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In which of the following AF \(_{n}\) molecules or ions is there more than one \(\mathrm{F}-\mathrm{A}-\mathrm{F}\) bond angle: \(\mathrm{PF}_{6}^{-}, \mathrm{SbF}_{\mathrm{s}}, \mathrm{SF}_{4} ?\)

Short Answer

Expert verified
The molecular geometry of each molecule/ion is as follows: 1. PF6-: Octahedral 2. SbFs: Trigonal bipyramidal 3. SF4: Seesaw or distorted tetrahedral All three molecules or ions, PF6-, SbFs, and SF4, have more than one F-A-F bond angle.

Step by step solution

01

1. PF6-

Phosphorus (P) has 5 valence electrons and Fluorine (F) has 7 valence electrons. The PF6- ion has 5+6(7)+1(extra electron) = 48 electrons. In this complex, P is the central atom, surrounded by 6 fluorine atoms. To minimize the repulsion between electron pairs, the molecular geometry of PF6- will be an octahedral, with 6 F-A (P-F) bonds. This structure will have several F-P-F angles of 90 and 180 degrees. Therefore, PF6- has more than one F-A-F bond angle.
02

₂. SbFs

Antimony (Sb) has 5 valence electrons, and Fluorine (F) has 7 valence electrons. The overall molecule has 5+5(7) = 40 electrons. In this molecule, Sb is the central atom, surrounded by 5 fluorine atoms. To minimize the repulsion between electron pairs, the molecular geometry of SbFs is trigonal bipyramidal, with 5 F-A (Sb-F) bonds. SbFs has 3 equatorial (F-Sb-F) angles equal to 120 degrees (at the central plane), and 2 axial (F-Sb-F) angles equal to 180 degrees, perpendicular to the central plane. Therefore, there are multiple F-A-F bond angles in SbFs.
03

₃. SF4

Sulfur (S) has 6 valence electrons and Fluorine (F) has 7 valence electrons. In the SF4 molecule, there are 6+4(7) = 34 electrons. In this molecule, S is the central atom, surrounded by 4 fluorine atoms with one lone pair on S. The molecular geometry of SF4 is called seesaw or distorted tetrahedral. The SF4 molecule has two S-F bond angles in the equatorial plane, equal to 120 degrees; and on each of two axial positions perpendicular (F-S-F) to the central plane, the angle is 180 degrees. Thus, there are more than one F-A-F bond angles in SF4. All three molecules or ions, PF6-, SbFs, and SF4, have more than one F-A-F bond angle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Geometry
Molecular geometry refers to the three-dimensional arrangement of atoms within a molecule. It plays a crucial role in determining the molecule's properties, such as reactivity, polarity, and phase of matter. Understanding molecular geometry allows us to predict the angles between atoms and how they influence molecular interactions.
To determine the molecular geometry, we use the Valence Shell Electron Pair Repulsion Theory (VSEPR). This theory suggests that electron pairs around a central atom arrange themselves to minimize repulsion. For instance, the molecule \( \text{PF}_6^- \) exhibits octahedral geometry, with the phosphorus atom at the center surrounded symmetrically by six fluorine atoms. This results in optimal spacing of electron pairs, reducing repulsion.
In contrast, \( \text{SbF}_5 \) has a trigonal bipyramidal structure, where three fluorine atoms are located in the equatorial plane with bond angles near 120 degrees, while two fluorines are axially positioned, creating 180-degree angles with the central atom. In \( \text{SF}_4 \), the presence of a lone pair forces the molecule into a "seesaw" or distorted tetrahedral shape, influencing the bond angles due to the extra repulsion from the lone pair.
Valence Electrons
Valence electrons are the outermost electrons of an atom and are crucial in forming chemical bonds. In VSEPR Theory, the number of valence electrons informs the arrangement of atoms in a molecule by determining how electron pairs (bonding and lone pairs) will orient themselves in space.
  • In \( \text{PF}_6^- \), phosphorus contributes 5 valence electrons, with each fluorine contributing 7, and an extra electron adds up to 48 electrons in total, influencing the molecular shape.
  • Antimony in \( \text{SbF}_5 \) brings in 5 valence electrons, with each fluorine atom having 7. Collectively, 40 electrons dictate the molecule's trigonal bipyramidal shape.
  • For \( \text{SF}_4 \), sulfur's 6 valence electrons, combined with those from four fluorine atoms, total 34 electrons, resulting in its unique "seesaw" geometry.
By understanding valence electrons, we can predict how atoms bond and the resulting molecular geometry, guiding how molecules interact with each other.
Bond Angles
Bond angles are the angles formed between adjacent bonds at an atom, and they're crucial for defining molecular shape and behavior. Different molecular geometries result in varying bond angles, which can influence physical and chemical properties.
In molecules like \( \text{PF}_6^- \), the octahedral geometry creates bond angles of 90 degrees between adjacent fluorine atoms and 180 degrees across the phosphorus atom. This symmetrical structure helps minimize the repulsion between electron pairs, achieving stability.
The trigonal bipyramidal arrangement in \( \text{SbF}_5 \) results in 120-degree angles between equatorial bonds and 180-degree angles between axial bonds. This asymmetry gives \( \text{SbF}_5 \) its distinct geometric properties.
In \( \text{SF}_4 \), with its seesaw shape, the lone pair slightly distorts bond angles from the idealized values. Bonds within the equatorial plane measure approximately 120 degrees, while those in the axial position are around 180 degrees, influenced by the lone electron pair's repulsion. Understanding these angles is crucial for predicting molecular behavior and interactions.

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Most popular questions from this chapter

Dichloroethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{Cl}_{2}\right)\) has three forms (isomers), each of which is a different substance. (a) Draw Lewis structures of the three isomers, all of which have a carbon-carbon double bond. \((\mathbf{b})\) Which of these isomers has a zero dipole moment? (c) How many isomeric forms can chloroethylene, \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}\), have? Would thev be expected to have dipole moments?

(a) The \(\mathrm{PH}_{3}\) molecule is polar. Does this offer experimental proof that the molecule cannot be planar? Explain. (b) It turns out that ozone, \(\mathrm{O}_{3}\), has a small dipole moment. How is this possible, given that all the atoms are the same?

In the sulphate ion, \(\mathrm{SO}_{4}^{2-}\), the sulphur atom is the central atom with the other 4 oxygen atoms attached to it. (a) Draw a Lewis structure for the sulphate ion. (b) What hybridization is exhibited by the \(\mathrm{S}\) atom? (c) Are there multiple equivalent resonance structures for the ion? (d) How many electrons are in the \(\pi\) system of the ion?

Draw the Lewis structure for each of the following molecules or ions, and predict their electron-domain and molecular geometries: (a) \(\mathrm{AsF}_{3}\) (b) \(\mathrm{CH}_{3}^{+},(\mathbf{c}) \mathrm{Br} \mathrm{F}_{3}\) (d) \(\mathrm{ClO}_{3}^{-}\) (e) \(\mathrm{XeF}_{2}\) (f) \(\mathrm{BrO}_{2}^{-}\).

Describe the bond angles to be found in each of the follow- ing molecular structures: (a) trigonal planar, \((\mathbf{b})\) tetrahedral, (c) octahedral, (d) linear.

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