Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Based on their positions in the periodic table, predict which atom of the following pairs will have the smaller first ionization energy: (a) \(\mathrm{Br}, \mathrm{Kr} ; \mathbf{( b )} \mathrm{C}, \mathrm{Ca} ;(\mathbf{c}) \mathrm{Li}, \mathrm{Rb} ;\); (d) \(\mathrm{Pb}, \mathrm{Si} ;\) (e) \(\mathrm{Al}, \mathrm{B}\).

Short Answer

Expert verified
The elements with smaller first ionization energies in each pair are: (a) Br, (b) Ca, (c) Rb, (d) Pb, and (e) Al.

Step by step solution

01

(a) Comparing Br and Kr

Br (Bromine) is in Group 17 (7A) and Period 4, while Kr (Krypton) is in Group 18 (8A) and also Period 4. Since they are in the same period and ionization energy generally increases from left to right within a period, Br will have the smaller first ionization energy compared to Kr.
02

(b) Comparing C and Ca

C (Carbon) is in Group 14 (4A) and Period 2, while Ca (Calcium) is in Group 2 (2A) and Period 4. The ionization energy decreases from top to bottom within a group, so Ca (being lower in the periodic table) will have the smaller first ionization energy compared to C.
03

(c) Comparing Li and Rb

Li (Lithium) is in Group 1 (1A) and Period 2, while Rb (Rubidium) is in Group 1 (1A) and Period 5. Since they are in the same group, we will apply the trend that ionization energy decreases from top to bottom and determine that Rb will have the smaller first ionization energy compared to Li.
04

(d) Comparing Pb and Si

Pb (Lead) is in Group 14 (4A) and Period 6, while Si (Silicon) is in Group 14 (4A) and Period 3. As they are in the same group, ionization energy decreases from top to bottom within a group, so Pb will have the smaller first ionization energy compared to Si.
05

(e) Comparing Al and B

Al (Aluminum) is in Group 13 (3A) and Period 3, while B (Boron) is in Group 13 (3A) and Period 2. Since they are in the same group, we will apply the trend that ionization energy decreases from top to bottom within a group, thereby concluding that Al will have the smaller first ionization energy compared to B.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Periodic Table
The periodic table is a powerful tool in chemistry, organizing all known elements in a tabular format that reveals various trends and relationships. Elements are arranged by increasing atomic number, meaning each element has one more proton in its nucleus than the previous element. This organization allows for the prediction of chemical properties and reactivity patterns.

Key elements of the periodic table include:
  • Groups: These are the vertical columns that run from top to bottom. Elements in the same group have similar electron configurations and chemical properties.
  • Periods: These are the horizontal rows. As you move across a period, properties of elements change predictably.
Understanding the layout of the periodic table and the group and period information can help us predict various properties of elements such as ionization energy.
Ionization Energy Trends
Ionization energy is the amount of energy required to remove an electron from an atom in its gaseous state. Understanding ionization energy trends helps in predicting the reactivity of elements. The general trend is that ionization energy increases across a period from left to right and decreases down a group.

Several factors influence these trends:
  • Nuclear Charge: As the positive charge of the nucleus (from protons) increases, it holds electrons more tightly, requiring more energy for removal.
  • Electron Shielding: Inner electrons can block the attraction between the nucleus and the outermost electrons, which can lower ionization energy.
  • Atomic Radius: Larger atoms tend to have lower ionization energies because the valence electrons are farther from the nucleus and are less strongly attracted.
These factors work together to create the observable trends in ionization energy across the periodic table.
Group and Period Trends
Trends within groups and periods in the periodic table critically affect elements' chemical and physical properties, including ionization energy. In a group, as you go from top to bottom, the principal quantum number increases, meaning that there are more electron shells, and hence, the atomic size increases.

When discussing period trends:
  • Within Groups: Ionization energy usually decreases down a group because the increase in electron shells outweighs other factors, causing the electrons to be further from the nucleus.
  • Across Periods: Ionization energy tends to increase across a period since electrons are added to the same energy level, and the increased nuclear charge increases the attraction between the nucleus and electron.
Having a firm grasp on these trends allows for better predictions about the properties and behaviors of different elements in various chemical contexts.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free