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Give examples of transition metal ions with +3 charge that have an electron configuration of \(n d^{5}(n=3,4,5 \ldots)\).

Short Answer

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The transition metal ions with +3 charge that have an electron configuration of the form nd^5 are: 1. Mn^3+ (Manganese) with an electron configuration of [Ar] \(3d^5\). 2. Tc^3+ (Technetium) with an electron configuration of [Kr] \(4d^5\). 3. Re^3+ (Rhenium) with an electron configuration of [Xe] \(5d^5\).

Step by step solution

01

Identify the electron configuration of the neutral transition metal atoms

Before looking for the ions, it is necessary to determine the electron configurations for neutral transition metal atoms. In this case, we need the metal atoms that have their highest energy electrons in the d orbitals and follow the order of the periodic table.
02

Determine the +3 charged ions' electron configurations

Now that we know the electron configurations of the transition metal atoms, we'll consider their ions with a +3 charge by removing three electrons. This will result in nd^5 configuration with n being equal to 3, 4, 5, etc.
03

Identify the metal ions of interest

After removing three electrons to result in the required nd^5 configuration, we can identify which metal ions have the desired electron configuration. A few examples are provided below: 1. For n = 3, \(3d^5\), Mn^3+ ion (Manganese): In a neutral Mn (Manganese) atom, the electron configuration is [Ar] \(4s^23d^5\). Upon losing three electrons, Mn becomes Mn^3+ with an electron configuration of [Ar] \(3d^5\). 2. For n = 4, \(4d^5\), Tc^3+ ion (Technetium): In a neutral Tc (Technetium) atom, the electron configuration is [Kr] \(5s^24d^5\). Upon losing three electrons, Tc becomes Tc^3+ with an electron configuration of [Kr] \(4d^5\). 3. For n = 5, \(5d^5\), Re^3+ ion (Rhenium): In a neutral Re (Rhenium) atom, the electron configuration is [Xe] \(6s^25d^5\). Upon losing three electrons, Re becomes Re^3+ with an electron configuration of [Xe] \(5d^5\). These are examples of transition metal ions with +3 charge and electron configurations of the form nd^5 where n is equal to 3, 4, and 5 respectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Understanding electron configuration is crucial in chemistry because it explains how electrons are distributed in an atom's orbitals. Each element has a unique electron configuration, which follows the arrangement of electrons in shells and subshells based on increasing energy levels. Electrons fill subshells in a specific order, starting from the lowest energy level:
  • s (2 electrons)
  • p (6 electrons)
  • d (10 electrons)
  • f (14 electrons)
In transition metals, electrons fill the d subshells last after s subshells, despite s being lower in energy. This sometimes leads to unique electron configurations compared to other elements. When forming ions, electrons are typically removed from the outermost subshell first. For transition metals, this often means removing electrons from the s orbitals before the d orbitals, which is vital to understand when dealing with charged ions like the +3 transition metal ions discussed here.
Manganese Ion (Mn^3+)
Manganese (Mn) is a transition metal known for its various oxidation states, with Mn^3+ being one of them. To comprehend the electron configuration of Mn^3+, start with neutral manganese. It has an electron configuration of [Ar] 4s^2 3d^5. In its +3 oxidation state, manganese loses three electrons. Observing the rule that electrons are first removed from the outermost shell, we remove two electrons from the 4s orbital and one from the 3d orbital, leaving Mn^3+ with an electron configuration of [Ar] 3d^5.

This configuration results in a half-filled d subshell, which is relatively stable due to its symmetric distribution of electrons. Understanding this stability helps explain why certain oxidation states are more prevalent in chemistry. Manganese ions often play critical roles in biological systems and are a key component in enzymes and other molecular structures.
Technetium Ion (Tc^3+)
Technetium (Tc) is a somewhat unique transition metal because all its isotopes are radioactive. Despite this, it still follows the expected electron configuration for transition metals. A neutral technetium atom has the configuration [Kr] 5s^2 4d^5.

When forming the Tc^3+ ion, three electrons are lost. Consistent with rules for electron removal, two electrons are removed from the 5s orbital and one from the 4d orbital. Thus, Tc^3+ has the electron configuration [Kr] 4d^5.

Like manganese, technetium in the +3 oxidation state results in a half-filled d subshell, which contributes to its relative stability. Understanding Tc's properties helps scientists in fields such as nuclear medicine, where it is used in diagnostic imaging. Knowing the electron configuration allows chemists to predict and explain these and other behaviors in chemical reactions and formations.
Rhenium Ion (Re^3+)
Rhenium (Re) represents another fascinating example in the study of transition metals. Its electron configuration in the neutral state is [Xe] 6s^2 5d^5. In forming a +3 charged ion, three electrons are removed to achieve its ionized state.

Electrons are first removed not from the d orbital, but from the s orbital due to their higher principal quantum number, 6s. Thus, the Re ion loses two electrons from the 6s orbital and one from the 5d orbital, resulting in Re^3+ with an electron configuration of [Xe] 5d^5.

This half-filled d subshell bestows Re^3+ ions with additional stability, akin to other ions with nd^5 configurations. In industrial applications, rhenium is admired for its high melting points and use in high-temperature superalloys. Its electron configuration helps ensure these properties by influencing its chemical stability and bonding patterns.

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Most popular questions from this chapter

Based on their positions in the periodic table, predict which atom of the following pairs will have the smaller first ionization energy: (a) \(\mathrm{Br}, \mathrm{Kr} ; \mathbf{( b )} \mathrm{C}, \mathrm{Ca} ;(\mathbf{c}) \mathrm{Li}, \mathrm{Rb} ;\); (d) \(\mathrm{Pb}, \mathrm{Si} ;\) (e) \(\mathrm{Al}, \mathrm{B}\).

Which will experience the greater effect nuclear charge, the electrons in the \(n=2\) shell in \(\mathrm{F}\) or the \(n=2\) shell in \(\mathrm{B}\) ? Which will be closer to the nucleus?

(a) Does metallic character increase, decrease, or remain unchanged as one goes from left to right across a row of the periodic table? (b) Does metallic character increase, decrease, or remain unchanged as one goes down a column of the periodic table? (c) Are the periodic trends in (a) and (b) the same as or different from those for first ionization energy?

Elements in group 17 in the periodic table are called the halogens; elements in group 16 are called the chalcogens. (a) What is the most common oxidation state of the chalcogens compared to the halogens? (b) For each of the following periodic properties, state whether the halogens or the chalcogens have larger values: atomic radii, ionic radii of the most common oxidation state, first ionization energy, second ionization energy.

Chlorine reacts with oxygen to form \(\mathrm{Cl}_{2} \mathrm{O}_{7} .\) (a) What is the name of this product (see Table 2.6)? (b) Write a balanced equation for the formation of \(\mathrm{Cl}_{2} \mathrm{O}_{7}(l)\) from the elements. (c) Would you expect \(\mathrm{Cl}_{2} \mathrm{O}_{7}\) to be more reactive toward \(\mathrm{H}^{+}(a q)\) or \(\mathrm{OH}^{-}(a q) ?(\mathbf{d})\) If the oxygen in \(\mathrm{Cl}_{2} \mathrm{O}_{7}\) is considered to have the -2 oxidation state, what is the oxidation state of the \(\mathrm{Cl}\) ? What is the electron configuration of \(\mathrm{Cl}\) in this oxidation state?

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