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State whether each of these statements is true or false. (a) An oxygen-oxygen double bond is shorter than an oxygenoxygen single bond. (b) There are three lone pair electrons in the \(\mathrm{NH}_{3}\) molecule. (c) The \(\mathrm{C}-\mathrm{C}\) bond in ethene is longer than the \(\mathrm{C}-\mathrm{C}\) bond in polyethene. (d) The \(\mathrm{C}-\mathrm{Cl}\) bond is shorter than the \(\mathrm{C}-\mathrm{Br}\) bond. \((\mathbf{e})\) The greater the difference in the electronegativity of atoms in a bond, the stronger the bond.

Short Answer

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(a) True (b) False (c) True (d) True (e) False

Step by step solution

01

Statement (a) - Oxygen-oxygen double bond and single bond

To determine whether an oxygen-oxygen double bond is shorter than an oxygen-oxygen single bond, we consider the fact that double bonds involve the sharing of more electrons between the bonded atoms. This leads to a higher electron density and stronger electrostatic attraction between the nuclei and the bonding electrons. As a result, double bonds are generally shorter and stronger than single bonds. Hence, the statement (a) is true.
02

Statement (b) - Lone pair electrons in NH3 molecule

The NH3 molecule has one nitrogen atom and three hydrogen atoms. Nitrogen has 5 valence electrons and each hydrogen atom contributes 1 electron. The nitrogen atom forms three single bonds with the three hydrogen atoms, using 3 of its 5 valence electrons. The remaining 2 electrons form a lone pair on the nitrogen atom. This means there is only one lone pair of electrons in the NH3 molecule. Thus, statement (b) is false.
03

Statement (c) - C-C bond in ethene and polyethene

Ethene has a carbon-carbon double bond, while polyethene has carbon-carbon single bonds. As previously discussed, double bonds are generally shorter and stronger than single bonds due to a higher electron density and stronger electrostatic attraction. Therefore, the C-C bond in ethene is shorter than the C-C bond in polyethene. Statement (c) is true.
04

Statement (d) - C-Cl and C-Br bond lengths

The bond length between two atoms is influenced by their atomic size. Generally, as you move down a group in the periodic table, the atomic size increases. Chlorine is above bromine in the periodic table, so it is smaller in size than bromine. As a result, the C-Cl bond is shorter than the C-Br bond. Statement (d) is true.
05

Statement (e) - Bond strength and electronegativity difference

The electronegativity of an atom is its ability to attract electrons in a bond. A bond formed between two atoms with a large electronegativity difference is polar and has a significant amount of ionic character. Such bonds are generally stronger than non-polar bonds. However, this statement is not universally true, as bond strength will also depend on other factors such as the size of the atoms and electron configuration. Therefore, statement (e) is false. In conclusion: - Statement (a) is true - Statement (b) is false - Statement (c) is true - Statement (d) is true - Statement (e) is false

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bond Length
Bond length refers to the average distance between the nuclei of two bonded atoms. The strength of this connection varies depending on several factors, primarily the type of bond: single, double, or triple.
A double bond involves more shared electrons than a single bond, leading to a higher electron density. This increased electron density results in a shorter and stronger bond because the attraction between the bonded nuclei and electrons is greater.
For instance, in the exercise's statement (a), an oxygen-oxygen double bond is indeed shorter than an oxygen-oxygen single bond. This is because double bonds share more electrons and thus, cause the atoms to stay closer together, which reduces the bond length.
  • This principle applies to all covalent bonds: as the number of shared electron pairs increases, the bond length decreases.
  • Besides, bond length is also influenced by the size of the atoms: the smaller the atomic radii, the shorter the bond length.
Electronegativity
Electronegativity is a measure of how strongly an atom can attract electrons towards itself in a chemical bond. Each element has a unique electronegativity value, which provides insight into the bond's nature.
Typically, bonds between atoms with a large difference in electronegativity exhibit a greater tendency towards ionic characteristics, resulting in a polar bond. In general, the more polar the bond, the stronger it is due to the electrostatic attractions between the charged atoms.
However, electronegativity alone does not determine bond strength, contrary to statement (e) in the exercise, which is false. Bond strength also depends on factors like:
  • The bond type (single, double, or triple).
  • Atomic size, since larger atoms generally form weaker bonds.
Understanding electronegativity is crucial when predicting molecular interactions and the behavior of different compounds.
Lone Pair Electrons
Lone pair electrons, also known as non-bonding pairs, are valence electrons not shared with another atom. They play a critical role in the shape and reactivity of molecules.
In the NH extsubscript{3} molecule example, nitrogen uses three of its five valence electrons to form single bonds with three hydrogen atoms. The remaining two electrons form a lone pair. So, statement (b) in the exercise is false, as there is only one lone pair.
  • Lone pairs affect molecular geometry by repelling other electron pairs, leading to specific shapes according to VSEPR theory.
  • They also influence physical properties and reactivity, as lone pairs can participate in chemical reactions or influence polar characteristics.
Lone pairs are pivotal for understanding advanced bonding concepts and analyzing chemical behaviors.

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Most popular questions from this chapter

Trifluoroacetic acid has the chemical formula \(\mathrm{CF}_{3} \mathrm{CO}_{2} \mathrm{H}\). It is a colorless liquid that has a density of \(1.489 \mathrm{~g} / \mathrm{mL}\). (a) Trifluoroacetic acid contains one \(\mathrm{CF}_{3}\) unit and is connected to the other \(\mathrm{C}\) atom which bonds with both O's. Draw the Lewis structure for trifluoroacetic acid. (b) Trifluoroacetic acid can react with \(\mathrm{NaOH}\) in aqueous solution to produce the trifluoroacetate ion, \(\mathrm{CF}_{3} \mathrm{COO}^{-}\). Write the balanced chemical equation for this reaction. (c) Draw the Lewis structure of the trifluoroacetate ion, showing resonance if present. (d) How many milliliters of a \(0.500 \mathrm{M}\) solution of \(\mathrm{NaOH}\) would it take to neutralize \(10.5 \mathrm{~mL}\) of trifluoroacetic acid?

For Group 13-17 elements in the third row of the periodic table and beyond, the octet rule is often not obeyed. A friend of yours says this is because these heavier elements are more likely to make double or triple bonds. Another friend of yours says that this is because the heavier elements are larger and can make bonds to more than four atoms at a time. Which friend is more correct?

In the vapor phase, \(\mathrm{BeCl}_{2}\) exists as a discrete molecule. (a) Draw the Lewis structure of this molecule, using only single bonds. Does this Lewis structure satisfy the octet rule? (b) What other resonance structures are possible that satisfy the octet rule? (c) On the basis of the formal charges, which Lewis structure is expected to be dominant for \(\mathrm{BeCl}_{2}\) ?

(a) Draw the Lewis structure for hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\). (b) What is the weakest bond in hydrogen peroxide? (c) Hydrogen peroxide is sold commercially as an aqueous solution in brown bottles to protect it from light. Calculate the longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide.

Ammonia reacts with boron trifluoride to form a stable compound, as we saw in Section 8.7. (a) Draw the Lewis structure of the ammonia-boron trifluoride reaction product. \((\mathbf{b})\) The \(\mathrm{B}-\mathrm{N}\) bond is obviously more polar than the C-C bond. Draw the charge distribution you expect on the \(\mathrm{B}-\mathrm{N}\) bond within the molecule (using the delta plus and delta minus symbols mentioned in Section 8.4 ). (c) Boron trichloride also reacts with ammonia in a similar way to the trifluoride. Predict whether the \(\mathrm{B}-\mathrm{N}\) bond in the trichloride reaction product would be more or less polar than the \(\mathrm{B}-\mathrm{N}\) bond in the trifluoride product, and justify your reasoning.

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