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Which of the following ions will always be a spectator ion in a precipitation reaction? (a) \(\mathrm{Cl}^{-},(\mathbf{b}) \mathrm{NO}_{3}^{-}\), (d) \(\mathrm{S}^{2-}\), (c) \(\mathrm{NH}_{4}^{+}\) (e) \(\mathrm{SO}_{4}^{2-} .[\) Section 4.2\(]\)

Short Answer

Expert verified
The nitrate ion (\(\mathrm{NO}_{3}^{-}\)) in option (b) will always be a spectator ion in a precipitation reaction, as it is not known to form any insoluble compounds.

Step by step solution

01

Identify common soluble ions

In general, ions from Group 1 elements (like Na+ and K+), and the ammonium ion (NH4+) are soluble in water. Additionally, the nitrate ion (NO3-) is also soluble. Knowing this, we can narrow down our choices to options (b) and (c).
02

Check for known insoluble compounds

Let's check each remaining ion to see if they form any well-known insoluble compounds: - Option (b): Nitrate ion (\(\mathrm{NO}_{3}^{-}\)): Nitrates typically produce soluble compounds when combined with other ions. - Option (c): Ammonium ion (\(\mathrm{NH}_{4}^{+}\)): Ammonium also typically produces soluble compounds when combined with other ions. As both ions under consideration tend to form soluble compounds when reacting with other ions, neither of them is likely to participate in a precipitation reaction.
03

Select the spectator ion

While both options (b) and (c) are known to have high solubility in water, the question asks which ion will *always* be a spectator ion. Based on our analysis, we can conclude that the nitrate ion (\(\mathrm{NO}_{3}^{-}\)) in option (b) is the ion that will always act as a spectator ion in a precipitation reaction, as it is not known to form any insoluble compounds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility Rules
Solubility rules are guidelines used to predict whether a compound will dissolve in water. These rules are crucial in chemistry as they help determine which substances interact in a solution. The key solubility rule to remember is:
  • Most salts containing alkali metal ions and the ammonium ion (\( ext{NH}_4^+\)) are soluble.
  • Nitrates (\( ext{NO}_3^-\)), acetates (\( ext{CH}_3 ext{COO}^-\)), and most perchlorates (\( ext{ClO}_4^-\)) are soluble.
  • Halides such as chlorides, bromides, and iodides are generally soluble, but there are exceptions.
Exceptions occur, especially with compounds containing certain heavy metal ions, so knowing the specific rules can help predict outcomes in various chemical contexts.
This knowledge is especially useful for determining spectator ions in precipitation reactions.
Precipitation Reactions
Precipitation reactions occur when two soluble salts in solution react to form one or more insoluble products, known as precipitates. This type of chemical reaction is fundamental in understanding many natural and industrial processes.
When two aqueous solutions are mixed, the potential formation of a precipitate depends on the interactions of their ions. A useful tool to predict precipitation reactions is the solubility rules.
In a precipitation reaction, ions that do not participate in the formation of the precipitate are called spectator ions. These ions remain dissolved in the aqueous phase and do not change during the course of the reaction.
Spectator ions are often critical in determining whether a reaction occurs visibly by a cloudiness or solid appearing in the solution.
Nitrate Ions
Nitrate ions (\( ext{NO}_3^-\)) are some of the most commonly encountered ions in the field of chemistry, particularly in aqueous solutions. Nitrate ions are always soluble, which makes them consistent spectator ions in many reactions.
Due to their solubility, they do not form precipitates under typical conditions. This is why, in precipitation reactions, nitrate ions usually do not participate in the formation of insoluble products.
Since nitrate ions do not change during the course of a precipitation reaction, they help provide balance to the overall reaction in terms of charge and mass. Thus, they are a prime example of spectator ions, making them pivotal in chemical equations and experimentation.
Chemistry Education
Chemistry education often focuses on hands-on learning and critical thinking, essential for grasping complex concepts. Topics like solubility, precipitation reactions, and ionic interactions are foundational in the chemistry curriculum.
Interactive experiments allow students to observe real-life applications of solubility and reactions, enabling them to visualize how ions behave in solutions.
Additionally, problem-solving exercises, such as predicting spectator ions, hone critical thinking skills. Guidance and experience in identifying recurring patterns and applying rules are crucial.
Mastery of these subjects enables one to understand broader chemical processes, fostering a deeper appreciation for the subject and its applications in real-world challenges.

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Most popular questions from this chapter

Ignoring protolysis reactions, indicate the concentration of each ion or molecule present in the following solu- tions: (a) \(0.35 \mathrm{MK}_{3} \mathrm{PO}_{4},\) (b) \(5 \times 10^{-4} \mathrm{MCuCl}_{2},(\mathbf{c}) 0.0184\) \(\mathrm{MCH}_{3} \mathrm{CH}_{2} \mathrm{OH}(\mathbf{d})\) a mixture of \(35.0 \mathrm{~mL}\) of \(0.010 \mathrm{MNa}_{2} \mathrm{CO}_{3}\) and \(50.0 \mathrm{~mL}\) of \(0.200 \mathrm{MK}_{2} \mathrm{SO}_{4}\). Assume the volumes are additive.

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