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For each statement, indicate whether it is true or false. (a) The greater the orbital overlap in a bond, the weaker the bond. (b) The greater the orbital overlap in a bond, the shorter the bond. \((\mathbf{c})\) To create a hybrid orbital, you could use the \(s\) orbital For each statement, indicate whether it is true or false. (a) The greater the orbital overlap in a bond, the weaker the bond. (b) The greater the orbital overlap in a bond, the shorter the bond. \((\mathbf{c})\) To create a hybrid orbital, you could use the \(s\) orbital

Short Answer

Expert verified
(a) False: Greater overlap results in a stronger bond. (b) True: Greater overlap leads to shorter bond lengths. (c) True: An s orbital can be used to create hybrid orbitals, such as sp, sp2, or sp3.

Step by step solution

01

Statement (a): The greater the orbital overlap in a bond, the weaker the bond.

False. The greater the orbital overlap in a bond, the stronger the bond. This is because increased overlap between atomic orbitals allows for more effective sharing of electrons, resulting in a stronger bond.
02

Statement (b): The greater the orbital overlap in a bond, the shorter the bond.

True. A larger orbital overlap results in a stronger bond, and stronger bonds are generally shorter in bond length. When orbitals overlap more effectively, the electrons shared between them can be more tightly held, thus leading to a shorter bond.
03

Statement (c): To create a hybrid orbital, you could use the s orbital.

True. Hybrid orbitals are formed by combining different types of atomic orbitals, such as s, p, and d orbitals. An s orbital can be combined with a p orbital to create sp, sp2, or sp3 hybrid orbitals, which are used in bonding in various molecular geometries.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Orbital Overlap
One of the key concepts in chemical bonding is orbital overlap. Orbital overlap happens when atomic orbitals on two different atoms overlap to form a bond. The degree of overlap directly impacts the strength and length of the bond. To visualize, think about atomic orbitals as clouds where electrons reside. When these clouds "merge" or overlap, electrons are shared between the two atoms.
  • Greater overlap means more electron sharing, leading to a stronger bond.
  • Stronger bonds generally result in shorter bond lengths.
To sum up, more overlap means stronger and often shorter bonds, as electrons are more effectively shared which enhances the hold between the atoms.
Hybrid Orbitals
Hybrid orbitals help explain the shapes and bonding in complex molecules. They are formed by merging different atomic orbitals on the same atom. For example, an s and a p orbital can hybridize to create new orbitals like sp, sp2, or sp3. This mixing allows atoms to form the equivalent number of bonds with equal strength and helps maintain the structural integrity of molecules.
  • Sp hybrids result from one s and one p orbital and form linear structures.
  • Sp2 hybrids result from one s and two p orbitals forming trigonal planar shapes.
  • Sp3 hybrids emerge from one s and three p orbitals creating tetrahedral structures.
Because hybrid orbitals allow for different spatial arrangements, they impact how molecules interact, react, and adopt complex structures.
Bond Strength
Bond strength is influenced by how tightly atoms are held together in a molecule. Two main factors affect bond strength:
  • Extent of orbital overlap – More overlap equals a stronger bond.
  • Electronegativity of the atoms – More electronegative atoms can pull shared electrons closer, adding to bond strength.
Stronger bonds have higher bond dissociation energies, meaning they require more energy to break. By understanding bond strength, it's easier to predict the stability of molecules and explain their chemical reactivity.
In molecular chemistry, knowing the strength of bonds helps chemists design new compounds and anticipate how molecules might behave in different environments.

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Most popular questions from this chapter

(a) Sketch the molecular orbitals of the \(\mathrm{H}_{2}^{-}\) ion and draw its energy-level diagram. (b) Write the electron configuration of the ion in terms of its MOs. (c) Calculate the bond order in \(\mathrm{H}_{2}^{-}\). (d) Suppose that theion is excited by light, sothat an electron moves from a lower-energy to a higher-energy molecular orbital. Would you expect the excited-state \(\mathrm{H}_{2}^{-}\) ion to be stable? (e) Which of the following statements about part (d) is correct: (i) The light excites an electron from a bonding orbital to an antibonding orbital, (ii) The light excites an electron from an antibonding orbital to a bonding orbital, or (iii) In the excited state there are more bonding electrons than antibonding electrons?

(a) Does \(C S_{2}\) have a dipole moment? If so, in which direction does the net dipole point? (b) Does \(\mathrm{SO}_{2}\) have a dipole moment? If so, in which direction does the net dipole point?

(a) Draw Lewis structures for chloromethane \(\left(\mathrm{CH}_{3} \mathrm{Cl}\right),\) chloroethene \(\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}\right)\), and chloroethyne \(\left(\mathrm{C}_{2} \mathrm{HCl}\right) .(\mathbf{b})\) What is the hybridization of the carbon atoms in each molecule? (c) Predict which molecules, if any, are planar. (d) How many \(\sigma\) and \(\pi\) bonds are there in each molecule?

The following is part of a molecular orbital energy-level diagram for MOs constructed from 1 s atomic orbitals. (a) What labels do we use for the two MOs shown? (b) For which of the following molecules or ions could this be the energy-level diagram: $$ \mathrm{H}_{2} \mathrm{He}_{2}, \mathrm{H}_{2}^{+}, \mathrm{He}_{2}^{+}, \mathrm{or} \mathrm{H}_{2}^{-} ? $$ (c) What is the bond order of the molecule or ion? (d) If an electron is added to the system, into which of the MOs will it be added? [Section 9.7\(]\)

In which of the following AF \(_{n}\) molecules or ions is there more than one \(\mathrm{F}-\mathrm{A}-\mathrm{F}\) bond angle: \(\mathrm{PF}_{6}^{-}, \mathrm{SbF}_{\mathrm{s}}, \mathrm{SF}_{4} ?\)

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