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In the chemical process called electron transfer, an electron is transferred from one atom or molecule to another. (We will talk about electron transfer extensively in Chapter 20.) A simple electron transfer reaction is A(g)+A(g)A+(g)+A(g) In terms of the ionization energy and electron affinity of atom A, what is the energy change for this reaction? For a representative nonmetal such as chlorine, is this process exothermic? For a representative metal such as sodium, is this process exothermic?

Short Answer

Expert verified
The energy change for the given electron transfer reaction can be calculated as: Energy change = Ionization energy of A - Electron affinity of A. For chlorine (a representative nonmetal), the process is endothermic with an energy change of 1600 kJ/mol. For sodium (a representative metal), the process is also endothermic with an energy change of 549 kJ/mol. Therefore, the process is not exothermic for both chlorine and sodium.

Step by step solution

01

Define ionization energy and electron affinity

Ionization energy is the energy required to remove an electron from an atom in its gaseous state. Electron affinity is the energy change that occurs when an electron is added to an atom in its gaseous state.
02

Calculate the energy change for the electron transfer reaction

The energy change for the reaction can be determined by considering the ionization energy and electron affinity: Energy change = Ionization energy of A - Electron affinity of A
03

Determine if the process is exothermic for a representative nonmetal (chlorine)

For chlorine (a representative nonmetal), the ionization energy is 1251 kJ/mol and the electron affinity is -349 kJ/mol. Using the energy change equation, we can calculate the energy change for the electron transfer reaction: Energy change = 1251 kJ/mol - (-349 kJ/mol) = 1600 kJ/mol Since the energy change is positive, the process is endothermic for chlorine, not exothermic.
04

Determine if the process is exothermic for a representative metal (sodium)

For sodium (a representative metal), the ionization energy is 496 kJ/mol and the electron affinity is -53 kJ/mol. Using the energy change equation, we can calculate the energy change for the electron transfer reaction: Energy change = 496 kJ/mol - (-53 kJ/mol) = 549 kJ/mol Since the energy change is positive, the process is also endothermic for sodium, not exothermic. In conclusion, the energy change for the electron transfer reaction can be calculated using the ionization energy and electron affinity of atom A. The process is endothermic for both a representative nonmetal (chlorine) and a representative metal (sodium), meaning the process is not exothermic for these examples.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionization Energy
Imagine needing to pack energy into an atom to pry away one of its electrons. This energy is known as ionization energy. It's like the entrance fee needed to pull an electron out from its cozy spot within an atom.
The ionization energy varies across elements. Some atoms tightly hold onto their electrons, demanding a hefty amount, while others surrender their electrons more easily, requiring less energy. Generally, you see higher ionization energy in nonmetals compared to metals.
  • Why is ionization energy important?
    Understanding it helps us predict how an atom behaves in terms of forming ions and compounds. For example, a metal's lower ionization energy is why it's more willing to give up electrons and form positive ions.
Ionization energy is a fundamental concept that shows the inherent nature of elements to resist or yield their electrons based on their chemical environments.
Electron Affinity
Welcoming an electron into an atom's embrace is accompanied by something known as electron affinity. While ionization energy talks about losing electrons, electron affinity deals with gaining them.
It's the change in energy that occurs when an electron is added to a neutral atom. For some elements, this process releases energy, making it exothermic, while for others, it demands energy input, making it endothermic.
  • Key Insights:
    1. Nonmetals typically have a more notable electron affinity as they love gaining electrons to achieve full valence shells.
    2. Metals, on the contrary, often resist addition since they prefer giving away electrons.
When calculating the electron transfer involving electron affinity, you're essentially assessing an element's eagerness or reluctance to adopt a new electron into its fold.
Energy Change in Reactions
When electrons waltz from one atom to another, there's an energy shift occurring behind the scenes. This phenomenon is described as the energy change during reactions.
In the given exercise, the energy dynamics are influenced by both ionization energy (the cost to remove an electron) and electron affinity (the benefit of gaining one). The formula for the energy change in electron transfer is represented as: Energy change=Ionization energy of AElectron affinity of AUsing specific element examples like chlorine and sodium:
  • Chlorine shows a high ionization energy compared to its electron affinity. The positive outcome in energy change calculations shows the process is endothermic.
  • Similarly, sodium's lower electron affinity than its ionization energy also results in endothermic reactions.
Understanding these energy changes enhances predictions about reaction spontaneity and the propensity of particular elemental reactions.

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Most popular questions from this chapter

Which will experience the greater effect nuclear charge, the electrons in the n=2 shell in F or the n=2 shell in B ? Which will be closer to the nucleus?

Consider the A2X4 molecule depicted here, where A and X are elements. The AA bond length in this molecule is d1, and the four AX bond lengths are each d2. (a) In terms of d1 and d2, how could you define the bonding atomic radii of atoms A and X? (b) In terms of d1 and d2, what would you predict for the XX bond length of an X2 molecule? [Section 7.3]

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Mercury in the environment can exist in oxidation states 0, +1, and +2. One major question in environmental chemistry research is how to best measure the oxidation state of mercury in natural systems; this is made more complicated by the fact that mercury can be reduced or oxidized on surfaces differently than it would be if it were free in solution. XPS, X-ray photoelectron spectroscopy, is a technique related to PES (see Exercise 7.111 ), but instead of using ultraviolet light to eject valence electrons, X rays are used to eject core electrons. The energies of the core electrons are different for different oxidation states of the element. In one set of experiments, researchers examined mercury contamination of minerals in water. They measured the XPS signals that corresponded to electrons ejected from mercury's 4 forbitals at 105eV, from an X-ray source that provided 1253.6eV of energy (1ev=1.602×1019 J) The oxygen on the mineral surface gave emitted electron energies at 531eV, corresponding to the 1s orbital of oxygen. Overall the researchers concluded that oxidation states were +2 for Hg and -2 for O. (a) Calculate the wavelength of the X rays used in this experiment. (b) Compare the energies of the 4f electrons in mercury and the 1s electrons in oxygen from these data to the first ionization energies of mercury and oxygen from the data in this chapter. (c) Write out the ground- state electron configurations for Hg2+ and O2; which electrons are the valence electrons in each case?

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