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When an 18.6-g sample of solid potassium hydroxide dissolves in \(200.0 \mathrm{~g}\) of water in a coffee-cup calorimeter (Figure 5.18), the temperature rises from 23.7 to \(44.5^{\circ} \mathrm{C}\). (a) Calculate the quantity of heat (in kJ) released in the reaction. (b) Using your result from part (a), calculate \(\Delta H\) (in kJ/mol KOH) for the solution process. Assume that the specific heat of the solution is the same as that of pure water.

Short Answer

Expert verified
The quantity of heat released in the reaction is 17.36864 kJ, and the enthalpy change (ΔH) for the solvation process of potassium hydroxide is 52.42 kJ/mol.

Step by step solution

01

Calculate the change in temperature (ΔT)

ΔT = Final temperature - Initial temperature ΔT = 44.5°C - 23.7°C ΔT = 20.8°C
02

Find the heat released (q) using the formula q = mcΔT

Here, we are given the mass of water (m) as 200.0 g. The specific heat capacity (c) of water is 4.184 J/g°C. q = (200.0 g)*(4.184 J/g°C)*(20.8°C) q = 17368.64 J Since we need the heat released in kilojoules (kJ), let's convert it from J to kJ: [q(kJ) = q(J) / 1000] q = 17.36864 kJ
03

Calculate moles of KOH dissolved

Now, we’ll find out how many moles of KOH were present in the 18.6-g sample: Molar mass of KOH = 39.1 (K) + 15.999 (O) + 1.007 (H) = 56.106 g/mol [Moles of KOH = mass / molar mass] moles of KOH = 18.6 g / 56.106 g/mol = 0.3314 mol
04

Calculate ΔH (enthalpy change) in kJ/mol KOH

[ΔH = Heat released (q) / moles of KOH] ΔH = 17.36864 kJ / 0.3314 mol ΔH = 52.42 kJ/mol Therefore, the enthalpy change for the solvation process of potassium hydroxide is 52.42 kJ/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calorimetry
Calorimetry is a technique used to measure the amount of heat absorbed or released during a chemical reaction. It is commonly conducted using a device called a calorimeter. The core principle behind calorimetry is the conservation of energy: the heat lost or gained by the system under investigation is equal to the heat gained or lost by the surroundings. This makes calorimetry a useful method for determining the enthalpy change (ΔH) of a reaction.
In a simple calorimeter setup, like the coffee-cup calorimeter, heat exchange with the environment is minimized. The chemical process takes place in a container (often a styrofoam cup), and the resulting temperature change is recorded. This temperature change, along with the known mass and specific heat capacity of the solution or reaction medium, allows us to calculate the amount of heat involved in the process.
Using the formula:
  • q = mcΔT, where
  • q = heat absorbed or released (in Joules),
  • m = mass of the solution (in grams),
  • c = specific heat capacity (in J/g°C), and
  • ΔT = change in temperature (in °C).
Employing this technique requires careful attention to calibration and measurements to ensure accuracy of the results.
Potassium Hydroxide
Potassium hydroxide (KOH) is a strong base commonly used in various industrial and laboratory applications. When dissolved in water, it dissociates completely into potassium ( K^+ ) and hydroxide ( OH^− ) ions, which is indicative of its strong alkaline nature. This complete dissociation is significant in calorimetry experiments, as it typically results in significant heat exchange with the environment.
Known for its high reactivity, KOH solutions are often used in chemical synthesis, pH regulation, and as a cleaning agent. In the context of calorimetry and enthalpy change calculation, the solvation of KOH is an exothermic process, meaning it releases heat to the surroundings. This release of heat is evident from the increase in temperature observed in the surrounding water solution when KOH dissolves.
The molar mass of potassium hydroxide is a crucial factor in such experiments, helping to convert the measured heat into an enthalpy change per mole, reflecting the energy changes involved in dissolving a known quantity of the solute.
Specific Heat Capacity
Specific heat capacity, often denoted as 'c', is a property of a substance that indicates the amount of heat required to raise the temperature of one gram of the substance by one degree Celsius. Water, with a high specific heat capacity of 4.184 J/g°C, is commonly used in calorimetry because it can absorb substantial amounts of heat without a large change in temperature.
Its ability to hold heat makes it ideal for use in calorimetric calculations, where understanding how much energy is involved in chemical reactions is essential. When using specific heat capacity to calculate heat in a calorimetry experiment, the data rely on the assumption that the solution behaves similarly to water, even if other substances are involved.
In the context of the given solution, specific heat capacity allows us to calculate the heat change when potassium hydroxide dissolves. By knowing the specific heat, the mass of the water, and the change in temperature, we can determine the amount of heat exchanged with precision and proceed to calculate further energy changes, like the enthalpy change, per mole of the substance involved.

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Most popular questions from this chapter

Indicate which of the following is independent of the path by which a change occurs: (a) the change in potential energy when a book is transferred from table to shelf, (b) the heat evolved when a cube of sugar is oxidized to \(\mathrm{CO}_{2}(g)\) and \(\mathrm{H}_{2} \mathrm{O}(g),(\mathbf{c})\) the work accomplished in burning a gallon of gasoline.

A coffee-cup calorimeter of the type shown in Figure 5.18 contains \(150.0 \mathrm{~g}\) of water at \(25.2^{\circ} \mathrm{C}\). A \(200-\mathrm{g}\) block of silver metal is heated to \(100.5^{\circ} \mathrm{C}\) by putting it in a beaker of boiling water. The specific heat of \(\mathrm{Ag}(s)\) is \(0.233 \mathrm{~J} /(\mathrm{g} \cdot \mathrm{K})\). The \(\mathrm{Ag}\) is added to the calorimeter, and after some time the contents of the cup reach a constant temperature of \(30.2^{\circ} \mathrm{C} .(\mathbf{a})\) Determine the amount of heat, in J, lost by the silver block. (b) Determine the amount of heat gained by the water. The specific heat of water is \(4.184 \mathrm{~J} /(\mathrm{g} \cdot \mathrm{K}) .(\mathbf{c})\) The difference between your answers for (a) and (b) is due to heat loss through the Styrofoam \(^{\circ}\) cups and the heat necessary to raise the temperature of the inner wall of the apparatus. The heat capacity of the calorimeter is the amount of heat necessary to raise the temperature of the apparatus (the cups and the stopper) by \(1 \mathrm{~K} .\) Calculate the heat capacity of the calorimeter in \(\mathrm{J} / \mathrm{K}\). (d) What would be the final temperature of the system if all the heat lost by the silver block were absorbed by the water in the calorimeter?

Two solid objects, A and B, are placed in boiling water and allowed to come to the temperature of the water. Each is then lifted out and placed in separate beakers containing \(1000 \mathrm{~g}\) of water at \(10.0^{\circ} \mathrm{C}\). Object A increases the water temperature by \(3.50^{\circ} \mathrm{C} ; \mathrm{B}\) increases the water temperature by \(2.60{ }^{\circ} \mathrm{C}\). (a) Which object has the larger heat capacity? (b) What can you say about the specific heats of \(\mathrm{A}\) and \(\mathrm{B}\) ?

(a) What is the electrostatic potential energy (in joules) between an electron and a proton that are separated by \(230 \mathrm{pm}\) ? (b) What is the change in potential energy if the distance separating the electron and proton is increased to \(1.0 \mathrm{nm}\) ? (c) Does the potential energy of the two particles increase or decrease when the distance is increased to \(1.0 \mathrm{nm}\) ?

(a) Under what condition will the enthalpy change of a process equal the amount of heat transferred into or out of the system? (b) During a constant-pressure process, the system releases heat to the surroundings. Does the enthalpy of the system increase or decrease during the process? (c) In a constant-pressure process, \(\Delta H=0\). What can you conclude about \(\Delta E, q,\) and \(w ?\)

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