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Does the hydrogen atom "expand" or "contract" when an electron is excited from the \(n=1\) state to the \(n=3\) state?

Short Answer

Expert verified
When an electron in a hydrogen atom is excited from the \(n=1\) state to the \(n=3\) state, the average distance of the electron from the nucleus increases, as calculated using the formula \(r_n = a_0n^2\). Since the average distance is greater in the \(n=3\) state compared to the \(n=1\) state, the hydrogen atom "expands" during this transition.

Step by step solution

01

Recall the Bohr Model for Hydrogen Atom

The Bohr model is a simplified model of a hydrogen atom where the electron orbits around the nucleus in specific energy levels. Each energy level is represented by an integer number called the principal quantum number, denoted by n.
02

Understand the meaning of "expanding" and "contracting"

As an electron moves from a lower energy level to a higher energy level, its average distance from the nucleus, also known as the radius of the orbital, tends to increase. If the average distance (radius) increases, then the hydrogen atom is said to "expand." Conversely, if the average distance (radius) decreases, the hydrogen atom is said to "contract."
03

Calculate the average distance of the electron in energy levels n=1 and n=3

The average distance of the electron in the nth orbital can be calculated using the formula: \(r_n = a_0n^2\), where \(a_0\) is the Bohr radius and roughly equals \(5.29 \times 10^{-11}\) meters. For n=1: \(r_1 = a_0(1)^2 = a_0\) For n=3: \(r_3 = a_0(3)^2 = 9a_0\) Now we need to compare these distances.
04

Compare the average distances to determine if the hydrogen atom expands or contracts

Since \(r_3 = 9a_0\) is larger than \(r_1 = a_0\), it means that the electron is on average farther from the nucleus when it is in the n=3 state than when it is in the n=1 state. Therefore, the hydrogen atom "expands" when an electron is excited from the n=1 state to the n=3 state.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Levels
In the Bohr model of the hydrogen atom, energy levels are depicted as discrete circular orbits around the nucleus where the electron can reside. Each energy level corresponds to a specific amount of energy that the electron has. Think of these levels like rungs on a ladder – the electron can "jump" from one rung to another, but it cannot reside in between these rungs.

The lower the energy level, the less energy is required for the electron to remain there. As the electron moves to higher energy levels, it absorbs energy corresponding to the energy difference between the levels.
  • The lowest energy level (closest to the nucleus) is called the ground state and is designated by the principal quantum number, \( n = 1 \).
  • Higher energy levels (further from the nucleus) are termed excited states, such as \( n = 2 \), \( n = 3 \), and so on.
When an electron transitions to a higher energy level, it occupies a position further from the nucleus, resulting in an increased orbital radius and, thus, a larger "size" of the atom as seen in the hydrogen atom expansion from \( n=1 \) to \( n=3 \).
Principal Quantum Number
The principal quantum number, symbolized as \( n \), is a fundamental concept in quantum mechanics. It defines the main energy level that an electron occupies in an atom. The principal quantum number is always a positive integer (\( n = 1, 2, 3, \ldots \)), indicating the relative distance of an electron's orbit from the nucleus.

Each principal quantum number correlates with a specific energy level:
  • \( n = 1 \) defines the first energy level or ground state.
  • \( n = 2 \), \( n = 3 \), etc., correspond to higher, excited states.
  • The larger the \( n \), the higher the energy and the farther the electron is from the nucleus.
For instance, when an electron "jumps" from \( n = 1 \) to \( n = 3 \), it moves to a significantly higher energy level, increasing the atomic orbital's average distance from the nucleus. This expansion from the core is due to the increased energy and thus increased principal quantum number.
Hydrogen Atom Expansion
The concept of hydrogen atom expansion comes into play when discussing electrons transitioning between different energy states. In the Bohr model, when an electron absorbs energy, it transitions to a higher energy level, characterized by a larger principal quantum number. This transition leads to an increase in the average orbital radius of the electron.

Mathematically, the average distance from the nucleus, or the radius \( r_n \), can be described by the formula:
  • \( r_n = a_0n^2 \)
Where \( a_0 \) is the Bohr radius (approximately \( 5.29 \times 10^{-11} \) meters). Hence, as the principal quantum number \( n \) increases, \( r_n \) grows, indicating that the atom "expands."

For example, the transition of an electron in hydrogen from \( n=1 \) to \( n=3 \) results in the radius growing from \( a_0 \) to \( 9a_0 \), a clear expansion of the hydrogen atom. This larger radius means the electron is now farther from the nucleus, effectively expanding the size of the atom in its excited state.

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Most popular questions from this chapter

Calculate the uncertainty in the position of (a) an electron moving at a speed of \((3.00 \pm 0.01) \times 10^{5} \mathrm{~m} / \mathrm{s},(\mathbf{b})\) a neutron moving at this same speed. (The masses of an electron and a neutron are given in the table of fundamental constants in the inside cover of the text.) (c) Based on your answers to parts (a) and (b), which can we know with greater precision, the position of the electron or of the neutron?

The first 25 years of the twentieth century were momentous for the rapid pace of change in scientists' understanding of the nature of matter. (a) How did Rutherford's experiments on the scattering of \(\alpha\) particles by a gold foil set the stage for Bohr's theory of the hydrogen atom? (b) In what ways is de Broglie's hypothesis, as it applies to electrons, consistent with J. J. Thomson's conclusion that the electron has mass? In what sense is it consistent with proposals preceding Thomson's work that the cathode rays are a wave phenomenon?

Molybdenum metal must absorb radiation with an energy higher than \(7.22 \times 10^{-19} \mathrm{~J}\) ( "energy threshold") before it can eject an electron from its surface via the photoelectric effect. (a) What is the frequency threshold for emission of electrons? (b) What wavelength of radiation will provide a photon of this energy? (c) If molybdenum is irradiated with light of wavelength of \(240 \mathrm{nm}\), what is the maximum possible velocity of the emitted electrons?

The series of emission lines of the hydrogen atom for which \(n_{f}=4\) is called the Brackett series. (a) Determine the region of the electromagnetic spectrum in which the lines of the Brackett series are observed. (b) Calculate the wavelengths of the first three lines in the Brackett series - those for which \(n_{i}=5,6,\) and 7.

If a sample of calcium chloride is introduced into a nonluminous flame, the color of the flame turns to orange ("flame test"). The light is emitted because calcium atoms become excited; their return to the ground state results in light emission. (a) The wavelength of this emitted light is \(422.7 \mathrm{nm} .\) Calculate its frequency. (b) What is the energy of \(1.00 \mathrm{~mol}\) of these photons (a mole of photons is called an Einstein)? (c) Calculate the energy gap between the excited and ground states for the calcium atom.

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