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We have learned in this chapter that many ionic solids dissolve in water as strong electrolytes; that is, as separated ions in solution. Which statement is most correct about this process? (a) Water is a strong acid and therefore is good at dissolving ionic solids. (b) Water is good at solvating ions because the hydrogen and oxygen atoms in water molecules bear partial charges. (c) The hydrogen and oxygen bonds of water are easily broken by ionic solids.

Short Answer

Expert verified
The most correct statement about the process of many ionic solids dissolving in water as strong electrolytes is (b) Water is good at solvating ions because the hydrogen and oxygen atoms in water molecules bear partial charges. This allows water molecules to surround and stabilize dissolved ions, forming hydration shells around them. This process is known as solvation, and it helps ionic solids dissolve in water.

Step by step solution

01

(Evaluation of Statement A)

(Statement A claims that water is a strong acid and therefore is good at dissolving ionic solids. This statement is not entirely correct. While water can act as both an acid and a base, it is considered a weak acid or base and does not play the primary role in dissolving ionic compounds.)
02

(Evaluation of Statement B)

(Statement B claims that water is good at solvating ions because the hydrogen and oxygen atoms in water molecules bear partial charges. This statement is correct. Water is a polar molecule, meaning it has a partial positive charge on hydrogen atoms and a partial negative charge on the oxygen atom. These partial charges allow water molecules to surround and stabilize dissolved ions, forming hydration shells around them. This process is known as solvation, and it helps ionic solids dissolve in water.)
03

(Evaluation of Statement C)

(Statement C claims that the hydrogen and oxygen bonds of water are easily broken by ionic solids. This statement is not entirely accurate. When ionic compounds dissolve in water, the water molecules do not break their own internal hydrogen and oxygen bonds. Instead, they use their partial positive and negative charges to stabilize the separate ions, allowing the ionic lattice to dissolve.)
04

(Conclusion)

(Based on the analysis of the three statements, option B is the most correct statement about the process of many ionic solids dissolving in water as strong electrolytes. Water's ability to solvate ions is due to the partial charges on hydrogen and oxygen atoms in water molecules, not because it is a strong acid or because its internal bonds are easily broken by ionic compounds.)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Strong Electrolytes
When we talk about strong electrolytes, we refer to substances that completely dissociate into ions when dissolved in water. This means all the molecules of the ionic compound separate into their respective positive and negative ions.

Because of this complete dissociation, solutions containing strong electrolytes conduct electricity very well. Examples of strong electrolytes include common salts like sodium chloride (NaCl), potassium bromide (KBr), and strong acids like hydrochloric acid (HCl). These substances are vital in various applications, from biological processes in the human body to chemical manufacturing in industries.

Strong electrolytes are against weak electrolytes, which only partially dissociate in solution, leading to poorer electrical conductivity. Understanding the nature of an electrolyte is crucial in predicting how it behaves in a solution. This knowledge helps in fields such as chemistry, medicine, and environmental science.
Polar Molecules
Polar molecules are molecules that have a net dipole moment due to the presence of polar bonds. These polar bonds result from differences in electronegativity between the atoms involved. In polar molecules, one end becomes slightly negatively charged, while the other takes on a positive charge.

Water is a classic example of a polar molecule. It has a bent shape with oxygen at the center and hydrogen atoms on either side. Oxygen is more electronegative than hydrogen, leading to a partial negative charge on the oxygen atom and a partial positive charge on the hydrogen atoms. This polarity is why water is so effective in dissolving many substances.

When polar molecules interact with ionic compounds, they help stabilize ions in the solution by aligning their charges with those of the ions. This interaction is crucial in processes such as solvation, where the polar nature of water molecules plays a key role in dissolving ionic solids.
Solvation Process
The solvation process is a fundamental concept in chemistry that describes how solvent molecules, like water, surround and interact with solute particles. This process is essential for dissolving substances and is driven by the polarity of the solvent molecules.

In the solvation process, water molecules use their partial charges to attract and stabilize ions from the dissociating ionic solid. This attraction forms a 'hydration shell' around each ion. For example, in the dissolution of salt (NaCl), water molecules surround the sodium ions (\[\text{Na}^+\]) and chloride ions (\[\text{Cl}^-\]), stabilizing them in solution.

This stabilization lowers the energy of the system, making dissolution favorable. The solvation process is crucial not only for simple ionic compounds but also in more complex biological and chemical systems. It explains how substances like sugar can dissolve in water and how reactions occur in aqueous solutions.

Understanding the solvation process helps in grasping how solutions form and why certain substances are soluble in particular solvents, providing critical insights for fields ranging from pharmacology to environmental science.

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Most popular questions from this chapter

(a) By titration, \(15.0 \mathrm{~mL}\) of \(0.1008 \mathrm{Msodium}\) hydroxide is needed to neutralizea \(0.2053-\mathrm{g}\) sample of a weak acid. What is the molar mass of the acid if it is monoprotic? (b) An elemental analysis of the acid indicates that it is composed of \(5.899 \mathrm{H}, 70.6 \% \mathrm{C},\) and \(23.5 \% \mathrm{O}\) by mass. What is its molecular formula?

Separate samples of a solution of an unknown salt are treated with dilute solutions of \(\mathrm{HBr}, \mathrm{H}_{2} \mathrm{SO}_{4},\) and \(\mathrm{NaOH}\). A precipitate forms in all three cases. Which of the following cations could be present in the unknown salt solution: \(\mathrm{K}^{+}, \mathrm{Pb}^{2+}, \mathrm{Ba}^{2+} ?\)

Neurotransmitters are molecules that are released by nerve cells to other cells in our bodies, and are needed for muscle motion, thinking, feeling, and memory. Dopamine is a common neurotransmitter in the human brain. (a) Predict what kind of reaction dopamine is most likely to undergo in water: redox, acid-base, precipitation, or metathesis? Explain your reasoning. (b) Patients with Parkinson's disease suffer from a shortage of dopamine and may need to take it to reduce symptoms. An IV (intravenous fluid) bag is filled with a solution that contains \(400.0 \mathrm{mg}\) dopamine per \(250.0 \mathrm{~mL}\) of solution. What is the concentration of dopamine in the IV bag in units of molarity? (c) Experiments with rats show that if rats are dosed with \(3.0 \mathrm{mg} / \mathrm{kg}\) of cocaine (that is, \(3.0 \mathrm{mg}\) cocaine per \(\mathrm{kg}\) of animal mass), the concentration of dopamine in their brains increases by \(0.75 \mu M\) after 60 seconds. Calculate how many molecules of dopamine would be produced in a rat (average brain volume \(5.00 \mathrm{~mm}^{3}\) ) after 60 seconds of a \(3.0 \mathrm{mg} / \mathrm{kg}\) dose of cocaine.

As \(\mathrm{K}_{2} \mathrm{O}\) dissolves in water, the oxide ion reacts with water molecules to form hydroxide ions. (a) Write the molecular and net ionic equations for this reaction. (b) Based on the definitions of acid and base, what ion is the base in this reaction? (c) What is the acid in the reaction? (d) What is the spectator ion in the reaction?

(a) You have a stock solution of \(14.8 \mathrm{M} \mathrm{NH}_{3}\). How many milliliters of this solution should you dilute to make \(1000.0 \mathrm{~mL}\) of \(0.250 \mathrm{MNH}_{3} ?\) (b) If you take a \(10.0-\mathrm{mL}\) portion of the stock solution and dilute it to a total volume of \(0.500 \mathrm{~L},\) what will be the concentration of the final solution?

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