Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Define the terms theoretical yield, actual yield, and percent yield. (b) Why is the actual yield in a reaction almost always less than the theoretical yield? (c) Can a reaction ever have \(110 \%\) actual yield?

Short Answer

Expert verified
Theoretical yield is the maximum amount of product that can be formed based on stoichiometry, while actual yield is the experimentally obtained product amount, and percent yield is the efficiency of a reaction calculated as \(\frac{Actual Yield}{Theoretical Yield} \times 100\%\). Actual yield is usually less than theoretical yield due to factors like incomplete reactions, side reactions, and impurities. A reaction cannot have a \(110\%\) actual yield, as it would contradict the principles of chemical reactions; any excess product would likely be due to experimental errors.

Step by step solution

01

1. Define Theoretical Yield

Theoretical yield refers to the maximum amount of product that can be formed from a given amount of limiting reactant, calculated based on stoichiometry and using balanced chemical equations.
02

2. Define Actual Yield

Actual yield is the actual amount of product that is obtained experimentally from a reaction, which is generally measured in the laboratory. It can be influenced by various factors, including impurities in reactants, side reactions, environmental conditions, and loss of material during the procedure.
03

3. Define Percent Yield

Percent yield represents the efficiency of a reaction, which is calculated by dividing the actual yield by the theoretical yield and then multiplying by 100. It is expressed as a percentage and illustrates the extent to which the reaction has produced the desired product. \(Percent Yield = \frac{Actual Yield}{Theoretical Yield} \times 100\%\)
04

4. Reason for Actual Yield being less than Theoretical Yield

The actual yield in a reaction is almost always less than the theoretical yield for a variety of reasons. Some of the factors contributing to lower actual yields include incomplete reactions, side reactions that consume reactants, unstable products that may decompose, impurities in the reactants, and loss of material during the separation and purification process.
05

5. Possibility of having 110% Actual Yield

It is not possible for a reaction to have a \(110\%\) actual yield because the maximum yield that can be achieved is \(100\%\). A percent yield greater than \(100\%\) would imply that more product has been formed than what is stoichiometrically possible, which contradicts the principles of chemical reactions. The presence of excess product in such cases can be attributed to experimental errors, such as inaccurate measurements or contamination of the product with other substances.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Actual Yield
The actual yield is the amount of product that is actually produced when a chemical reaction is carried out in a laboratory. Unlike the theoretical yield, which is a calculated prediction, the actual yield is determined through experimental trials. This means measuring the amount of product formed after the reaction is complete.

There are several factors that can affect the actual yield in a laboratory setting:
  • Impurities: Reactants may contain impurities, leading to less product being formed than expected.
  • Side Reactions: Other reactions can occur simultaneously, consuming reactants and forming unintended products.
  • Environmental Conditions: Changes in temperature, pressure, or humidity can alter reaction rates and yields.
  • Loss of Material: During processes like filtration or transfer, some material might be lost.
Actual yields are usually less than theoretical yields due to these and other factors.
Percent Yield
Percent yield is a measure of the efficiency of a chemical reaction. It compares the actual yield to the theoretical yield and expresses this as a percentage. This metric helps scientists understand how successful their experiment was in producing the desired amount of product.

To calculate percent yield, you use the following formula:\[Percent\ Yield = \frac{Actual\ Yield}{Theoretical\ Yield} \times 100\%\]Here are a few points to consider when using this calculation:
  • Understanding Efficiency: A percent yield close to 100% indicates a very efficient reaction where a significant portion of the reactants was converted to the desired product.
  • Recognizing Limitations: Often, the percent yield is less than 100% because of side reactions or incomplete reactions.
  • Considering Errors: A percent yield greater than 100% suggests possible measurement errors or contamination in the collected product.
Percent yield provides valuable insight into how practical and controlled a reaction is when carried out in a real-world setting.
Stoichiometry
Stoichiometry is the area of chemistry that involves calculating the quantities of reactants and products in chemical reactions. It relies on the balanced chemical equation for the reaction, which provides the relative coefficients of reactants and products. This information is crucial in predicting how much product can be made from given amounts of reactants, leading to what is known as the theoretical yield.

In stoichiometric calculations, several concepts are essential:
  • Balanced Equations: Ensure the chemical equation is balanced to maintain mass conservation.
  • Mole Ratios: Use the coefficients from the balanced equation to determine the mole ratio between reactants and products.
  • Limiting Reactants: Identify which reactant will be completely consumed first, thus limiting the amount of product formed.
  • Theoretical Yield: Calculated based on the limiting reactant and represents the maximum possible product.
Stoichiometry is fundamental for understanding and predicting the outcomes of chemical reactions in a quantitative manner.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The complete combustion of octane, \(\mathrm{C}_{8} \mathrm{H}_{18}\), produces \(5470 \mathrm{~kJ}\) of heat. Calculate how many grams of octane is required to produce \(20,000 \mathrm{~kJ}\) of heat.

The source of oxygen that drives the internal combustion engine in an automobile is air. Air is a mixture of gases, principally \(\mathrm{N}_{2}(\sim 79 \%)\) and \(\mathrm{O}_{2}(\sim 20 \%) .\) In the cylinder of an automobile engine, nitrogen can react with oxygen to produce nitric oxide gas, NO. As NO is emitted from the tailpipe of the car, it can react with more oxygen to produce nitrogen dioxide gas. (a) Write balanced chemical equations for both reactions. (b) Both nitric oxide and nitrogen dioxide are pollutants that can lead to acid rain and global warming; collectively, they are called "NO \(_{x}\) " gases. In 2009 , the United States emitted an estimated 19 million tons of nitrogen dioxide into the atmosphere. How many grams of nitrogen dioxide is this? (c) The production of \(\mathrm{NO}_{x}\) gases is an unwanted side reaction of the main engine combustion process that turns octane, \(\mathrm{C}_{8} \mathrm{H}_{18},\) into \(\mathrm{CO}_{2}\) and water. If \(85 \%\) of the oxygen in an engine is used to combust octane and the remainder used to produce nitrogen dioxide, calculate how many grams of nitrogen dioxide would be produced during the combustion of \(500 \mathrm{~g}\) of octane.

Valproic acid, used to treat seizures and bipolar disorder, is composed of \(\mathrm{C}, \mathrm{H},\) and \(\mathrm{O} .\) A \(0.165-\mathrm{g}\) sample is combusted to produce \(0.166 \mathrm{~g}\) of water and \(0.403 \mathrm{~g}\) of carbon dioxide. What is the empirical formula for valproic acid? If the molar mass is \(144 \mathrm{~g} / \mathrm{mol}\), what is the molecular formula?

Balance the following equations: (a) \(\mathrm{CaS}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{Ca}(\mathrm{HS})_{2}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q)\) (b) \(\mathrm{NH}_{3}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{H}_{2} \mathrm{O}(g)\) (c) \(\mathrm{FeCl}_{3}(s)+\mathrm{Na}_{2} \mathrm{CO}_{3}(a q) \longrightarrow \mathrm{Fe}_{2}\left(\mathrm{CO}_{3}\right)_{3}(s)+\mathrm{NaCl}(a q)\) (d) \(\mathrm{FeS}_{2}(s)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+\mathrm{SO}_{2}(g)\)

Vanillin, the dominant flavoring in vanilla, contains C, H, and O. When \(1.05 \mathrm{~g}\) of this substance is completely combusted, \(2.43 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) and \(0.50 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O}\) are produced. What is the empirical formula of vanillin?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free