Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) What is the trend in electronegativity going from left to right in a row of the periodic table? (b) How do electronegativity values generally vary going down a column in the periodic table? (c) True or false: The most easily ionizable elements are the most electronegative.

Short Answer

Expert verified
(a) The trend in electronegativity going from left to right in a row of the periodic table is that it increases due to an increased positive charge of the nucleus. (b) Electronegativity values generally decrease going down a column in the periodic table because of the increased shielding effect. (c) False: The most easily ionizable elements are not the most electronegative; in fact, they are less electronegative since they have lower ionization energy.

Step by step solution

01

Part (a): Trend in electronegativity going from left to right in a row

Electronegativity is the tendency of an atom to attract a bonding pair of electrons towards itself. As we move from left to right across a period in the periodic table, the number of protons in the nucleus increases, so the positive charge of the nucleus increases. Due to this increase in nuclear charge, the valence electrons are attracted more toward the nucleus and this leads to an increase in electronegativity. Hence, the trend in electronegativity from left to right in a row is that it increases.
02

Part (b): Variation of electronegativity values going down a column

When we go down a group or column in the periodic table, the number of electron shells increases. This results in an increased shielding effect, where the inner electron shells shield the outer valence electrons from the nucleus's positive charge. Due to this shielding effect, the attraction of valence electrons towards the nucleus decreases, and hence the electronegativity decreases. So, the electronegativity values generally decrease going down a column in the periodic table.
03

Part (c): Ionization energy and electronegativity relationship

Ionization energy is the amount of energy required to remove an electron from a neutral atom in its gaseous state. An element with high ionization energy requires more energy to remove an electron, indicating that the electron is held more tightly by the atom, and hence the atom has a higher tendency to attract electrons. On the other hand, elements with lower ionization energy can easily lose electrons. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. Elements with high electronegativity have a stronger pull on electrons in a chemical bond due to their high effective nuclear charge. Statement (c) says: "The most easily ionizable elements are the most electronegative." This statement is false. Since elements with higher ionization energy have a stronger pull on electrons, they are more electronegative. In contrast, more easily ionizable elements, which have lower ionization energy, are less electronegative.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Periodic Table Trends
The periodic table is designed to showcase elements and their increasing atomic numbers, revealing several patterns known as periodic table trends. One important trend is electronegativity, which reflects how strongly an atom can attract and hold onto electrons. As you move from left to right across a period on the periodic table, the atomic number rises, increasing the nuclear charge. This means that the nucleus has more protons and a greater pull on the electrons. As a result, the electronegativity of the elements tends to increase across a period.

Similarly, when moving down a group, electronegativity usually decreases. This occurs because additional electron shells are added, which places the valence electrons farther from the nucleus where they are less strongly attracted to it. Understanding these trends helps predict how different elements might behave in chemical reactions.
Ionization Energy
Ionization energy is an essential concept in chemistry, representing the energy needed to remove an electron from an atom. Generally, as you move across a period from left to right, ionization energy increases. This is due to the increase in nuclear charge, which means that electrons are more strongly attracted and are harder to remove.

On the other hand, as you move down a column in the periodic table, ionization energy decreases. This is primarily because of electron shielding: additional electron shells shield the valence electrons from the nucleus, making them easier to remove. High ionization energy often corresponds with high electronegativity because both relate to how strongly an atom holds onto its electrons.
Electron Shielding
Electron shielding is a phenomenon that occurs when inner electron shells block the positive charge of the nucleus from the outer valence electrons. This effect makes it so that the pull the nucleus has on valence electrons is reduced, which can influence an atom's electronegativity and ionization energy.

As you progress down a group in the periodic table, electron shielding increases because there are more electron shells. This increased shielding means that outer electrons are less tightly bound to the nucleus. This explains why atoms typically have lower electronegativity and ionization energy as you move down a group, making them more likely to lose electrons in reactions.
Nuclear Charge
Nuclear charge is a key concept in understanding the behavior of elements within the periodic table. It is defined by the number of protons in an atom's nucleus, determining how strongly the nucleus can attract electrons. As you move across a period from left to right, the nuclear charge increases since each successive element has one more proton.

This increase in nuclear charge generally leads to a higher electronegativity, as atoms are able to attract bonding electrons more effectively. It also results in higher ionization energy, as electrons are held more tightly and are harder to remove. Understanding nuclear charge helps in explaining many chemical properties and reactivity patterns of elements.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Trifluoroacetic acid has the chemical formula \(\mathrm{CF}_{3} \mathrm{CO}_{2} \mathrm{H}\). It is a colorless liquid that has a density of \(1.489 \mathrm{~g} / \mathrm{mL}\). (a) Trifluoroacetic acid contains one \(\mathrm{CF}_{3}\) unit and is connected to the other \(\mathrm{C}\) atom which bonds with both O's. Draw the Lewis structure for trifluoroacetic acid. (b) Trifluoroacetic acid can react with \(\mathrm{NaOH}\) in aqueous solution to produce the trifluoroacetate ion, \(\mathrm{CF}_{3} \mathrm{COO}^{-}\). Write the balanced chemical equation for this reaction. (c) Draw the Lewis structure of the trifluoroacetate ion, showing resonance if present. (d) How many milliliters of a \(0.500 \mathrm{M}\) solution of \(\mathrm{NaOH}\) would it take to neutralize \(10.5 \mathrm{~mL}\) of trifluoroacetic acid?

A common form of elemental phosphorus is the white phosphorus, where four \(\mathrm{P}\) atoms are arranged in a tetrahedron. All four phosphorus atoms are equivalent. White phosphorus reacts spontaneously with the oxygen in air to form \(\mathrm{P}_{4} \mathrm{O}_{6} .\) (a) How many valance electron pairs are in the \(\mathrm{P}_{4} \mathrm{O}_{6}\) molecule? (b) When \(\mathrm{P}_{4} \mathrm{O}_{6}\) is dissolved in water, it produces a \(\mathrm{H}_{3} \mathrm{PO}_{3}\), molecule. \(\mathrm{H}_{3} \mathrm{PO}_{3}\) has two forms, \(\mathrm{P}\) forms 3 covalent bonds in the first form and \(\mathrm{P}\) forms 5 covalent bonds in the second form. Draw two possible Lewis structures of \(\mathrm{H}_{3} \mathrm{PO}_{3}\). (c) Which structure obeys the octet rule?

(a) Use Lewis symbols to represent the reaction that occurs between Li and O atoms. (b) What is the chemical formula of the most likely product? (c) How many electrons are transferred? (d) Which atom loses electrons in the reaction?

(a) True or false: An element's number of valence electrons is the same as its atomic number. (b) How many valence electrons does a nitrogen atom possess? (c) An atom has the electron configuration \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2} .\) How many valence electrons does the atom have?

Draw the Lewis structures for each of the following ions or molecules. Identify those in which the octet rule is not obeyed; state which atom in each compound does not follow the octet rule; and state, for those atoms, how many electrons surround them: \((\mathbf{a}) \mathrm{HCl},(\mathbf{b}) \mathrm{ICl}_{5},\) (c) \(\mathrm{NO}\) (d) \(\mathrm{CF}_{2} \mathrm{Cl}_{2},(\mathbf{e}) \mathrm{I}_{3}^{-}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free