domain each.
- 3 electron domains align with an sp2 hybridization.
- 5 electron domains align with an sp3d hybridization.
Central Atom
The central atom in a molecule is a key player in determining molecular geometry and hybridization. It is typically the atom with the lowest electronegativity, making it capable of forming more bonds with other atoms in the molecule.
- In a polyatomic molecule, the central atom is most likely to be bonded to multiple atoms around it.
- For instance, in the \(\mathrm{PBr}_{5}\) molecule, phosphorus (P) is the central atom because it can connect with all five bromine atoms.
- The central atom serves as the backbone for understanding the full molecular structure.
- It impacts the molecular stability and reactivity based on electronegativity and atomic size.
Molecular Geometry
Molecular geometry is the three-dimensional arrangement of atoms within a molecule. This spatial configuration results from the number and type of electron domains around the central atom. Understanding molecular geometry is critical because it reveals the overall shape of the molecule, which affects its chemical and physical properties.
- For example, a molecule like \(\mathrm{CH}_{2} \mathrm{O}\) with \(\mathrm{sp}^{2}\) hybridization results in a trigonal planar geometry.
- In contrast, \(\mathrm{PBr}_{5}\) with \(\mathrm{sp}^{3}\ d\) hybridization forms a trigonal bipyramidal geometry.
- Linear, trigonal, and tetrahedral are just a few examples of potential geometrical outcomes.
- Each shape has defined bond angles, helping predict molecule interaction with other entities.